Kirat Is it possible to read a .py (python source code) as a file and display its class name, class methods and variables as output….? [closed] solved Is it possible to read a .py (python source code) as a file and display its class name, class methods and variables as output….? [closed]
What you might want to do is separate this out to a different function, your functions should have namespaces to architect your application. You can do this with a helper lib found here. You could try refactor code to something a little more structured like so: module-controller.js dali.util.namespace(‘myCompany.myApp.module’); myCompany.myApp.module.ClassName = function(maxGuesses) { this.maxGuesses = maxGuesses; … Read more
Your problem is the invalid JSON text. I’ve made an attempt to fix the json. Be aware, it’s ugly. Very ugly! So, having this as input: $a=”{“LinkedIn /*trimmed data to fit this format*/ Recruiting”}]}”; // you use $a = $_POST[‘LiRecData’]; What I did was try to reconstruct the JSON based on some (few) existing/correct elements: … Read more
as pointed out by @Delgan, it can be done directly via d1 = dict(keyval.split(“, “) for keyval in a_list) without the inner nesting 🙂 older approach which were not really correct :- d = [a.split(‘,’) for a in a_list] d1 = {key: val for key,val in d} or d1 = {key: val for key,val in … Read more
A simple example: echo {1..19..2}; echo {2..20..2}; echo {21..39..2}; echo {22..40..2} In a loop: #!/bin/bash i=1 while [ “$i” -lt 4000 ]; do for j in $i $((i+1)); do printf ‘%s ‘ $( seq $j 2 $((j+18)) ); echo done i=$((i+20)) done 2 solved bash print 10 odd numbers then 10 even numbers [closed]
why don’t you use split method String[] split = line1.split(“,”); System.out.println(split[1]); output part2 solved Substring of string is not working the way i want [closed]
df is the given data frame Desired output will come from this line cbind(df, var = apply(df[,4:16], 1, function(x) var(na.omit(x)))) 2 solved Add Variance Column in R data frame [closed]
According to java doc, Map.keyset() Returns a set view of the keys contained in this map. The set is backed by the map, so changes to the map are reflected in the set, and vice-versa. If the map is modified while an iteration over the set is in progress (except through the iterator’s own remove … Read more
In order to configure the environment for your subsequent ant command, you have to include the “. ./setantenv.sh” inside your second call. Both calls result in independent bash processes that dont share their specific environment. try this: su – USER -s /bin/bash -c ‘cd /PATH/ && . ./setantenv.sh && ant clean all’ 0 solved Linux, BASH … Read more
I have a feeling that you are requiring a formula to get number of iteration the nested loops will. for( i = 1; i <= n; i++ ) for ( j = i+1; j <= n; j++ ) for( k = j+1; k <= n; k++ ) For those loops, the number of iterations will … Read more
You declare an uninitialized variable of type int with identifier a: int a; The user provides a value to a. std::cin >> a; A copy is returned from the function: return a; Calls to the getValueFromUser() will create a temporary a, assign it to user input, and return it each time. solved How is “a” … Read more
I believe that what you want to do is this: public String[] getID(){ // Create an array of String of length staffNum String[] tempArray = new String[staffNum]; for(int x = 0; x < staffNum; x++){ // Affect the value Att[x] to each element of my array tempArray[x] = String.format(“Att[%d]”, x); } return tempArray; } 0 … Read more
I’m not sure what exactly you want to do, but you can try the following: arr = [“Japan”, “Egypt”, “Spain”, “Brazil”] arr.each { |a| Object.const_set(a, Hash.new(a)) } #initialize hashes Country = arr.map {|a| [a, 0]}.to_h #=> {“Japan”=>0, “Egypt”=>0, “Spain”=>0, “Brazil”=>0} or Country = Hash[arr.map {|a| [a, 0]}] #=> {“Japan”=>0, “Egypt”=>0, “Spain”=>0, “Brazil”=>0} Note: Ruby variables … Read more
You’re setting your StringVar’s wrong… textvariable = “self.var” + str(x) This is just a string. Not a reference to the StringVar. In your calc function you’re doing this: >>> float(”) Traceback (most recent call last): File “<stdin>”, line 1, in <module> ValueError: could not convert string to float: Because your StringVar has no “value” — … Read more
You can create layout like this <?xml version=”1.0″ encoding=”utf-8″?> <LinearLayout xmlns:android=”http://schemas.android.com/apk/res/android” android:orientation=”vertical” android:layout_width=”match_parent” android:gravity=”center” android:layout_height=”match_parent”> <TextView android:layout_width=”wrap_content” android:text=”That’s pnly for text(not clickable)” android:layout_height=”wrap_content” /> <LinearLayout android:layout_width=”match_parent” android:layout_height=”wrap_content”> <TextView android:layout_marginLeft=”10dp” android:layout_width=”10dp” android:layout_height=”wrap_content” android:textSize=”20dp” android:text=”Info”/> <LinearLayout android:layout_width=”match_parent” android:gravity=”center” android:layout_height=”match_parent”> <TextView android:layout_width=”wrap_content” android:text=”Hello World” android:layout_height=”wrap_content” /> </LinearLayout> </LinearLayout> </LinearLayout> 4 solved How Can I Do Text Box(left side)