You’ve been tasked with implementing a hashtable — this involves defining data types and functions to manipulate those types. I have no idea what you’re doing. First define a hashtable — do this by defining two types; one table type…
MD5 is a cryptographic hash function. Cryptographic hashes are one way functions. You cannot reverse a cryptographic hash value, but you can brute force messages to find one. Brute forcing means trying all possible input strings and then checking if…
I corrected your code also as per your need, and solved further, $ArrayX = [8349310431,8349314513] $ArrayY = [667984788,667987788] $ArrayZ = [148507632380,153294624079] $range_map = $ArrayX.zip([$ArrayY.map(&:to_i), $ArrayZ.map(&:to_i)].transpose).sort $ArrayX = [8349310431,8349314513] => [8349310431, 8349314513] $ArrayY = [667984788,667987788] => [667984788, 667987788] $ArrayZ = [148507632380,153294624079]…
If you read the documentation, you will learn it’s: key, old value, and new value. h1.merge(h2) { |key, old, new| new – old } means the final result will have value h2[key] – h1[key]. Since you are merging h2 over…
$ms = md5($transactionid.’:’.$secretkey); You need to concatenate with . solved Divide md5 function with colon (:) [closed]
Either make the information available by using statics (not recommended), use some kind of database (could be as simple as a text file) or pass an Intent along with your Activity. A nice tutorial on adding information to an Intent…
Arrays are allocated as single, large blocks of memory and entries are accessed by their indexes. The order of entries is fixed and they need have no particular identity apart from their position in the array. Other more complex data…
What is looks like is that you actually have a hash containing some Arrays. Cleaning it up I assume it should look something like this: hash = {:time_frame=>”Today”, :locations=>[“Tampa”, “Atlanta”, “California”, “Georgia”, “South Lake Union”], :local_totals=>[10000.0, 30,000, 70000, 50000, :expenses=>[2000,…
You need to join the values in a string: “#{address[‘house_number’]} #{address[‘street_name’]},\n#{address[‘city’]},\n#{address[‘post_code’]}” You could also improve the formatting by making this a helper method, and using a HEREDOC: def formatted_address(address) <<~ADDRESS #{address[‘house_number’]} #{address[‘street_name’]}, #{address[‘city’]}, #{address[‘post_code’]} ADDRESS end Usage: address = {…
The most space efficient way to store binary data is to store it as bytes. The only way you may get it even shorter is via compression. But for 92 Characters that will not amount to much. As for Base64:…
With this code you are doing linear probing index = hash(entry.key); while (!is_vacant(index)) index = next_index(index); template <class RecordType> inline std::size_t table<RecordType>::next_index(std::size_t index) const // Library facilities used: cstdlib { return ((index+1) % CAPACITY); } Say your map is nearly…
I’m not sure what exactly you want to do, but you can try the following: arr = [“Japan”, “Egypt”, “Spain”, “Brazil”] arr.each { |a| Object.const_set(a, Hash.new(a)) } #initialize hashes Country = arr.map {|a| [a, 0]}.to_h #=> {“Japan”=>0, “Egypt”=>0, “Spain”=>0, “Brazil”=>0}…
array[0].max_by{|i| i[0][‘value’].to_i} Should work 17 solved find maximum in hash ruby [duplicate]
If you can reverse it, then by definition it isn’t a hash. It’s an encoding. Any encoding will have zero collisions (otherwise it wouldn’t be able to accurately reverse it). A common encoding for this purpose is base64. solved What…
A central principle of a hash is that it is one way, as you have read. Since you want to be able to perform a two way conversion between your data and a secured version you need to use encryption,…