In order for this to work you need to override hashcode and equals on the contents of the list. Contains uses these methods, which by default are based on the memory reference so it will only work for a shallow copy. solved .contains() on a list of objects [closed]
The general case depends on whether the threads are wholly independent of each other. If you go multi-threaded, you must ensure that any shared resource is accessed appropriate protection. The code shown has a shared resource in the use of srand() and rand(). You will get different results in a multi-threaded process compared with those … Read more
Okay, it’s Saturday night and I’m feeling mellow enough to tackle this without a data model. You have given us the names of the three lookup tables (subjects, opinions, users) but not the actual structures and columns. So I’m making some guesses. select subjects.name as subject_name , opinions.value , o_users.name as opinion_guy , p_users.name as … Read more
Display the job title concatenated with the max salary (separated by a : and space) and name the column “Job Salary Range”. Use concat function solved Display the job title concatenated with the max salary (separated by a : and space) and name the column “Job Salary Range”. Use concat function
Try this instead: $result = doQuery(“SELECT DISTINCT c.PkID, c.CategoryName FROM ” . HC_TblPrefix . “categories c WHERE c.IsActive = 1 AND c.PkID IN (‘”. implode(“‘, ‘”, explode(“,”, $catIDs)) .”‘) ORDER BY c.CategoryName”); The reason your loop is only returning the last result is because you overwrite $resultCat every time, so when your loop is done, … Read more
You can use this code: theCoordinate2.longitude = [[details.longarray objectAtIndex:0] stringByAppendingString:[details.longarray objectAtIndex:1]; //and so on for index 2,3,4 stringByAppendingString:[details.longarray objectAtIndex:2 NSLog(@”longitudes list from %f”,theCoordinate2.longitude); solved how to converts NSMutableArray values into NSString? [duplicate]
Smells like homework assignment since you specifically request a recursive solution. A solution with recursion is to check whether first equals last letter and if they are recursively check the string in between. An empty or one character string is a palindrome. def palindrome?(str) str.length <= 1 or (str[0,1] == str[-1,1] and palindrome?(str[1..-2])) end solved … Read more
If I understand you correctly, you want to map the address 192.168.2.123 to the remotely accessable openvpn server 10.0.0.1 In order to do this, you will need to do two things Create an alias for the address 192.168.2.123 on your debian pc. A detailed how-to can be found here Setup your debian pc to rewrtite … Read more
If you want to run some java code(In server) and get the response in your javascript(in client). You can use Ajax in jquery. http://api.jquery.com/jQuery.ajax/ Remember this is for java (advance) programming. solved how to call java object in javascript?
Define you connection as below: import sqlite3 conn = sqlite3.connect(‘musicten.db’) 2 solved creating database based on two dataframes
First you would need to create a Map of all the letters: Hashmap<String, String> map = new Hashmap<String, String>(); map.put(“a”, “c”); map.put(“b”, “f”); … To get the translation of each letter you simply get the value from the map: String translatedLetter = map.get(letter); So now you would need to create a loop to translate the … Read more
Create your Comparator: // Here T is your class name public class Test implements Comparator<T> { @Override public int compare(T o1, T o2) { return (o1.getNumber() – o2.getNumber()); } } And pass it to Collections.sort: Collections.sort(yourList, new Test()); solved How to sort an ArrayList by comparing the element’s property?
Aside from using loops explicitly, for List<Integer> list you can do: int sum = list.stream().mapToInt(Integer::intValue).sum(); If it’s an int[] arr then do: int sum = IntStream.of(arr).sum(); This is based on the use of streams. Or you can do this simple one liner loop: int sum = 0; for (Integer e : myList) sum += e; … Read more
On Android: http://developer.android.com/reference/org/apache/http/client/methods/HttpPost.html The permission you need would be INTERNET. (Well, duh.) solved Is it possible for an app to POST to a web browser?
The way you want to do this… To answer the original question re: your formatting, you can use an if statement to define a variable, but it’s not particularly readable: $myVariable = (strlen($myString) > 0) ? ‘<p>’.$myString.'</p>’ : ”; echo $myVariable; Live demo. Recommended way to do this… However, in your case this is entirely … Read more