[ad_1] if v < e: v = e can be read: “If v is less than e, make v the value of e.” As above you should put a new line to make it read easier: if v < e: v = e [ad_2] solved Python : What is the purpose of a colon in … Read more
[ad_1] You can use the javascript history.pushState() here history.pushState({},”Some title here”,”/”) For example, on http://yourwebsite.com/secretlink.html, after the JS runs, the URL bar will show http://yourwebsite.com/ without having refreshed the page1. Note that if the user refreshes the page they will be taken to http://yourwebsite.com/ and not back to the secret link. You can also do … Read more
[ad_1] You have a couple of choices. You can use sprintf or one of it’s cousins which work like printf or you can use std::ostringstream. snprintf example #include <cstdio> char buffer[100] = “some text already there “; std::snprintf(buffer + strlen(buffer), sizeof(buffer) – strlen(buffer), “%x”, index); . std::ostringstream example #include <sstream> std::string text(“some already existing text … Read more
[ad_1] I have searched for code translators and can find no comprehensible answer. I need to know what this bit of python codes means [ad_2] solved I have searched for code translators and can find no comprehensible answer. I need to know what this bit of python codes means
[ad_1] Just do window.open(“https://stackoverflow.com/questions/20507661/how-to-open-a-url-in-a-new-window”,”this is a new window”), but please don’t add that to this page, or you might get a Stack Overflow [ad_2] solved How to open a url in a new window? [closed]
[ad_1] Yes, it’s valid. The only problem with not having a remote repository is that if your computer fails, you’ve basically lost the code and the history. Yes. The .git folder maintains all the information. To me it feels that the only problem with backing up by simply “copy pasting” the entire folder into a … Read more
[ad_1] You should use the callback in setState if you want to do that because it is async. Please refer to the following link to get more info: https://reactjs.org/docs/react-component.html#setstate Another alternative is to set the state only once instead of doing it multiple times. You don’t need to put all that info in the state … Read more
[ad_1] First you should do is to properly define type of the graph, because unlike Python you have to specify types in Swift in declaration: var graph: [String: [String: Int]] // Dictionary(hash table) with keys of type String and values of type Dictionary<String, Int> Then you should initialize graph with some initial value, because in … Read more
[ad_1] First of all you forgot semicolon $temperatuur = 19; <–here if ($temperatuur > 20) { echo “Vandaag is het lekker warm. Namelijk 23 graden”; } elseif ($temperatuur > 10) { echo “Het is weer om een dun jasje aan te trekken”; } else { //<– else statement does not accept parameter echo “Brrr… Ik … Read more
[ad_1] const data = {“chart”: {“type”: “column”},”credits”: {“enabled”: true,”href”: “#”,”position”: {“align”: “right”,”verticalAlign”: “bottom”,”y”: 0},”text”: “www.midasplus.com”},”series”: [{“color”: {“linearGradient”: {“x1″: 1,”x2″: 0,”y1″: 0,”y2″: 1},”stops”: [[0,”#9a1919″],[“0.25″,”#9a1919”],[“0.5″,”#9a7319”],[“0.75″,”#9a1919″],[1,”#9a1919″]]},”data”: [“-1.03″,”-3.01″,”-2.25″,”0.63″,”-1.07″,”1.14″,”-0.38″,”2.03″,”-2.07″,”-3.55″,”-3.99″,”-0.41″],”negativeColor”: {“linearGradient”: {“x1″: -1,”x2″: 0,”y1″: 0,”y2″: -1},”stops”: [[0,”#199A19″],[“0.25″,”#199A19”],[“0.5″,”#00CC00”],[“0.75″,”#199A19″],[1,”#199A19″]]},”showInLegend”: “false”}],”title”: {“text”: “Control Chart”},”xAxis”: {“categories”: [“Q3 2013″,”Q4 2013″,”Q1 2014″,”Q2 2014″,”Q3 2014″,”Q4 2014″,”Q1 2015″,”Q2 2015″,”Q3 2015″,”Q4 2015″,”Q1 2016″,”Q2 2016”]} } const floatArr = data.series[0].data.map(item => … Read more
[ad_1] On the following line for(student_type *p; p<=&studs[1]; ++p){ You should initialize the variable p is not initialized. You should set it to a known value. I guess you’d want to initialize it as follows. Also your stop condition goes one too far: use < instead of <=. for(student_type *p=studs; p<&studs[1]; ++p){ 3 [ad_2] solved … Read more
[ad_1] If you have all names in file (e.g. names.txt): Baynes, Aron Bazemore, Kent Beal, Bradley Beasley, Malik Beasley, Michael Belinelli, Marco Bell, Jordan Bembry, DeAndre’ You can: Read line split line (using separator) display in reverse way import java.io.BufferedReader; import java.io.FileReader; public class Main { public static void main(String[] args) { // File name … Read more
[ad_1] If you want to use recursive method why use loop in it…? I have write simple method which returns the reverse string using recursion. public string ReverseString(string s) { if (s == null || s.Length <= 1) // if length is less or equal 1 then also returns return s; return ReverseString(s.Substring(1)) + s[0]; … Read more
[ad_1] str = “IV_04.03.2019-10-56-45_example_c584536f-ab26-40ce-b5b6-386f755ba747_1.csv” s1= str.split(“_”)[2] s2= str.split(“_”)[3] print (s1) print (s2) output: example c584536f-ab26-40ce-b5b6-386f755ba747 3 [ad_2] solved How to get string between two underscores? [closed]
[ad_1] Try this: List<String> actual = new ArrayList<>(); List<String> required = new ArrayList<>(); List<String> common = new ArrayList<>(actual); common.retainAll(required); System.out.println(” 100.0 * common / actual = ” + (actual.size() == 0 ? 0 : 100.0 * common.size() / actual.size())); System.out.println(” 100.0 * common / required = ” + (required.size() == 0 ? 0 : 100.0 … Read more