[ad_1] This is much easier with ES6 template literals: div.innerHTML = rawstr.split(“\n\n”).map(str => `<p>${str}</p>`)).join(“”); newstr = oldstr.split(/\s+“|”\s+/g).map(str => `”${str}”`)).join(” “); `${p[0]} (${p[1]}) ${p[2]}` 3 [ad_2] solved An elegant way to surround a string in Javascript [closed]
[ad_1] Very simple Use the str.split() function transform your alphabet soup, then split the single elements further by directly accessing them. For example: text=””‘ A1 A10 A10 B14 C1 C14 C14 C8 ”’ for t in text.split(): print( {t[0]: t[1:]} ) prints: {‘A’: ‘1’} {‘A’: ’10’} {‘A’: ’10’} {‘B’: ’14’} {‘C’: ‘1’} {‘C’: ’14’} {‘C’: … Read more
[ad_1] there are several issues in this code. first the closing of the controller brackets should be changed app.controller(“notePadCtrl”,function($scope){ $scope.message=””; $scope.left=function(){ return 100 – $scope.message.lenght; }; $scope.clear=function(){ $scope.message=””; }; $scope.save=function(){ alert(“file got saved”); }; }); then add the angular script tag inside the body or head tag <!DOCTYPE html> <html> <head> <script data-require=”[email protected]″ data-semver=”1.5.8″ src=”https://code.angularjs.org/1.5.8/angular.js”></script> … Read more
[ad_1] Assuming you realize this is array: NSArray *a = [[NSArray alloc] init]; NSMutableArray *a1 = [[NSMutableArray alloc] init]; for(int i = 1; i < a.count; i++) { [a1 addObject: a[i]]; } 1 [ad_2] solved Saving data in NSDictionary from NSDictionary
[ad_1] You just need to make a Date object and use the getMilliseconds function of that object. Example: var d = new Date(); d.setHours(22); //10 PM d.setMinutes(25); d.setSeconds(10); console.log(d.getMilliseconds() + ‘ milliseconds’); 1 [ad_2] solved Convert given time into millisecond [closed]
[ad_1] You could use Dictionary object: Sub test() Dim keywordColumn As String, productColumn As String Dim products As String Dim i As Integer Dim myKey, p ‘after adding reference to Microsoft Scripting Runtime ‘Dim Keywords As New Dictionary Dim Keywords As Object Set Keywords = CreateObject(“Scripting.Dictionary”) keywordColumn = “B” productColumn = “A” With ActiveSheet maxRow … Read more
[ad_1] Java strings are immutable. Every time you do: s+=c; You’re really saying: s = new String(s + c); new String(s + c) must allocate a string of length s + 1, or: 1 2 3 4 5 6 7 8 9 … etc. Since Sum(1..N) == (n + 1) (n / 2), this is … Read more
[ad_1] Following is a naive method to achieve the desired functionality: Generate a mask of pixel indices with dummy values for pixel with zero value. Count the number of non-zero pixels Create an output vector with length equal to non-zero count. Copy the non-zero pixel indices from the generated mask to the output vector (a … Read more
[ad_1] insert_recursively does not return a value when it goes into else block however you store the returned value (garbage) in right_linker or left_linker anyway. Note that compiler issues a corresponding warning: warning C4715: ‘insert_recursively’: not all control paths return a value 1 [ad_2] solved wrong result in Visual Studio
[ad_1] Assume the string follows the format <int,string>,…. Please find the pseudo-code below: Loop through the string `str` and { smaller_sign_pos = str.find(‘<‘, prev_pos) entry_comma_pos = str.find(‘,’, smaller_sign_pos+1) greater_sign_pos = str.find(‘>’, entry_comma_pos+1) if (all pos values are not `npos`) { int_value = atoi(str.substr(smaller_sign_pos+1, entry_comma_pos-smaller_sign_pos-1)) str_value = str.substr(entry_comma_pos+1, greater_sign_pos-entry_comma_pos-1) prev_pos = greater_sign_pos+1 append int_value to int … Read more
[ad_1] You may use RecyclerView, which is far more advanced and customize-able than ListView. Here is a link to start with: http://hmkcode.com/android-simple-recyclerview-widget-example/ Note: I’m not representing or related to hmkcode in any way, nor intend to promote hmkcode on any forum this is just a link to provide something to start with. [ad_2] solved Should … Read more
[ad_1] You can acheive it by using this code int iend = a.indexOf(“=”); if (iend != -1) { String B = a.substring(0 , iend); } 2 [ad_2] solved Seperating String Left side =, and Right side of =
[ad_1] You can use this regex ^(?=\d)(?!0(?![.]))(?:\d{0,3})(?:[.]\d{1,3})?$ Regex Demo Regex Breakdown ^ #Start of string (?=\d) #Lookahead to ensure there is a dot or number (?!0(?![.])) #Negative lookahead to ensure there is no 0 in starting followed by . (?:\d{0,3}) #Match at most three digits before decimal (?:[.]\d{1,3})? #Match at most three digits after decimal. … Read more
[ad_1] there is a method in String class that can help you convert it, but you should give this method the regex , in your case regex is “,” you can use this method to convert it: public String[] convertToArray(String str, String regex){ return str.split(regex); } String[] str = convertToArray(str, “,”); [ad_2] solved String to … Read more
[ad_1] Usage of GetObject() is documented in this old KB article. Error handling is required to get the first instance created. Like this: Dim excel On Error Resume Next Set excel = GetObject(, “Excel.Application”) If Err.number = 429 Then Set excel = CreateObject(“Excel.Application”) End If If Err.number <> 0 Then WScript.Echo “Could not start Excel: … Read more