[ad_1] Here is a simple, but not most efficient way. you can achieve that by two step: convert list to set, to remove the duplicate number. use heap to find nlargest and nsmallest in set def difference(list1): set1 = set(list1) return heapq.nlargest(2, set1)[1] – heapq.nsmallest(2, set1)[1] Here is a one pass way, more efficient way, … Read more
[ad_1] for(int a=0;a<200;a++){ for(int g=0;g<200;g++){ char str[10]; snprintf(str, 10, “%d,%d”, a,g); key = [NSString stringWithCString:str encoding:NSASCIIStringEncoding]; } } Runs 4 times as fast on my old ipod touch 2g Time old: 4.303022833333 Time new: 1.117406833333 3 [ad_2] solved Is there a way to speed up this Objective-C string assignment?
[ad_1] 1> Why can’t i remove from tkinter import* from the last_function file.. cause anyway it’s got that on the top of the file that’s calling it right.Why do i get an error saying IntVar() not defined The Python “import” follows the same scoping rules as the rest of the Python language. By “import” at … Read more
[ad_1] The expression ++i || ++j && ++k will group like so due to precedence: ++i || (++j && ++k) One of the few rules C has about evaluation order of expressions is that the left-hand side of the || and the `&& operators must execute before the right-hand side (for short circuiting). This is … Read more
[ad_1] Java doesn’t support operator overloading, instead you need to add an add function: public class Money { private BigDecimal amount; private Currency currency; public Money add(Money m) { Money res = new Money(); if (!currency.equals(m.currency)) { throw new UnsupportedOperationException(); } res.currency = currency; res.amount = m.amount.add(amount); return res; } } Money result = one.add(two); … Read more
[ad_1] Accordingly your issue the regular expression is quite simple. /\.(jpe?g|png|gif|bmp)$/i Do you really sure that nothing else will be used? For example, JPEG format allows both .jpg and .jpeg extensions. That’s why I put e? pattern in the regular expression. Example of validation could be as follows: var filename = “/site/images/test.png”; if ( /\.(jpe?g|png|gif|bmp)$/i.test(filename) … Read more
[ad_1] Algorithm input = [2,5,1,4,7,3,1,2,3] output = [[]] for idx,val in enumerate(input): if idx > 0 and input[idx-1] > input[idx]: output.append([val]) else: output[-1].append(val) print output Output is [[2, 5], [1, 4, 7], [3], [1, 2, 3]] Explanation of the algorithm in words: Create an output list with an empty sublist. Enumerate over the input list. … Read more
[ad_1] Time complexity of program is usually calculated based on the number of inputs. For the programs like one u have given, the complexity is always constant so the time complexity is O(1). Read a bit about the complexity of algorithms then u will get a clear picture. I would suggest an algorithm book by … Read more
[ad_1] So if it’s objective c, it’s init and not init() 🙂 just saying… kinda big things… See in java, when you are doing a new MyClass() 2 things happened: the compiler book some space in memory to store your new instance the MyClass constructor is called. now, in objective-C, those 2 thing are separated … Read more
[ad_1] Just create a list and add items to it, List<Integer> checkedList = new ArrayList<Integer>(); for (Product p : boxAdapter.getBox()) { if (p.aBoolean) checkedList.add(p.id); } I would suggest you work on your basics before you start coding, it will help you in such situations. Hope this is the solution you were looking for. 0 [ad_2] … Read more
[ad_1] Try this public void generateQRCode_general(String data, ImageView img)throws WriterException { com.google.zxing.Writer writer = new QRCodeWriter(); String finaldata = Uri.encode(data, characterEncoding); BitMatrix bm = writer.encode(finaldata, BarcodeFormat.QR_CODE,bitmapWidth, bitmapHeight); ImageBitmap = Bitmap.createBitmap(bitmapWidth, bitmapHeight,Config.ARGB_8888); for (int i = 0; i < bitmapWidth; i++) { for (int j = 0; j < bitmapHeight; j++) { ImageBitmap.setPixel(i, j, bm.get(i, j) … Read more
[ad_1] Taking your second question: is this possible? Of course it is. Both PHP and python are turing complete, and both can take console input. 1 [ad_2] solved Convert Python calculator to PHP [closed]
[ad_1] Probably this line itemInventory.get(j).getName().equalsIgnoreCase(n) == true causes NPE. Make sure that itemInventory.get(j) is not null before you get the name: if(itemInventory.get(j)!=null) //only then get the name if(itemInventory.get(j).getName().equalsIgnoreCase(n)) 6 [ad_2] solved return Array[] or return null Java
[ad_1] I want the cube to return back to its original position when the user stopped touching the cube I can’t exactly tell which part of this you are struggling with but you can simply get the position of the GameObject in the Start or Awake function then set the transform.position to that value when … Read more
[ad_1] The amount of time required to execute the core of your program you’ve written is incredibly small. Figure that it consists of three or four assembly instructions, and at several gigahertz that will only require a couple of nanoseconds to run. That’s such a small amount of time that it’s vastly below the detection … Read more