[Solved] Python elif: syntax error

you end the if block in the previous line when put a instruction at the same level indentation that the if statement if condition: stuff something # doing this close the if block and a elif can only happen in a if block and you do that in if row_count == 0: for i in … Read more

[Solved] My code isn’t executing [closed]

The code does not require explanation. def getNegativesList(postivesAndNegativeslist): if postivesAndNegativeslist is None: return None elif len(postivesAndNegativeslist) == 0: return None negativesList = [] for val in postivesAndNegativeslist: if val<0: negativesList.append(val) return negativesList print(getNegativesList([2,-3,-5,10,-1])) 6 solved My code isn’t executing [closed]

[Solved] Else without if error? [closed]

Let’s take a closer look at your code’s conditional structure by correctly separating and using indentations: I like to add a bit of white-space to clearly know what’s going on. private void main(void){ //Indentation shows how program blocks are related to one another if (this.condition(parameters) == true) // Indentation here shows the following statement is … Read more

(Solved) PHP parse/syntax errors; and how to solve them

What are the syntax errors? PHP belongs to the C-style and imperative programming languages. It has rigid grammar rules, which it cannot recover from when encountering misplaced symbols or identifiers. It can’t guess your coding intentions. Most important tips There are a few basic precautions you can always take: Use proper code indentation, or adopt … Read more