To get the expected output, you can make the outer loop loop from word.length() – 1 down to 0 instead: #include <cstddef> // std::size_t #include <iostream> #include <string> int main() { std::cout << “Enter the word:”; if (std::string word; std::cin >> word) { for (auto i = word.length(); i–;) { // <- here for (std::size_t … Read more
You may want to try out the following regex. Regex101 link ((?:\?.*?&|\?)journey=)[^&]* Try out the following code to replace the value of journey to replacement string url = “http://www.whitelabelhosting.co.uk/flight-search.php?dept=any&journey=R&DepTime=0900″; string newUrl = Regex.Replace(url, @”((?:\?.*?&|\?)journey=)[^&]*”, “$1″+”replacement”); Remember to add the following to your file: using System.Text.RegularExpressions; You can do the same for DepTime using the following … Read more
Your post isn’t javascript, but here’s basically what you want to do. It should be easy to change it over from javascript. function compareWords(words){ var longestWord = ”; for(var i = 0; i < words.length; i++){ if(words[i].length > longestWord.length){ longestWord = words[i]; } } return longestWord; } var words = [‘gunslinger’, ‘gundam’, ‘dragon’, ‘shirt’, ‘unicorn’, … Read more
To get the part of the string after the first space: string city = str.Substring(str.IndexOf(‘ ‘) + 1); This will also give a result even if there happens to be no space in the string. The IndexOf method will return -1 in that case, so the code will return the entire string. If you would … Read more
Just pass empty string to end parameter in print function after strippping off the newline character. print (line, end = “”) print by default print the content in a new line for each iteration but by passing empty string to the end parameter, this default behaviour won’t work. If you failed to remove the newline … Read more
You can try this- const data = [ “2-inch leg extension”, “2′ x 8′ Overhead Garage Storage Rack”, “4 Drawer Base Cabinet 16-1/2\”W x 35\”H x 22-1/2\”D”, “24\” Long Tool Bar w/ Hooks Accessory” ]; const res = data.map(str => str.replace(/[^a-z\d\-_]/ig, ”)); console.log(res); If you need any prefix with the ID then add it like- … Read more
The problem is in the MakeALine method. You actually concat the number with itself, so for input 1 you actually get “1” + “1”. Instead you should repeat the string representation of your number k times. For this you can use Enumerable.Repeat in the following way: static string MakeALine(int k) { return String.Concat(Enumerable.Repeat(k.ToString(),k)); } 3 … Read more
Since after one day all the comments and answers so far obviously could not help you, see the following simple solution. The exercise targets people starting with C++, so I suppose it is better to use basic constructs like arrays and loops. The array counts holds the counts of the digits, one for each possible … Read more
This has to do with the scope of your variables. You can find more informatnion here. Currently the variables stored in class A have package-private scope. There are really two ways to do what you are describing. The better solution would be to provide a getter method within classA: public String getA(){ return this.A; } … Read more
Guessing that you want to split by the comma then this will make it String toSplit = “LXI H, 2000H, MOV M A”; // this is a regular expression, you should study regular expressions too String[] split = toSplit.replace(“,”, “”).split(” +”); for (String s : split) System.out.println(s); Read the String class in the java API … Read more
First open an ifstream to open your file then check for the string: #include <iostream> #include <fstream> #include <string> using namespace std; int main () { string line; ifstream myfile (“example.txt”); if (myfile.is_open()) { while ( getline (myfile,line) ) { if(line.find(“the string to find”) != string::npos) { //line found, do something } } myfile.close(); } … Read more
You can try something like this : input_st = “Field1:’abc’,Field2:’HH:MM:SS’,Field3:’d,b,c'” output_st = {item.split(“:”)[0]:”:”.join(item.split(“:”)[1:]).replace(“‘”, “”) for item in input_st.split(“‘,”)} outputs : {‘Field1’: ‘abc’, ‘Field2’: ‘HH:MM:SS’, ‘Field3’: ‘d,b,c’} Kind of ugly but it does the job. 4 solved Convert string to Ordered Dictionary [closed]
Use: var queryStringParts = queryString.split(‘&’); var pairs = queryStringParts.map(function(str) { return str.split(‘=’) }) var rewrittenParts = pairs.map(function(pair){ return ‘slides[0].’ + pair[0] + ‘=’ + pair[1] }); var newQuerystring = rewrittenParts.join(‘&’); As was pointed out in the comments, in this specific case we could skip the split into pairs step and just do var queryStringParts = … Read more
public class TranslateChar { /** @param args */ public static void main(final String[] args) { final Map<Character, Character> mapCharCod = new HashMap<>(36); final Map<Character, Character> mapCharDecod = new HashMap<>(36); mapCharCod.put(‘A’, ‘Z’); mapCharCod.put(‘B’, ‘X’); mapCharCod.put(‘C’, ‘Y’); mapCharDecod.put(‘Z’, ‘A’); mapCharDecod.put(‘X’, ‘B’); mapCharDecod.put(‘Y’, ‘C’); final String toCod = “CAB”; StringBuilder sb = new StringBuilder(“{“); for (final char c … Read more
Here char *firstName[50]; firstName is array of 50 character pointer, and if you want to store anything into each of these char pointer, you need to allocate memory for them. For e.g for (int counter = 0; counter < 10; counter ++) { firstName[counter] = malloc(SIZE_FIRST); /* memory allocated for firstName[counter], now you can store … Read more