[ad_1] Whats wrong with this program in C? It terminates. I am having difficulty in understanding read input string in pointer of pointers [closed] [ad_2] solved Whats wrong with this program in C? It terminates. I am having difficulty in understanding read input string in pointer of pointers [closed]
[ad_1] Good question… This is really hard to answer but I attempted a solution(what engineers try to do) that might work based on analyzing the pattern example you gave: import string import random def generate_similar(string): # Generates similar name by substituting vowels similar_word = [] for char in string: if char.lower() in ‘aeiou’: similar_word.append(random.choice(string.letters).lowercase()) else: … Read more
[ad_1] This is an alternative that does not require to create a custom Comparator. I’m proposing it only for the sake of completeness. Split the String in words. Create a SortedMap. Iterate on the word list. Populate it with “%03d%05d”.format(999-aWord.length(),i) -> aWord , where i is the index of aWord in in the word list. … Read more
[ad_1] test=”qwertyuiopasdfghjklzxcvbnm” def changestring(string): for x in ‘aeiou’: string = string.replace(x, ‘*’) return string changestring(test) ‘qw*rty***p*sdfghjklzxcvbnm’ Is this what you are trying to do? 5 [ad_2] solved Why can’t I return the modified str_func function back to the main function?
[ad_1] While this code is not pretty to do what your’re looking to do you need to change these lines if num>0: l+='”‘+ str(k) + ‘”=’ + str(num)+’ ‘ True if True: lst+=[l] If you change it to something like if num>0: l+='”‘+ str(k) + ‘”=’ + str(num)+’ ‘ flag = True if flag: lst+=[l] … Read more
[ad_1] Assuming your string will always have only two -s, you could using the following to get the substring between them. If this is not the case please modify the question to better describe the issue. string myString = AccountName.Split(‘-‘)[1]; Check out https://msdn.microsoft.com/en-us/library/system.string.split(v=vs.110).aspx for more information on the Split method in the string class. 1 … Read more
[ad_1] Pretty simple: In [8]: course_name Out[8]: ‘Post Graduate Certificate Programme in Retail Management (PGCPRM) (Online)’ In [9]: print re.sub(‘\([A-Z]+\)\s*’, ”, course_name) Post Graduate Certificate Programme in Retail Management (Online) In [17]: print re.search(‘\(([A-Z]+)\)\s*’, course_name).groups()[0] PGCPRM 0 [ad_2] solved Extract only first match using python regular expression [duplicate]
[ad_1] To print empty elements: for (int i = 0; i < arr.length; i++) { if (arr[i] == null || arr[i].trim().isEmpty()) { System.out.println(“Element ” + i ” + ” is null or empty.”); } } The print non-empty elements: for (int i = 0; i < arr.length; i++) { if ( arr[i] != null && … Read more
[ad_1] It’s actually working correctly. There is a leading space on the string and thus the ninth index is the space just before the DU. Consider this diagram: Jun30/13 DU SJ9802 0123456789 You’re starting on the ninth index, and that’s a space . 1 [ad_2] solved string.Substring not working correctly in C#
[ad_1] I am not going to write the code for you, but this will probably help. If I am understanding the question correctly you are trying to take a big block of text (paragraph) split it into sentences then get the average len of characters in each sentence. So: 1) Break text block into sentences. … Read more
[ad_1] raw_input returns a string. Strings are never equal to numbers. >>> ‘0’ == 0 False Compare the string with a string. For example, to check whether the string starts with specific character (sub-string), using str.startswith: if number.startswith(‘0’): … [ad_2] solved Determining the First Digit
[ad_1] The reason beeing is the compiler. At compile time the compiler does notice that the literal Hi exists twice in the code and does intern this string for your specific class. After compilation both of your interned strings Hi are pointing to the same reference of Hi. That´s the reason why the second print … Read more
[ad_1] Perhaps like this. Note that string concatenation cannot be done on simple char types. #include <stdio.h> #include <string.h> int main (void) { char s1[] = “stack”; // skipped the string inputs char s2[] = “overflow”; char str[120]; size_t i; // var type returned by `strlen` size_t index = 0; size_t leng1 = strlen(s1); size_t … Read more
[ad_1] Well. I cannot give you code… I can give you some advice.. Split the String based on semicolon (;). For each String in the array (which you got after splitting, except the last one) split it again based on “=”. Take the RHS of the split String and parse it as integer. Now parse … Read more
[ad_1] First, no one is supposed to give you the actual code for your homework. Here is the basic idea on how it looks like conceptually: This can be done recursively by (pseudo-code of course): String[] allCombinations(String[] input) { if (input is empty) { return [ “” ] } String[] result String[] childrenCombinations = allCombinations(input[1:]) … Read more