That’s because you never set an initial value for x and y in either ArcherDown or Archer. You can solve this problem by adding a method such as def __init__(self, x, y): self.x = x self.y = y to each class. 3 solved Why does it say that my instance has no attribute x?
You can try something like this : input_st = “Field1:’abc’,Field2:’HH:MM:SS’,Field3:’d,b,c'” output_st = {item.split(“:”)[0]:”:”.join(item.split(“:”)[1:]).replace(“‘”, “”) for item in input_st.split(“‘,”)} outputs : {‘Field1’: ‘abc’, ‘Field2’: ‘HH:MM:SS’, ‘Field3’: ‘d,b,c’} Kind of ugly but it does the job. 4 solved Convert string to Ordered Dictionary [closed]
The two main concept that you see in the last line are list comprehension and nested loops. Have a look. for understanding better what is going on, we’re going to split that line in simplier part: TENS for tens in “twenty thirty forty fifty sixty seventy eighty ninety”.split(): print(tens) OUTPUT: twenty thirty forty fifty sixty … Read more
After going through the Pandas documentation, found the way to validate the data. Let’s just say you have a custom validation function. def validate_rating(rating): “””” Description: validate if hotel rating is a digit between 0 to 5 Args: rating (str): rating to be validated Returns: True if rating is valid False if rating is not … Read more
You could just iterate until 5 instead of 6 and print your message out of the loop: for counter in range(5): # Remove the if statement: # if counter == 5: # print(“”) # break myCar.accelerate() time.sleep(1) print(“Maximum speed reached!”) 1 solved Break out of Python for loop
raw_input returns a string … you cannot square a string (or raise it to any power for that matter) try def square(n): n = int(n) #this will try to force it to be an integer instead of a string … print square(n) beware if a user types “hello” or something though .. as it cannot … Read more
Here is the best I can do with your description: i need to concat result of a search ( it could be FG|BG|MG ) with a known string import re line = “createNode transform -n \”water\” -p \”FG\”;” m = search(r'(FG|BG|MG)’,line) if m: result = m.groups()[0] # What do you want to concat it to? … Read more
When cv2 can’t read image then it doesn’t raise error but it returns None and later it may gives error in other lines when it tries to use this None to display image (or change color, or edit image) You should use full path in imread() – imshow needs text for widow’s title, it doesn’t … Read more
Computing the ratio Since there are multiple regions in a country, there are duplicated values in the Country_Region column. Therefore, I use groupby to sum the total cases of a nation. ratio = df.groupby(“Country_Region”)[[“Recovered”, “Confirmed”]].sum() ratio[“Ratio”] = ratio[“Recovered”] / ratio[“Confirmed”] Let’s get the first five nations. >>> ratio.head() Recovered Confirmed Ratio Country_Region Afghanistan 41727 52513 … Read more
If you already have the helper functions then you only need to loop once through each item of the list and modify all your key:value pairs: for i in list: i[‘key’] = recode_key(i[‘key’]) i[‘anotherkey’] = recode_anotherkey(i[‘key’]) i[‘yetanotherkey’] = recode_yetanotherkey(i[‘key’]) You would need to loop through the list once, touch all the keys that you need, … Read more
You need to write the command twice, one with @commands.command and a second with @cog_ext.cog_slash Maybe if the commands function is very long or you just do not want it twice you can spil it it into another funtion that you call with both commands async def cmd(author): # do your commands stuff here @commands.command(name=”cmd”) … Read more
You can make use of re.split to split into sections and then look for the [failed] string in the each section: splitted = re.split(r'(\d{1,2})\.(.*)(?= _{3,})’, text) failed = [(splitted[i-2], splitted[i-1]) for i, s in enumerate(splitted) if re.search(r’\[failed\]’, s)] failed # [(‘9’, ‘TX_MULTI_VERIFICATION 2412 DSSS-1 NON_HT BW-20 TX1′), # (’11’, ‘TX_MULTI_VERIFICATION 2472 DSSS-1 NON_HT BW-20 TX1’), … Read more
python 3 simple calculator , need assistance understanding subject and completing task, new to python and coding in general [closed] solved python 3 simple calculator , need assistance understanding subject and completing task, new to python and coding in general [closed]
It’s a Python indentation issue. The start of your print line must have the same indentation as the start of the train_accuracy line. Something like this: if i%10 == 0: train_accuracy = sess.run( accuracy, feed_dict={ x:batch[0], y_: batch[1], keep_prob: 1.0}) print(“step %d, training accuracy %g”%(i, train_accuracy)) solved Error while using simple print in Python [closed]
Problem with your current regex wiz r’^[0-9]{8,8}’: {8,8} minimum and maximum length you want is 8 so you can make it exact 8 like {8}, no need to have range Current regex has condition to check beginning of string but you have not defined end of string which can be defined using symbol $ which … Read more