You could just iterate until 5 instead of 6 and print your message out of the loop: for counter in range(5): # Remove the if statement: # if counter == 5: # print(“”) # break myCar.accelerate() time.sleep(1) print(“Maximum speed reached!”) 1 solved Break out of Python for loop
You could probably use goto.js (http://summerofgoto.com/) to handle this with the exact loop that you’re trying to use, but you should consider just finding a different way to factor your code. 3 solved Moving on deep function [closed]
If I understand you correctly, you want to loop while a condition is true and exit the loop when the condition become false. So you should be using the while control-flow operator, not for. i <- 1 while(i<=length(blocks) & length(blocks[[i]])!=0){ i <- i+1 } # check that we exited the loop because there was a … Read more
print value (prints 1) ++ (adds 1 to $value) check if value is > or = to 10 and break if it is that is why you loop never gets to printing 10 since it breaks when the value is equal to 10 solved it may seem like a silly question but it’s confusing to … Read more
As per the specifications 6.6.1 The break statement [stmt.break] The break statement shall occur only in an iteration-statement or a switch statement and causes termination of the smallest enclosing iteration-statement or switch statement; control passes to the statement following the terminated statement, if any. Hence 1 should not even reach . Some Java compiler might … Read more
Change the condition in your while loop to use == not =. Right now you are making an assignment and not comparing the two meaning the first chars will always be the same and give a score of 1. You can then remove the if statement from inside the loop. The assignment asks you to … Read more
int val; while (1) { printf(“Enter the number to be reversed”); scanf(“%d”, val); if (val == 0) { printf(“exiting program…!!”); exit(0); } // your code for reversing } 4 solved Creating an infinite loop with an exception on C [closed]
This is the way break works. If you want to iterate over the whole list, simply remove the break (or if you want to do something with the value, use pass as a placeholder). values = [1, 2, 3, 4, 5] for value in values: if value == 3: pass print(value) Output: 1 2 3 … Read more
P.S. I was using two do while loops one inside of another maybe that is what caused it? It could well be. A break (note the spelling) will only break out of one loop, so if it was inside the inner loop, it would break out of that loop, but continue execution immediately after the … Read more
Your $digit variable is the maximum, use it that way. Change your for loop in this for ($x= 1; $x <= $digit; $x++) { echo ‘Hello ‘ . $x. ‘<br />’; } Then you will get what you want. solved Input numeric text for # loops [closed]
When you enter a number different than 2 you actually read another line which you do not process: if (answer != 2) { Console.WriteLine(“Wrong answer. Press enter to get your next sum”); Console.ReadLine(); } Your confusion could be because of this line. Change it to: if (answer != 2) { Console.WriteLine(“Wrong answer. Press enter to … Read more
If you want to check whether the input is zero before doing anything else, do so. If you want to stop the loop in certain conditions, put the break inside a conditional. Note that count and total were unused. Also, format() with no formatting is redundant. def main(): while True: entry = int(input(‘Enter a number … Read more
I don’t recommend you to use break statement if it’s not strict necesary it’s use. It isn’t a good practise in programming (look at this: Is it a bad practice to use break in a for loop?) and I recommend you to use another alternatives, instead of break that could make the same work. For … Read more
You can’t compare two string pointers with != or ==. you need to use strcmp, for example: while (strcmp(check,input) != 0) strcmp compares the string pointed to, by str1 to the string pointed to by str2. 3 solved I am trying to write a program that stops with a specific string input [duplicate]