Since your files are sorted, you don’t have to store them or even parse them outside of lines. You can keep advancing in the sequence with the lesser current element: def count_equal(a, b): “”” Counts the number of values that are equal in two sorted iterables. >>> odds = [1, 3, 5, 7, 9, 11, … Read more
For this to work, you would have to sort your coins in descending order, or use reversed(coinList) instead of coinList in the first for loop and vice versa in the second if you would like to sort them forwards: total = 250 value = 0 coins = [] coinList = [100, 100, 20, 20, 20, … Read more
The trick is to recognize that you don’t have to test all the a up to x. For a^x == a+x, then a&x == 0. So we count the number of zeroes in the bitstring of x and then out answer is 2**count -1 test = int(input()) for _ in range(test): x = int(input()) print(2**bin(x)[2:].count(‘0’) … Read more
There can be many other reasons that slow down your site. But at least you can use minified versions. Also combining them into one file as you said should help. Have a look at Scott Hanselman’s article. solved Site is loading slowly. Is javascript the culprit? [closed]
Rather than using benchmarks for the GPU, look at existing cross-platform applications with similar performance and see how it compares. Install it on your computer to make sure the intensiveness is similar (using whatever benchmarks you want), then install it on your android device to see if it can keep up to your expectations. You … Read more
To get more accurate results, remove the calls to Console.WriteLine inside both loops. You will still see that parallel loop is slower, because of the reasons stated in the question comments. To get a better feel for why that is, use instead an overload of Parallel.For from here and set the property ParallelOptions.MaxDegreeOfParallelism to 4 … Read more
We see runtime performance issues compiling Java 6 bytecode with Java 7. Is that expected? No. It is not expected. It is possible … but I wouldn’t have predicted it, and I can’t think of an obvious explanation. What are the downsides/benefits of doing that? I can think of no real benefits to your problem … Read more
A static variable is a variable: public static int whatever = 0; A static method is a method: public static void whatever() {} A static class is a class: public static class SomeInnerClass {} (A class can only have the static modifier when it is nested inside another class) Static variables and methods can be … Read more
In short: probably Matlab and Python achieve similar speeds in loops. The sources that you found are likely comparing old versions of Matlab, as @Eitan mentioned the new versions have proper Just In Time mechanisms which speed simple loops up a lot. There will be loops that python does faster, and those that Matlab does … Read more
Never wonder; use Google Caliper to find out. Since there has been quite a bit of discussion around the relative weights of testing against zero vs. upper limit and incrementing vs. decrementing, here’s the Cartesian product of all these cases: import java.util.Random; import com.google.caliper.Runner; import com.google.caliper.SimpleBenchmark; public class Performance extends SimpleBenchmark { static final Random … Read more
List<Type> list = … list.removeIf(item -> item.getId() == something); As the name suggests, removeIf() removes all elements if they satisfy the predicate. 7 solved How to remove some items from an arraylist without loop and less time complexity?
There’s no single instruction that can do this. BMI1 blsi dst,src can isolate the lowest set bit, not the highest. i.e. x & -x. If x86 had a bit-reversed version of blsi, we could use that, but it doesn’t. But you can do much better than what you were suggesting. An all-zero input is always … Read more
Could the Rust program be written in an idiomatic way, to execute faster? Yes. To create a vector with a few elements, use the vec![] macro: let mut work: Vec<f64> = vec![0.0, 1.0]; for _x in 1..100000000 { work.swap(0, 1); } So is this code faster? Yes. Have a look at what assembly is generated: … Read more
The simplest solution is the below one. str = “0x00000000 7B 22 69 64 22 3A 36 35 33 30 36 36 33 7D {“”id””:2133221}” arr = Split(str, “:”) strID = Left(arr(1), len(arr(1)) – 1) msgbox strId However, If you still need a more robust one, try regex 3 solved Extract Text from Response Body … Read more
In words, the process you’re doing says “zero out the flags for all multiples of this number.” The if statement says “do the next step only if the current number is a prime.” The second sieve has to zero out all multiples of 2, then 3, then 4, … for every number in the sieve. … Read more