Your second code (after removing the syntax error caused by the comment) reads a = b– – printf(“a = %d, b = %d”, a, b); Since printf returns a value, that is valid code. When I initialise int a = 0; the program output is a = 0, b = 120 In C end-of-line does … Read more
There are multiple things. One is that some of your code is unnecessary. public Dice(int dice1 /*, int a, int b, int c, int d, int e, int f*/ ){ this.dice1 = dice1; //this.a = a; //this.b = b; //this.c = c; //this.d = d; //this.e = e; //this.f = f; } You don’t need … Read more
This is enough I suppose for explaining whatever you have shown. And the behavior you see can be anything given that it is undefined. From standard The fprintf function writes output to the stream pointed to by stream, under control of the string pointed to by format that specifies how subsequent arguments are converted for … Read more
char is a that, on most systems, takes 1 byte (8 bits). Your implementation seems to have char represent a signed type, however on other implementations it could be unsigned. The maximum value for a signed type is 2^(n-1)-1, where n is the number of bits. So the maximum value of char is 2^(8-1)-1=2^7-1=128-1=127. The … Read more