Try with int probability = x / 1000; // 1/100 of the value to get an probability in percent (integer) or float probably = x / 100000F; //F for a `float` double probability = x / 100000.0; //a decimal without a F is a `double` Without that, this can’t work : float probably = x … Read more
Assuming your JSON is assigned to a variable called response you can access the body with:let body = response.data.data[0].body And the title withlet title = response.data.data[0].title In case you want to loop over the data array in order to get a value for all entries (e.g. title), try this:let titles = response.data.data.forEach(entry => console.log(entry.title)); 0 … Read more
Change it to: public static class ObjectsGlobal { public static Bays bay1 = new Bays(); public static bay10 = new Bays(); } Also, as recommended in a comment I have now read, take a look at the Singleton Pattern. solved C# Global Object [closed]
let chanIds[someObject.chanId] = someObject.symbol 1 solved How give key object through condition ‘if’?
Use Array.prototype.map instead, forEach gets no returns let newobj = [ { id: 22, reason: ‘reason 2’, phase: ‘phase 2’, reviewer: ‘by user 2’, date: ‘date 2’ }, { id: 21, reason: ‘reason 1’, phase: ‘phase 1’, reviewer: ‘by user 1’, date: ‘date 1’ } ]; let arr1 = { initiateLevel: true, parent: [ { … Read more
Any JS problem relating to this is likely due to the way the function using this is called. Storing a reference to this in your that variable should let you reference it from within your nested functions, exactly the way you are doing it already – assuming that qwerty() is called in a way that … Read more
GradeBook::Grade is a non-static member function, it needs to operate on an instance of GradeBook. You can’t pass it in to a function expecting a plain function pointer. You could change TESTobj::SET to accept std::function objects, then wrap your member function in a lambda: void TESTobj::SET(std::function<void()> nu) void GradeBook::Set() { OBJ.SET([this](){Grade();}); OBJ.Test(); } solved C++ … Read more
You can reduce the objects into a Map by iterating the sources of each object using forEach. You spread the Map’s keys iterator to get the sources array, and spread the values iterator to get the values array: const data = [{“year”:2017,”month”:1,”sources”:{“source1″:50,”source2″:30,”source3”:10}},{“year”:2017,”month”:2,”sources”:{“source1″:50,”source2”:10}},{“year”:2017,”month”:3,”sources”:{“source1″:10,”source2″:10,”source3”:1}}] const sourcesMap = data.reduce((m, { sources }) => { Object.entries(sources).forEach(([key, value]) => m.set(key, … Read more
First, your code is not valid C++. Declaring empty arrays using [] does not exist in C++. So the first thing is to turn this into valid C++ that still preserves what you’re trying to accomplish. One solution is to use std::vector: #include <vector> class Universe { public: std::vector<Star> stars; std::vector<Planet> planets; public: Universe(const std::vector<Star>& … Read more
C++ does not have an associated length property for arrays. (See How do I find the length of an array?) You can do something like this: int length = sizeof(animals)/sizeof(animals[0]); Then, before accessing member variables of elements (like this: animals[i] -> hasFur(true);), you need to first create objects. animals[i] = new Animal(); // assuming the … Read more
Because it’s a dictionary, no enumerate() required: var aDictionary: [String: Float] = [“EUR”: 1, “RON”: 4.5, “USD”: 1.3] for (index,item) in aDictionary{ print(index,item) } solved How can I loop through objects in Swift? [closed]
In python? why do the subclass inherit from parent? when you use the init of method to assign the parent?but it does not work [duplicate] solved In python? why do the subclass inherit from parent? when you use the init of method to assign the parent?but it does not work [duplicate]
A simple Array.prototype.reduce with Object.assign will do // objectMap reusable utility function objectMap(f,a) { return Object.keys(a).reduce(function(b,k) { return Object.assign(b, { [k]: f(a[k]) }) }, {}) } var arr = { “a”: “Some strings of text”, “b”: “to be encoded”, “c”: “& converted back to a json file”, “d”: “once they’re encoded” } var encodedValues = … Read more
All objects must have keys. You define an object using curly bracers {}. Basically what you are saying is, add an array with one object that has no keys defined. If you want an array with the values a,b,c,d you can remove the bracers: myObjectList[0] = [“a”, “b”, “c”, “d”]; You always define objects with … Read more
Just use array[0].value: var array = [{ label: “1”, value: “11” }, { label: “2”, value: “22” }, { label: “3”, value: “33” }, { label: “4”, value: “44” }, ]; var firstValue = array[0].value; console.log(firstValue); You can also use destructuring like so: var array = [{ label: “1”, value: “11” }, { label: “2”, … Read more