for (final Map.Entry<String, Object> entry : hashmap.entrySet()) { final String key = entry.getKey(); System.out.println(“Key:” + key); Object obj = entry.getValue(); } solved How can I retrieve values and keys from a HashMap in Java 8?
user_key = user_id.key() But why is your head spinning? What are you actually trying to accomplish? 0 solved Deriving Key() from get_by_id()
You could do this: a = {‘vladimirputin’: {‘milk’: 2.87, ‘parsley’: 1.33, ‘bread’: 0.66}, ‘barakobama’:{‘parsley’: 0.76, ‘sugar’: 1.98, ‘crisps’: 1.09, ‘potatoes’: 2.67, ‘cereal’: 9.21}} b = {} for prez in a: for food in a[prez]: if food not in b: b[food] = {prez: a[prez][food]} else: b[food][prez] = a[prez][food] This gives: {‘bread’: {‘vladimirputin’: 0.66}, ‘cereal’: {‘barakobama’: 9.21}, … Read more
Try this // file path $file=”orderdata.txt”; // REMEMBER TO MENTION THE CORRECT FILE WITH EXTENSION // open the file and get the resource handle with errors suppressed $handle = @fopen($file,’r’); // DONT USE @ while at development since it will suppress errors // array to hold our values $params = array(); if($handle) { // if … Read more
let chanIds[someObject.chanId] = someObject.symbol 1 solved How give key object through condition ‘if’?
items() contains tuples, key-value pairs: >>> spam.items() dict_items([(‘name’, ‘Zophie’), (‘age’, 7)]) Your key is not such a tuple. It may be contained in one of the tuples, but in does not test for containment recursively. Either test for the correct key-value tuple: >>> (‘name’, ‘Zophie’) in spam.items() True or if you can’t get access to … Read more
It’s definitely an array key issue, but it seems you have unique alt attributes in each data set (array). <StyledHorizontalScrollList columns={columns}> {tunesTeasers.map(teaser => teaser.noTonieboxes ? ( <List key={teaser.alt} onClick={toggleModal}> <TeaserCard alt={teaser.alt} src={teaser.src} /> </List> ) : ( <StyledLink key={teaser.alt} to={teaser.link}> <TeaserCard alt={teaser.alt} src={teaser.src} /> </StyledLink> )} </StyledHorizontalScrollList> solved React: Warning each child in a list … Read more
You need to have a backend server to do to this, it will test if the key is valid, if not it won’t download. If it is valid it will download. Here is the most basic authentication that you can do. I would recommend using a better secret key to test for validation, such as … Read more
The old way of doing this is a multi-step process: add the column which will be the primary key update the column enforce the primary key. Something like this: create sequence t23_id; alter table t23 add id number; update t23 set id = t23_id.nextval ; alter table t23 add constraint t23_pk primary key (id); In … Read more
In my case the keys were integers They were not. Object property names can only be strings or Symbols (ECMAScript, mdn). The numbers (JS doesn’t have an integer data type) were converted to strings when the property was created, not when the property names were read. solved Why does Object.keys() return an Array of strings? … Read more
There is the working code quiz_scores = { ‘Corbin’: [92, 66, 88, 91, 100, 95, 94], ‘Kevin’: [100, 99, 100, 98, 95, 98, 99], ‘Hannah’: [79, 67, 78, 81, 70, 55, 74], ‘Ben’: [94, 88, 85, 100, 91, 79, 88], ‘Yasaswini’: [99, 90, 88, 91, 89, 95, 94], ‘Veda’: [79, 97, 88, 82, 70, 95, … Read more
A simple INternet search would have brought you to Wikipedia, where the following is stated on DNS Record Classes: The CLASS of a record is set to IN (for Internet) for common DNS records involving Internet hostnames, servers, or IP addresses. In addition, the classes Chaos (CH) and Hesiod (HS) exist.[34] Each class is an … Read more
You just need to group your array elements and use map to join your keys using joined(separator: “, “): extension Array { func group(of n: IndexDistance) -> Array<Array> { return stride(from: 0, to: count, by: n) .map { Array(self[$0..<Swift.min($0+n, count)]) } } } Testing: let dic = [“f”:1,”a”:1,”b”:1,”c”:1,”d”:1,”e”:1, “g”: 1] let arr = Array(dic.keys).group(of: 2).map{ … Read more