Your question is not well-phrased. If your elem1 or elem2 is a single item you want to compare against, this is pretty easy. Just do a LINQ Where to find the items that match the criteria. Coordinates it = new Coordinates { lat = 5, lon = 5 }; var picked = list.Where(x => Math.Abs(x.lat … Read more
Because x :: xs returns a new list, where the first element is x, followed by xs. So, to make your code work, make list a var and re-assign it inside the loop: var list = List[Int]() while(list.length < 20) list = Random.nextInt(100) :: list However, the idiomatic way of doing this in Scala is … Read more
Something like this: dictionary = {‘results’: [{‘name’: ‘sarah’, ‘age’: ’18’}]} name = dictionary[‘results’][0][‘names’] + ‘.txt’ open(name, “w”) Opening a file in the write mode, if it doesn’t exist already, will create a new file with that name. 2 solved How to name a file using a value in a list in a dictionary?
var temp = new List<string>(); foreach(var item in remoteFiles){ if(localfiles.Contains(item) == false){ temp.Add(item); } } //temp now contains all items in remoteFiles that are not present in localfiles 1 solved How to compare two lists and get unmatching items – without using LINQ [closed]
“I do not need a solution with saying me to make my own class. I definitely will not re-invent an already existing data-type!” List<string,string,string> is not an already existing data type. You probably did something like this in the past; // Another simple way would be to create a class which has a constructor to … Read more
The tricky part is aligning the several table entries and the table headers. For this, we first have to find out how long the longest entry in each column is. pad then can be used to add a number of padding spaces to the given string. fields = [“ident”, “make”, “model”, “disp”, “power”, “luxury”] max_len … Read more
First, you should be more specific of what you expect. If you want your list to be the sum of the numbers in the tuples, here’s what you can do: listnum = [sum(x) for x in listnum] 1 solved How can I add tuples in a list? [closed]
Two major issues: 1) You are storing the results in chos_items, then not doing anything with them. full_items, when you exit the while loop, contains “end” or “” print(“That would be, {}”.format(‘ ‘.join([items[int(item)] for item in chos_items]))) Will give you a list of all the items chosen, but it won’t give how many, as you … Read more
UPDATED: private List<string> Clients = new List<string>(){ “Jack”, “Sandra”, “Anna”, “Tom”, “Bob”}; private void btnAddClient_Click(object sender, EventArgs e) { string msg = “”; if (txtAddClient.Text == “”) { MessageBox.Show(“No client name has been entered!”); } else { string newClient = txtAddClient.Text; Clients.Add(newClient); foreach (string val in Clients) { msg += “- ” + val + … Read more
Why not do this: for(int i=0; i<selectedPlanet.size(); i++) { if(planet.isChecked()) { selectedPlanets.add(planet.getDisplayName()); } else { selectedPlanets.remove(planet.getDisplayName()); } } 6 solved add or remove a string from a list based on an if statement
using System; using System.Collections.Generic; using System.Text; using Microsoft.PointOfService; namespace POS { public class CashDrawerClass { CashDrawer myCashDrawer; PosExplorer explorer; public CashDrawerClass() { explorer = new PosExplorer(this); DeviceInfo ObjDevicesInfo = explorer.GetDevice(“CashDrawer”); myCashDrawer = explorer.CreateInstance(ObjDevicesInfo); } public void OpenCashDrawer() { myCashDrawer.Open(); myCashDrawer.Claim(1000); myCashDrawer.DeviceEnabled = true; myCashDrawer.OpenDrawer(); myCashDrawer.DeviceEnabled = false; myCashDrawer.Release(); myCashDrawer.Close(); } } } try that. maybe … Read more
You can get the first item of the list like so: Person p = pList[0]; or Person p = pList.First(); Then you can modify it as you wish: p.firstName = “Jesse”; Also, I would recommend using automatic properties: class public Person { public string firstName { get; set; } public string lastName { get; set; … Read more
There is no need to multiply each element by 2; just multiply the whole sum by 2 afterwards. >>> data = [9, 4, 5] >>> 2 * sum(data) 36 2 solved Python performing calculation in a list
Your attempt won’t work since you’re handling the creation in the loop, so you will end up adding several persons there. Just write it the way you described it: if (allPersons.isEmpty() || !allPersons.contains(person)) allPersons.add(person) Now, in order for this to work you have to ask yourself an important question: What exactly constitutes “the same person”? … Read more
You can use Contains status = false; for (var i = 0; i < ids.Count; i++) { if (list.Count > 0 && !list.Contains(ids[i])){ list.Add(ids[i]); //add this, be it duplicate or not status = true; //different element found break; //break if this is not duplicate } else { //do something for duplicate list.Add(ids[i]); //add this, be … Read more