After a couple of tryouts I just achieved to solve it: tuple_1 = (‘[email protected]’, ‘asdf’) tuple_2 = () for elem in [item for item in tuple_1 if ‘@’ in item]: tuple_2 = tuple_2 + (elem,) print tuple_2 I hope this is what you need! I’m voting you up, since it was a little bit of … Read more
You forgot to call the conversion function for some parameter in your function. I tested and corrected your code, call it this way: is_verified = verified( convert(data[‘k_signer’]), data[‘d_pk’], convert(data[‘d_signer’]), data[‘sig’], convert(data[‘addr’]), convert(data[‘seed’]), convert(data[‘data’]) ) solved How can i fix concatenate tuple (not “list”) to tuple
As suggested in comments, you could use itertools.groupby to subdivide the tuple into “not a separator” and “separator” groups and then pick those groups that are not separators. This works for arbitrary numbers of segments, but can also be unpacked into two variables if you know to have exactly two groups. >>> a = (‘a’, … Read more
Are you looking for this? var tupleList = new List<Tuple<string, string>>(); for (int i = 0; i < data.Count; i++) { for (int j = i + 1; j < data.Count; j++) { tupleList.Add(new Tuple<string, string>(data[i], data[j])); } } 1 solved Combine elements of a list [closed]
The problem is that when you sort the GPAs, they’re no longer associated with the name ordering – you can simply skip doing so and the list indicies will stay correct or bring them into some collection (the instructions actually specify a tuple) # starting values scores_GPA = [3.85, 4.89, 2.89, 1.02, 3.8, 3.7, 2.9, … Read more
t = list(t) list(t) returns a new list while keeping t as a tuple. Think about a case you want to have both tuple and list. t2 = list(t) t is still a tuple while t2 is now a list. solved Permanently converting tuples to lists in Python [closed]
Hoo boy, this was a big XY problem. You want to sort by the third character of the second element of each tuple. Use the sorted built-in with its kwarg key. lst = [(‘abc’, ‘bcd’), (‘abc’, ‘zza’)] result = sorted(lst, key=lambda t: t[1][2]) key here accepts a function that is given each element in turn, … Read more
If time ends with – b then you could use normal str.split(“- b”) to get parts. And you would have to run it in loop results = [] for line in all_lines: parts = line.split(‘ – b’) results.append( parts ) or if you want to modify time or data results = [] for line in … Read more
you can use basic for loop and if statement to check values: List_1 = [((1.1, 2, 3), (1.1, 2, 3, 4), (3, 4, 5), 5, 6, 7)] List_2 = [((1.1, 2, 3), (1.1, 2, 3, 4), (3, 4.4, 5), 5, 6, 7)] List_1 = list(List_1[0]) # [(1.1, 2, 3), (1.1, 2, 3, 4), (3, 4, … Read more
Writing a function to print letters of a string according to their frequency compalsarily using dictionary and tuple [closed] solved Writing a function to print letters of a string according to their frequency compalsarily using dictionary and tuple [closed]