Introduction This question is about finding the distance between two specific words in a String. This can be done by using a combination of the String.indexOf() and String.substring() methods. The indexOf() method will return the index of the first occurrence of the specified word in the String, and the substring() method will return the part … Read more
Introduction If you are looking for the most efficient way to get the smallest list, then you have come to the right place. In this article, we will discuss the various methods that can be used to get the smallest list possible. We will discuss the advantages and disadvantages of each method, as well as … Read more
titlelist is not initialized. You need to initialize it prior to assigning Strings to it : String[] titlelist = new String[titles.size()]; // assuming Elements has a size() method 1 solved I pass a string -> NullPointerException [duplicate]
Introduction Analysis complexity is an important concept in computer science, as it helps to determine the efficiency of algorithms. In particular, the analysis of complexity in a for inside for loop is important, as the complexity of the second for loop depends on the first one. This article will discuss the analysis of complexity in … Read more
Introduction If you are getting an erroneous output when running a program, it can be a frustrating experience. It can be difficult to determine the cause of the problem and even more difficult to find a solution. This article will provide an overview of the most common causes of erroneous output and provide tips on … Read more
You have to instanciate current class, use this code: public static void main(String[] args) { A a = new A(); int value = a.abc(); } 2 solved How to call a behavioral method from main method in java?
For code like if(a==1) {do1();} else if(a==2) {do2();} else if(a==3) {do2();} else if(a==4) {do2();} else { doOther(); } Equal code will be switch(a) { case 1: do1(); break; case 2: do2(); break; case 3: do3(); break; case 4: do4(); break; default: doOther(); break; } 2 solved Java replace if else with switch
Introduction This tutorial will provide a step-by-step guide on how to create a loop in a program that will continue until the user types in the word “Stop”. This is a useful technique for creating interactive programs that allow the user to control the flow of the program. We will be using a while loop … Read more
A few pieces of information that might help when looking at code like this: Calling an object or class as a function calls the appropriate apply method if there is one Parentheses are often optional so another way to rewrite the code above would be: val route = HttpService.apply({ case GET -> Root / “hello” … Read more
Introduction This question is a duplicate of a previously asked question. The question is about a NullPointerException that is thrown when a string is passed. This type of exception is thrown when a program attempts to use an object reference that has not been initialized. In this case, the string that is being passed is … Read more
Imagine you wrote such function: public static int square(int x) { pow(x, 2); return x; } It will compute the square of x. But then computed square will not affect anything and the function will return just x. Now look carefully at your code if (i == 5){ return i; } else { something(i + … Read more
Here’s a pseudo-code for you count = 1 begin for : if(condition) increment count by 1 // do something… if (increment > 5) // do something… break //or return else // do something… break //or return end of for EDIT: Use break in your else block. The break statement breaks out of the closest loop. … Read more
Introduction Calling a behavioral method from the main method in Java is a common task for many Java developers. It is a simple process that can be done with a few lines of code. In this article, we will discuss how to call a behavioral method from the main method in Java. We will also … Read more
This is your solution : public class NewMain { public static void main(String args[]) throws ParseException { Scanner s = new Scanner(System.in); char yes; do { System.out.println(“Hi”); yes = s.next().charAt(0); } while (yes == ‘Y’); // if u enter ‘Y’ the it will continue } } To exit enter any thing other then ‘Y’ 0 … Read more
I hope I’ve understood correctly what you wanted to ask. First of all as it was already mentioned you can’t store integers in String array. Secondly, in Java two-dimensional array is actually the array of arrays. So when you declare int[][] nums = int[4][3] you create an int[] array nums that has four elemets and … Read more