[Solved] Filter element in array of doubles

The for-loop solution should be the easiest, as you can use the Math.floor function to get the start of your desired list: for (double d = Math.floor(start); d <= Math.ceil(end); d += 1.0) list.add(d); 13 solved Filter element in array of doubles

[Solved] How to Split text by Numbers and Group of words

you can try splitting using this regex ([\d,]+|[a-zA-Z]+ *[a-zA-Z]*) //note the spacing between + and *. [0-9,]+ // will search for one or more digits and commas [a-zA-Z]+ [a-zA-Z] // will search for a word, followed by a space(if any) followed by another word(if any). String regEx = “[0-9,]+|[a-zA-Z]+ *[a-zA-Z]*”; you use them like this … Read more

[Solved] Why does Java and Javascript Math.round(-1.5) to -1?

Rounding mode to round towards negative infinity. If the result is positive, behave as for RoundingMode.DOWN; if negative, behave as for RoundingMode.UP. Note that this rounding mode never increases the calculated value. It is just matter of whole number and its position against number chart. From here you can see javadocs. public static int round(float … Read more

[Solved] Create a PDF file in memory

this solution, using itext, primefaces media. <p:dataTable widgetVar=”tb1″ id=”tablaFact” var=”item” selection=”#{listadoFacturasMB.selectedFactura}” selectionMode=”single” paginator=”true” rows=”20″ rowKey=”#{item.idFactura}” value=”#{listadoFacturasMB.facturaUtilList}”> <p:ajax event=”rowSelect” update=”:frm1:growl :frm1:dialog” oncomplete=”PF(‘servDialog’).show()” listener=”#{listadoFacturasMB.createPDF}”/> <f:facet name=”header”> <h:outputText value=”Listado de facturas (Cantidad: #{listadoFacturasMB.cantFact})”/> </f:facet> <p:column style=”width:10%” headerText=”Nro” sortBy=”noFactura” filterFunction=”#{utilMB.filterByName}” filterBy=”noFactura” filterMatchMode=”contains”> <h:outputText value=”#{item.noFactura}”/> </p:column> </p:dataTable> <p:dialog resizable=”false” closeOnEscape=”true” appendTo=”@(body)” modal=”true” id=”dialog” header=”Detalles de la factura” widgetVar=”servDialog” width=”1000px” height=”630px”> … Read more

[Solved] Using Android Studio, how can I create a value which will increase its value by 1 every time a button is clicked? [closed]

you need to add a button to your .xml file like this : <Button android:layout_width=”match_parent” android:layout_height=”wrap_content” android:text=”Goal” android:layout_margin=”8dp” android:onClick=”add1ForTeamA” android:id=”@+id/Three_Button_B”/> then if you will notice that the android:onclick has been set to the add1ForTeamA method. Go to the mainActivity.java file and add this method `public void addOneForTeamA(View view) { scoreTeamA = scoreTeamA + 1; displayForTeamA(scoreTeamA); … Read more

[Solved] The compareToIgnoreCase method in Java

Comparisons are similar to the ordering that one might find in a dictionary. The return of this method is an int which can be interpreted as follows: returns < 0 then the String calling the method is lexicographically first (comes first in a dictionary) returns == 0 then the two strings are lexicographically equivalent returns … Read more

[Solved] Date Parsing Operation Crashes Server

The reason that my server keeps crashing is because it runs out of memory. (From: @Jon Skeet) The fact that you’re looping over a collection and conditionally adding to it looks suspect to me. It’s possible that it’s just looping forever, because it adds an item, then finds that item and adds another, then adds … Read more

[Solved] Parenthesis/Brackets Matching using Stack algorithm

Your code has some confusion in its handling of the ‘{‘ and ‘}’ characters. It should be entirely parallel to how you handle ‘(‘ and ‘)’. This code, modified slightly from yours, seems to work properly: public static boolean isParenthesisMatch(String str) { if (str.charAt(0) == ‘{‘) return false; Stack<Character> stack = new Stack<Character>(); char c; … Read more

[Solved] Reading text files in java

I don’t see much here which really surprises me. Most likely, the end of the file gets reached in your while loop with the first call to Scanner#nextLine(). Then, you make a second call which throws the exception since there is no more content to read. while (reader.hasNextLine()) { // during the last iteration, this … Read more