I solved this problem in this way: @Root(name = “images”) public class Images { @ElementList(entry = “image”, required=false, inline = true) private List<String> imageList; public List<String> getImageList() { return imageList; } } solved Java, Simple XML parsing list
UPDATE FOR THE NEW CLEARER QUESTION: It sees now that I should have added more text to my question. I wanted to know what would be the sequence of execution in case both these statements(1 and 2) are in one single class for the same variable ? You are interessted something like this: private class … Read more
There are two ways to look at this: Integer.toBinaryString(n) produces a string of length ceiling(log2(n)). That computation will take time that is roughly proportional to log(n). The maximum value for n is 2^31 – 1, and that computation will always take less than some fixed constant time. In fact, the question of the big O … Read more
The following block should generate the series as you described it. int numberOfLines = 4; int numberOfDigitsPerLine = 5; for (int i=1; i<numberOfLines+1; i++){ for(int j=1; j<=numberOfDigitsPerLine; j++) { if(j>=i) { System.out.print(j); } else { System.out.print(i); } } System.out.println(); } Change numberOfLines and numberOfDigitsPerLine as necessary. Elaboration: First you must analyze the series, by the … Read more
First, Java is not Python (although Jython implements Python in Java). Second, you should read the JavaDoc on ArrayList – that is it throws an Exception, IndexOutOfBoundsException – if the index is out of range (index < 0 || index >= size()) Finally, you can do this myList.get(myList.size() – 1); to get this last element … Read more
Keep track of the number of bytes you’re writing, and when it reaches a specified point, close the existing file and continue in a new one. There’s no need to analyze the size of the file, since you know exactly what’s going into it. Something like this: long fileSizeByteLimit = 5000000; long bytesOutput = 0; … Read more
I suppose you have an ArrayList of ArrayLists, then you can do this to retrieve number of “columns”: list.get(0).size() It means get the first ArrayList from list and get it’s size. solved Number of column in a two dimensional ArrayList
This is not because of the complier. It is happening because you are doing i /= 10; //slice end So when you do 13.4 after the first run it wont give you 1.34 it will give you something like 1.339999999999999999 which is 1.34. Check Retain precision with double in Java for more details. If you … Read more
You probably get a compiler error in this (and the next ones) line: if(int card[] = 0) int card[] is an array, which is eventually an Object, and you are trying to assign to it a primitive value… which won’t work. Besides, it looks like you are trying to compare something, which rather uses ==, … Read more
It seems you have written the “new” Keyword with a capital letter. Try Clerck object = new Clerck(); instead. 2 solved Making Objects In main Class [closed]
Save code in file. Get it’s absolute Path. Use Process myProcess = Runtime.getRuntime().exec(command); to compile and run your code. You can also redirect Errors/Warnings to diff files. solved How to run an application in an interface? [closed]
MyClass and MyObj are the wrong way around, it should be: MyClass MyObj = new MyClass(); Otherwise you are trying to declare an instance of MyObj which doesn’t exist. Instead you declare an instance of MyClass and name this MyObj. Hopefully that makes sense to you 🙂 solved Defining Proper Classes with Java [closed]
To get a working recursive solution you need a base case, for example a == 0, and then work yourself down towards the base case by recursively calling yourself. The solution for question 1 could be something along the lines of this, that decreases the a argument until it reaches 0: int multiply(int a, int … Read more
Let’s debug this a little, add a few system outs… this is what you would see for each step 100.0 – 5.0 95.0 + 10.0 105.0 + 13.0 118.0 your value array is {100,5,10,13} and your operator array is {-,+,+} you have not mapped a = 100, b = 5, c= 10, d = 13, … Read more
A first step will be to convert the time in HH:MM:SS format (which is how your string is formatted) to that of seconds as per the following: String timerStop1 = String.format(“%02d”, hours) + “:” + String.format(“%02d”, minutes) + “:” + String.format(“%02d”, seconds); String[] timef=timerStop1.split(“:”); int hour=Integer.parseInt(timef[0]); int minute=Integer.parseInt(timef[1]); int second=Integer.parseInt(timef[2]); int temp; temp = second … Read more