[Solved] Correct printf formats for double numbers in C

%e specifier is used to print value of float\double in exponential format. So here %1.4e will print 1 digit before the decimal point and 4 digits after the decimal point. So if bmax=12.242 then the output will be 1.2242e+01. 3 solved Correct printf formats for double numbers in C

[Solved] Ask user to repeat the program or exit in C

int main(void) { float x,y,sum; char ch; do { printf (“Enter the first number:”); scanf (“%f”,&x); printf (“Enter the second number:”); scanf (“%f”,&y); sum=x+y; printf (“The total number is:%f\n”,sum); printf (“Do you want to repeat the operation Y/N: “); scanf (” %c”, &ch); } while (ch == ‘y’ || ch == ‘Y’); } This uses … Read more

[Solved] Convert binary, octal, decimal and hexadecimal values between each other in BASH / Shell [duplicate]

Convert binary, octal, decimal and hexadecimal values between each other in BASH with bc and printf Some relevant Q&A: Understand “ibase” and “obase” in case of conversions with bc? TL;DR: ibase and obase params order matters, but not always. Hex values must be in UPPERCASE. Convert a character from and to its decimal, binary, octal, … Read more

[Solved] Printing Array in struct

You can’t print the two values by using x[i]. You must print them one-by-one. You probably want something like: for (i=0;i<12;i++) { printf(“\t index %d value %f, %f \n\r”,i, x[i].a, x[i].b); } 1 solved Printing Array in struct

[Solved] Why is the & operator used after using scanf? [closed]

You have declared string as a single character but you fill it with a string. This invokes undefined behavior. You should change your code to : char string [20] = “default”; //20 is random, you should use the maximum length of the input you may have printf(“The default String is: %19s”, string); scanf(“%s”, string); printf(“You … Read more

[Solved] printf() function in C

Read the printf spec: First format string, then parameters. #include <stdio.h> int main(){ long mn = 166662; printf(“Howdy, I am %ld i hope that you had a better better day than I am having.\n”, mn ); return 0; } 2 solved printf() function in C

[Solved] a is a double, printf(“%d”, a); works differently in IA32 and IA32-64 [closed]

%d actually is used for printing int. Historically the d stood for “decimal”, to contrast with o for octal and x for hexadecimal. For printing double you should use %e, %f or %g. Using the wrong format specifier causes undefined behaviour which means anything may happen, including unexpected results. 5 solved a is a double, … Read more

[Solved] Does printf alter variables?

The output will be 1. Your expression ++x will be x = x+1; In both the printf() you get 1 So the value of x is modified with the pre-increment operator here and in printf() in the second line prints the new value of x which is 1 printf() just prints the value of x … Read more

[Solved] Need to understand printf functioning deeply

Would make sense if you knew a li’l bit about awk. Anyways what happens here is that the * is replaced by the numbers you’ve given (-5 and 4 respectively), which means printf(“%*.*s”,-5, 4, s+3); would change to printf(“%-5.4s”, s+3); 0 solved Need to understand printf functioning deeply

[Solved] Printf spaces if number < 10 using only printf [duplicate]

printf(“%2d”, yournumber) will print number with 2 characters. If number is less than 2 chars long, spaces will be included before number. In case number is bigger than 2 digits, modifier has no effect and entire number will be printed. printf(“%2d”, 1); // ” 1″ printf(“%2d”, 10); // “10” printf(“%2d”, 100); // “100” 4 solved … Read more