I suggest you to read the javadoc of String.split. I think that you misunderstood the concept when you did this: String[] f=line.split(“,”); a[count]=Integer.parseInt(f[2]); //–> java.lang.NumberFormatException here! Avoid using ‘magic’ numbers in your code like int[] a = new int[24];. Why 24? Well, here comes a version that do what you want to do. Maybe it … Read more
Convert binary, octal, decimal and hexadecimal values between each other in BASH with bc and printf Some relevant Q&A: Understand “ibase” and “obase” in case of conversions with bc? TL;DR: ibase and obase params order matters, but not always. Hex values must be in UPPERCASE. Convert a character from and to its decimal, binary, octal, … Read more
Define a struct with all the correct types and order. Point the struct to the data. Then just access the items via the struct elements. Be careful with the types, it is probably best to use well defined types such as int8_t, uint8_t, uint16_t, int16_t, etc to insure the correct element size. You will want … Read more
Not very hard, all you need is a loop and a cast to make sure your numbers are unsigned for (int i = 0; i < 16; ++i) printf(“%02X”, (unsigned char)data[i]); 4 solved Extracting hex numbers from char array [closed]
#include <stdio.h> void flipme(char *buf, const char *inBuf) { int x; sscanf(inBuf, “%x”, &x); x ^= 1 << 17; sprintf(buf, “%06X”, x); } int main(void) { char buf[16]; flipme(buf, “002A05”); printf(“002A05->%s\n”, buf); flipme(buf, “ABCDEF”); printf(“ABCDEF->%s\n”, buf); } Output: 002A05->022A05 ABCDEF->A9CDEF You wrote: I tried converting hex string to integer via strtol, but that function strip … Read more
string temp = “aaff4455”; string temp2 = “”; int size = temp.Length; for (int i = 0; i < size; i += 2) { temp2 += temp.Substring(i, 2); if ((i+2) < size) temp2 += “,”; } 5 solved Convert a Hex String to comma separated Hex String c#
Big or little endianness defines how to interpret a sequence of bytes longer than one byte and how to store those in memory. Wikipedia will help you with that. I was really just looking to understand how 0x0300020 when read 2 bytes at a time and reprinted yields 0 1 2. You don’t read 2 … Read more
Technically, no. But why are you using htons? It changes the endianess of a 16 bit datum to big-endian (that is, network byte order). First is your variable not 16 bit but 32 bit, so uint16_t acc = 0xBBD1 would be more appropriate. Second, as your on a little-endian machine, the bytes are exchanged, hence … Read more
You’ve converted the binary content to a string when you copied it from Wireshark. The result is a string that represents the binary data in a hex Format. Instead of revers the convertion you should use an appropriate methop to copy the data. Try Wireshark’s feature “follow XXX stream” and take the “C Arrays” representation, … Read more
They seem to be HTML entities, but they are not complete, they should end with ‘;’ So the code should read: јυѕt The characters you see are: &#1112; CYRILLIC SMALL LETTER JE &#965; GREEK SMALL YPSILON &#1109; CYRILLIC SMALL LETTER DZE t a normal t In your browser it look almost like ‘just’ For a … Read more
You have to initialize a new NSString object using the right format specifier. Like : int i = 9; NSString *octalString = [NSString stringWithFormat:@”%o”, i]; // %O works too. This will create an autoreleased NSString object containing octal string representation of i. In case you start from a NSString containing a decimal number representation, you … Read more
Its really some binary information and If you have clearly read out the product manual then it says formation of this binaries. Converting the data to hex will give something like this.. 24-41-20-20-67-72-51-30-35-41-68-40-91-29-3F-3F-3F-FF-FF-FB-FF-FF-3F-3F- And then you need to refer the manual for exact meaning of these hex numbers ex–(in some chinese devices) 2 bytes(24), stand … Read more
Try this : for dec_ldev in range(0,16777215): hex_ldev = hex(dec_ldev)[2:].zfill(6) print(“{}{}{}:{}{}:{}{}”.format(”,*hex_ldev)) 1 solved Generate a range of hex numbers in format [duplicate]
If you have control of your input format, i.e. you can guarantee it will always be something like 0xabc, then you can try: const char input[] = “0xabc”; uint32_t tmp; sscanf(input, “0x%x”, &tmp); struct cmd cmdid; cmdid.a = (tmp & 0xFF0000U) >> 16; cmdid.b = (tmp & 0xFF00U) >> 8; cmdid.c = (tmp & 0xFFU); … Read more
Either use real encryption and decryption between your source and destination (implementation will vary depending on how you are sending the data) or just obfuscate a bit by adding a known value to the hex that is ‘only’ known by the source and destination (probably best to modulo this by 127) – essentially this is … Read more