I have done lot of research over web, but I got solution from one Expert. Date getDateFrmString(String dDate) { java.sql.Date dDate = new java.sql.Date(new SimpleDateFormat(“yyyy-MM-dd”).parse(sDate).getTime()); return dDate; } this is what I want. solved Create a function that takes string object and returns Date object in dd-MM-yyyy format [duplicate]
How about something like this? It would only handle one specific format but the regex can be adjusted for other formats. Regex rg = new Regex(@”[01]?\d[/-][0123]?\d[/-]\d{2}”); Match m = rg.Match(string); m.ToString(); Here is a question with a bunch of date regexes that may help. Regular Expression to match valid dates solved Extract a date from … Read more
with DB query fetch the values so that you get something like $blacklist = array(’18:00′,’19:00′) check for time being black-listed with if(!in_array(’18:00′, $blacklist)){…} if you have white-listed values as array, and you don’t want to check in viewing part, then its better to use array_diff as @YaK answered solved Print all times, except the ones … Read more
The “basic” regex matching just the year field is \d{4} but it is not enough. We must prohibit that before the year occurs: 3 letters (month) and a space, then 2 digits (day) and a space. This can be achieved with negative lookbehind: (?<!\w{3} \d{2} ) But note that: after the day field there can … Read more
Update: It would appear that it is a bug in Xcode. Trying your code in the viewDidLoad and setting a breakpoint causes the lldb description of the date to be nil, however it correctly prints the expected value out. You can see more about the bug at this SO post, thanks to OOPer for the … Read more
This is due to the format you used as “yyyy-MM-DD”. The parser will parse in the sequence way: Your input value is “2018-03-08” yyyy – will bring to the year 2018 MM – will bring to the month MARCH But what is DD? It’s the number of the days from the beginning of the year. … Read more
First convert your Date in to specific Date format using SimpleDateFormat Use SimpleDateFormat simpleDateFormat = new SimpleDateFormat(“EEEE”); to get Day name in week WHERE EEEE -> Day name in week SAMPLE CODE SimpleDateFormat inFormat = new SimpleDateFormat(“dd-MM-yyyy”); try { Date myDate = inFormat.parse(date+”-“+month+”-“+year); SimpleDateFormat simpleDateFormat = new SimpleDateFormat(“EEEE”); String dayName=simpleDateFormat.format(myDate); } catch (ParseException e) { … Read more
DateTime.Now would give you current time for your time zone. DateTime.UtcNow gives you current date and time on this computer, expressed as the Coordinated Universal Time (UTC). solved How do I get the correct time in C#
Ok I finally found it. On the x axis I wanted to plot dates either as POSIXct or as number of day of recording (integer). On the y axis I wanted the time of day so that the graph would present a dark bar on each day (x-axis) and between the time (y-axis) that the … Read more
EDIT#1: If the value ‘42248’ has somehow gotten into A1, then in another cell enter: =–TEXT(A1,”d.m”) to retrieve the 1.9 5 solved Regain an original fractional numeric value that Excel has transformed to a date value
function getWeekNumber(thisDate) { var dt = new Date(thisDate); var thisDay = dt.getDate(); var newDate = dt; newDate.setDate(1); // first day of month var digit = newDate.getDay(); var Q = (thisDay + digit) / 7; var R = (thisDay + digit) % 7; if (R !== 0) return Math.ceil(Q); else return Q;} getWeekNumber(“07/31/2016”); 1 solved How … Read more
This function should be very close to what you want. I’ve tested it in both Python 2.7.9 and 3.4.2. The initial version I posted had some problems because — as I mention then — it was untested. I’m not sure if you’re using Python 2 or 3, but this worked properly in either one. Another … Read more
if you’re facing the problem of converting a human readable date to numeric values you have to reconsider your design. Your code should work only with 32 or 64 bit epoch values (seconds since 1st January 1970) and then convert them into the appropriate format only when needed. In any case, just do this: $time … Read more
So I got following code that works for me: public void setOverdueFlagIfRequired(Date today, Date causedAtDate) { Calendar now = Calendar.getInstance(); now.setTime(today); Calendar causedAt = Calendar.getInstance(); causedAt.setTime(causedAtDate); Calendar yesterday2300 = Calendar.getInstance(); yesterday2300.setTime(today); yesterday2300.add(Calendar.DATE, -1); yesterday2300.set(Calendar.HOUR_OF_DAY, 23); yesterday2300.set(Calendar.MINUTE, 0); yesterday2300.set(Calendar.SECOND, 0); yesterday2300.set(Calendar.MILLISECOND, 0); Calendar fiveDaysBack2300 = Calendar.getInstance(); fiveDaysBack2300.setTime(yesterday2300.getTime()); fiveDaysBack2300.add(Calendar.DATE, -4); if (causedAt.compareTo(fiveDaysBack2300)<=0) { setFiveDaysOverdue(true); } else if … Read more
try this: string todayDate = DateTime.Today.ToString(“yyyyMMdd”) 0 solved How to retrieve date without time in the yyyymmdd format in C# [closed]