Easy one: $today = date(‘l’); // returns Sunday When you want it to do like your image, you should get your date from the dropdown. Then do the following: $date=”2017-7-27 10:51:10″; // example date var_dump(date(‘l’, strtotime($date))); // returns Sunday Goodluck! 2 solved Display which day it is? sunday or monday “php coding”? [closed]
Here is a nice post: http://nickstips.wordpress.com/2010/02/12/c-get-nist-internet-time/ It describes in very detail how to achieve what you want 🙂 solved is there a way ti get Date\time values Online? [closed]
TL;DR: You’re right to be concerned about the use of the system local time zone, but you should have been concerned earlier in the process, when you used the system local time zone to construct a Date in the first place. If you just want the formatted string to have the same components that Date.getDate(), … Read more
I would use the DateTimeFormatter for this. You can find more information in the docs. https://docs.oracle.com/javase/8/docs/api/java/time/format/DateTimeFormatter.html However, here an example: DateTimeFormatter parser = DateTimeFormatter.ofPattern(“EEE MMM dd HH:mm:ss zzz yyyy”, Locale.US); LocalDateTime date = LocalDateTime.parse(“Sun Apr 01 01:00:00 EEST 2018”, parser); DateTimeFormatter formatter = DateTimeFormatter.ofPattern(“dd-MM-yyyy HH:mm:ss”); System.out.println(formatter.format(date)); //01-04-2018 01:00:00 The Locale.US part is required even if … Read more
It’s quite simple, create a new date, get the day and the year increase them and return a new date with the new values. This is a DEMO returning a date increased with one day and one year from the current one. var date = new Date(); document.write(date); var month = date.getMonth()+1; var day = … Read more
So by just creating a quick rdd in the format of the csv-file you describe val list = sc.parallelize(List((“1″,”Timothy”,”04/02/2015″,”100″,”TV”), (“1″,”Timothy”,”04/03/2015″,”10″,”Book”), (“1″,”Timothy”,”04/03/2015″,”20″,”Book”), (“1″,”Timothy”,”04/05/2015″,”10″,”Book”),(“2″,”Ursula”,”04/02/2015″,”100″,”TV”))) And then running import java.time.LocalDate import java.time.format.DateTimeFormatter val startDate = LocalDate.of(2015,1,4) val endDate = LocalDate.of(2015,4,5) val result = list .filter{case(_,_,date,_,_) => { val localDate = LocalDate.parse(date, DateTimeFormatter.ofPattern(“MM/dd/yyyy”)) localDate.isAfter(startDate) && localDate.isBefore(endDate)}} .map{case(id, _, _, … Read more
Use the modern Java date and time classes for everything that has got to do with dates or times. DateTimeFormatter usFormatter = DateTimeFormatter.ofLocalizedDate(FormatStyle.SHORT) .withLocale(Locale.US); System.out.println(date.format(usFormatter)); DateTimeFormatter deFormatter = DateTimeFormatter.ofLocalizedDate(FormatStyle.SHORT) .withLocale(Locale.GERMANY); System.out.println(date.format(deFormatter)); This will print something like 6/27/17 27.06.17 It’s not exactly the formats you asked for, but it’s the formats Java thinks are appropriate for … Read more
Calendar calendar = Calendar.getInstance(); int lastDay = calendar.getActualMaximum(Calendar.DAY_OF_MONTH); int currentDay = calendar.get(Calendar.DAY_OF_MONTH); int daysLeft = lastDay – currentDay; System.out.println(“Last Day: ” + lastDay); System.out.println(“Current Day : ” + currentDay); System.out.println(“There are ” + daysLeft + ” days left in the month.”); output Last Day: 30 Current Day : 1 There are 29 days left in … Read more
How to gather timezone of operating system from Oracle database in string format? (Migrate/convert date to ts with tz) solved How to gather timezone of operating system from Oracle database in string format? (Migrate/convert date to ts with tz)
Use dateutil.parser.parse() parse the date string into a timezone aware datetime object, then use strftime() to get the format you want. For better explanation goto solved How to convert datetime string to another format [duplicate]
Assuming that 2013-2014 is a valid format, this might be a function that works: public static bool IsSchoolYearFormat(string format, int minYear, int maxYear) { string[] parts = format.Trim().Split(new[] { ‘-‘ }, StringSplitOptions.RemoveEmptyEntries); if (parts.Length == 2) { int fromYear; int toYear; if (int.TryParse(parts[0], out fromYear) && int.TryParse(parts[1], out toYear)) { if (fromYear >= minYear && … Read more
using php try like this $month=”JAN-2014″; echo date(‘m’, strtotime($month)); 1 solved How to get month in number from date in “JAN-2014” format?
Here is a simple function to do that //birthday YYYY-MM-DD function userInfo($fname, $lname, $birthday) { //Calc age $age = date_diff(date_create($birthday), date_create(‘today’))->y; return $fname .” “. $lname . ” “.$age; } now call it echo userInfo(‘John’, ‘Doe’, ‘1986-02-01’); 1 solved PHP Date issues [duplicate]
Kindly go through following R console code snippet: > dates <- c(“10/23/16”, “10/24/16”) > dates [1] “10/23/16” “10/24/16” > Dates <- as.Date(dates, + format = “%m/%d/%y”) > Dates [1] “2016-10-23” “2016-10-24″ Hope it works for you! solved Fix incomplete character string for year “2016” from “0016” in R [closed]
This is nice and easy using strtotime strtotime(‘next friday’); See strtotime() 1 solved What date of next Friday?