date-parsing

[Solved] How to format the given date “31.12.9999” in the format “yyyy/MM/dd HH:mm:ss”

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Please try below i mentioned date format code,I hope it will help you, From this, String inputDate = “31.12.9999”; SimpleDateFormat dateFormatter = new SimpleDateFormat(“yyyy.MM.dd HH:mm:ss”); Date toDate = dateFormatter.parse(inputDate); To Change: Date date = new SimpleDateFormat(“dd.MM.yyyy”).parse(“31.12.9999”); String formattedDate = new SimpleDateFormat(“yyyy.MM.dd HH:mm:ss”).format(date); System.out.println(“formattedDate :: ” + formattedDate); Thanks,. 2 solved How to format the given … Read more

[Solved] Exception on Date parsing android [duplicate]

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Your date format MM/dd/yyyy’T’HH:mm:ss which your using is incorrect 1/31/2018 8:58:12 AM +00:00 and return different value from expected. SimpleDateFormat sdf = new SimpleDateFormat(“MM/dd/yyyy’T’HH:mm:ss”); return 1/31/2018T8:58:12 And you are trying to pass below 1/31/2018 8:58:12 AM +00:00 1 solved Exception on Date parsing android [duplicate]

[Solved] How to convert dd/MM/yyyy string to MM-dd-YYYY DateTime int C#

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I suggest you use explicit formats in your case, you can do that by using ParseExact to get the DateTime object and then providing the desired format to the ToString overload: string date = “15/01/2017”; DateTime date1 = DateTime.ParseExact(date, “dd/MM/yyyy”, CultureInfo.CurrentCulture); btnBack.Text = date1.ToString(“MM-dd-yyyy”); solved How to convert dd/MM/yyyy string to MM-dd-YYYY DateTime int C#

[Solved] java.lang.NumberFormatException: For input string: “2019-11-27”

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LocalDate and ThreeTenABP String dateString = “2019-11-27”; LocalDate date = LocalDate.parse(dateString); int epochDay = (int) date.toEpochDay(); System.out.println(epochDay); This snippet outputs: 18227 The documentation explains: The Epoch Day count is a simple incrementing count of days where day 0 is 1970-01-01 (ISO). So my suggestion is that this number is fine for feeding into your BarEntry … Read more