You have to changes the format for working in both case: var isoDate = “2018-10-31” let dateFormatter = DateFormatter() dateFormatter.dateFormat = “yyyy-MM-dd” print(dateFormatter.date(from: isoDate)!) isoDate = “2016-04-14T10:44:00+0000” dateFormatter.dateFormat = “yyyy’-‘MM’-‘dd’T’HH’:’mm’:’ssZZZ” print(dateFormatter.date(from: isoDate)!) solved Format string to date format swift [closed]
The main problem with your format is that Python does not support anything more granular than microseconds, as explained here. In fact, assuming you have 000 as the last three decimals of seconds, you can use the format below. from datetime import datetime datetime_object = datetime.strptime(’24/NOV/18 05:15:00.000000000 AM’, ‘%d/%b/%y %I:%M:%S.%f000 %p’) If you cannot make … Read more
Introduction Converting a 12 hour string into a 24 hour datetime can be a tricky task. Fortunately, there are a few methods that can be used to make this conversion. In this article, we will discuss the different methods that can be used to convert a 12 hour string into a 24 hour datetime. We … Read more
public DateTime GetLastDayOfMonth(int year, int month) { month += 1; if (month>12) { month = 1; } return new DateTime(year, month, 1).AddDays(-1); } solved C# DateTime The last 1 days of each month [closed]
So using datetime you can actually get the minutes like this: from datetime import datetime time = datetime.now() minutes = time.minute Or in one line: from datetime import datetime minutes = datetime.now().minute Now that you have the minutes, the if statement can be simplified down, because you don’t look at the hour. if minutes == … Read more
string timeString = “20150828020000UTC”; IFormatProvider culture = new CultureInfo(“en-US”, true); DateTime dateVal = DateTime.ParseExact(timeString, “yyyyMMddHHmmss’UTC'”, culture); 2 solved How to parse date YYYYMMDDHHMMSSUTC [closed]
This is an overly simplified example of what you could do, using only .NET classes: public static string TimeSinceEvent(DateTime eventTime) { TimeSpan timeSince = DateTine.Now – eventTime; if (timeSince.Hours > 0) return string.Format(“Added {0} hours ago”, timeSince.Hours); else if (timeSince.Minutes > 0) return string.Format(“Added {0} minutes ago”, timeSince.Minutes); else return string.Format(“Added {0} seconds ago”, timeSince.Seconds); … Read more
This should do it: int untilNextQuarter = 4 – (currentMonth % 3); Or a slightly clearer but slightly less efficient approach: int[] remainingMonths = new[] { 3, 2, 4 }; int untilNextQuarter = remainingMonths[(currentMonth – 1) % 3]; solved In C#, is there any more elegant way to take a DateTime and calculate how many … Read more
To get the first day of the month, you could make use of DateTime class methods and properties alone. DateTime dt = DateTime.Now; //change this to any date you want DateTime firstDayOfMonth = dt.AddDays(1-dt.Day); //the trick is here, minus the DatetTime by the current day (of month) + 1, you necessarily get the first day … Read more
Your question seems terribly inconsistent, but it appears that you have the completely wrong approach. To have expiring items, you do not manually deactivate them when the expiry date comes or something like that. You simply have the expiry date as part of the item (say, a column in your database) and you select items … Read more
List<Date> date = new ArrayList<Date>(); date.add(new Date()); ez or date.add(user.getDate()); solved How to add date in ArrayList of “Date” data type? [closed]
If you want to use php, you would do something like… <input type=”hidden” name=”datetime” value=”<?php echo $arrivalString; ?>” /> inside your form. 2 solved timestamp within a form [closed]
As MySql have YYYY-MM-DD HH:II:SS format you can achieve it using DateTime function of PHP as $date = DateTime::createFromFormat(‘d M Y H:i:s:u’, ’13 Sep 2014 00:35:23:440′); echo $date->format(‘Y-m-d H:i:s’); DEMO 1 solved PHP DateTime supported formats
yyyy-MM-dd HH:mm:ss For example: DateTime.UtcNow.ToString(“yyyy-MM-dd HH:mm:ss”) 2 solved DateTime Format yyyy-mm-dd 24hr
from datetime import datetime date_data=”02012019 09:02:53″ data = datetime.strptime(date_data,’%d%m%Y %H:%M:%S’) result = data.strftime(‘%d-%m-%Y %H:%M:%S’) # output ’02-01-2019 09:02:53′ solved int to datetime in Python [duplicate]