I wouldn’t rely too much on the approach you posted in your answer. Use the following function instead: function index_of_one($dec) { // maximum precision is 15 $str = str_replace(‘.’,”,sprintf(‘%.15f’, $dec)); $pos = strpos($str, ‘1’); if ($pos === false) { return -1; } return ($pos + 1); } Example: $dec1 = 1.00000000; $dec2 = 0.10000000; $dec3 … Read more
You can use GroupBy: var voteGroups = Votes.GroupBy(s => s); Now, if you want to know the count of each string use Enumerable.Count: foreach(var voteGroup in voteGroups) Console.WriteLine(“Vote:{0} Count:{1}”, voteGroup.Key, voteGroup.Count()); Another way is using ToLookup: var voteLookup = Votes.ToLookup(s => s); foreach (var voteGroup in voteLookup) Console.WriteLine(“Vote:{0} Count:{1}”, voteGroup.Key, voteGroup.Count()); The lookup has it’s … Read more
Just switch name and count in your select select name,count(*) from db.db group by name order by name desc 1 solved count(*) column to the right of the data? [closed]
C++ Count type of characters (uppercase, lowercase, digits, special) WITHOUT if-else, ternary, or switch case. Any IDEA? [closed] solved C++ Count type of characters (uppercase, lowercase, digits, special) WITHOUT if-else, ternary, or switch case. Any IDEA? [closed]
Count(*) is most reliable becuase it gives correct count even when some rows are deleted from the table 1 solved use select count(*) everytime or save the count as a number directly
If I am reading your question right, the result table give you the age ID and Period, and then the count of toys per age ID and Period. Here is how you would write that query: SELECT Ages.ID, Ages.Period, IFNULL(sub.cnt,0) AS Count FROM Ages LEFT JOIN (SELECT Toys.age_id, COUNT(*) AS cnt FROM Toys GROUP BY … Read more
You say 10,000 but you write 1000, here is what I would do for 1000: if (counter % 1000 == 0) { //Do something. } For 10,000 do: if (counter % 10000 == 0) { //Do something. } solved ‘do something’ every time a counter increase of 1000 [closed]
Use this simple query: select count(*) as numCustomersFromSydney from table where Suburb = “Sydney”; solved Count number of times value appears in column in MySQL
SELECT Area, COUNT(Area) as Count FROM ftm_data GROUP BY Area order by Count DESC LIMIT 5 solved MySQL Query, Count Number of Rows with Same Value Limited to 5 Results
You can solve the problem by following the steps below like QBrute correctly pointed out. public String countMatches(String main) { //Create an array of the alphabets length main = main.toLowerCase(); int[] foundArray = new int[26]; String output = “”; //Create an alphabets array String[] alphabets = “a b c d e f g h i … Read more
You can write a state machine that should handle most cases. As you scan the file, you’ll be in one of the following states: TEXT – regular (non-commented) text; this is the state you’ll start in. Any newline seen in this state will cause the total-lines counter to be incremented. SAW_SLASH – You’ve seen a … Read more
I changed 2 things : while n > 1: instead of while n > 0: otherwise your loop never stops n=n//10 instead of n=n/10, where // is the euclidian division, which is what you need here You should try this : def testD(D,n): if D % 2 == 0: return 0 count = 0 while … Read more
Dont know what you mean there. But here is what I understand from your question <?php for ($i=0; $i< count($contentdinamit[“chart”][“songs”][“song”]); $i++ ) { if(($i+1)<=10){//limit your item by 10 echo'<li class=”up”><a href=”‘ .$contentdinamit[“chart”][“songs”][“song”][“$i”][“artist_name”].'”><strong>’ .$contentdinamit[“chart”][“songs”][“song”][“$i”][“song_name”].'</strong></a><br /><a href=”‘ .$contentdinamit[“chart”][“songs”][“song”][“$i”][“artist_name”].'”>’ .$contentdinamit[“chart”][“songs”][“song”][“$i”][“artist_name”].'</a></li>’; } } ?> 6 solved How to limit items from for loop?
Something like this: CREATE VIEW GetNumberOfStudentswithMajor AS SELECT COUNT(*) FROM dbo.Students where Major1 is not null and Major2 is not null solved Total count in sql
Here how I would do it using JavaScript. This code calculates words for whole table. If you need to run it for the row, you should modify it appropriately. var words = []; var uniqueWords = []; $(“td”).each(function(){ words.push($(this).text()) }); $(words).each(function(){ for(var i = 0; i < uniqueWords.length; i++){ var current = uniqueWords[i]; if(current.word.toString() == … Read more