[Solved] Switch statement in a C# calculator
[ad_1] check this and please don’t add pseudocode case “%”: textBox_Result.Text = (Double.Parse(textBox_Result.Text) * resultValue / 100.0).ToString(); 2 [ad_2] solved Switch statement in a C# calculator
[ad_1] check this and please don’t add pseudocode case “%”: textBox_Result.Text = (Double.Parse(textBox_Result.Text) * resultValue / 100.0).ToString(); 2 [ad_2] solved Switch statement in a C# calculator
[ad_1] I have to check if this exercise is correct It is not. if (((x < y) && (y < z)) && (y != 3)) printf(ā%f < %d < %d \nā, x, y, z); Is correct, assuming float x and int y, z. <> in some languages means “does not equal”. But in c, the … Read more
[ad_1] You can try, but if the assignment succeeds it will not store the entirety of your original number, because representing it with accuracy requires more than 16 bits. The highest order bit in a 16 bit integer is the 215 place. Two to the fifteenth power is 32768. Setting your 16 bits to all … Read more
[ad_1] You could use std::map with key -> primary key, value instance of your student class, but for good use some kind of database which will handle it for you. 2 [ad_2] solved How do I restrict users from entering redundant data in C++ program? [closed]
[ad_1] You don’t need to use ref in your parameter declarations. For reference types like your class A, a parameter declared as just A other will cause C# to pass a reference to the object. A parameter declared as A other in C# is similar to A* other in C++. A parameter declared as ref … Read more
[ad_1] In case source as well as pList are long, you may try converting source into a Dictionary: // Provinding that all LongRecordId are distinct var dict = source .ToDictionary(item => item.LongRecordId, item => item); … foreach (var item in pList) { MyRecord foundItem = null; //TODO: Put the right type here // Instead of … Read more
[ad_1] Your exponent function needs to return the n instead of x and in your main() you probably want to initialize the variable x to the value of function exponent with an argument of 5: int x = exponent(5); prior to printing via: print_exponent(x); That being said, your exponent function is broken as the return … Read more
[ad_1] You may be able to see what’s happening more clearly if you split the statement into several statements: int temp1 = printf(“Hello world!\n”); int temp2 = printf(“%d”, temp1); printf(“%d”, temp2); The first printf prints Hello world!\n. Since this is 13 characters, it returns 13. The second printf prints 13. Since this is 2 characters, … Read more
[ad_1] One way would be to just add a negative sign in front of the value: int myInt = -myInt; Another way to switch between a positive or negative number in a statement would be to multiply it by -1. myInt = myInt * -1; 0 [ad_2] solved Positive and negative number values [duplicate]
[ad_1] This: if(fare == -40){ char desc[50] = “Ouch! Cold either way!!”; } opens up a new scope, with a new local variable called desc, that “shadows” the one in the surrounding scope. This variable is initialized to the string, then thrown away as the scope exits. The variable of the same name in the … Read more
[ad_1] You didn’t post any minimal compiling code we can help you debug, so, everything I’m about to say are guesses based on other questions I’ve seen on this topic: make sure asd is declared static, CreateThread is a C function and knows nothing about class methods make sure asd is declared __stdcall, having wrong … Read more
[ad_1] #include <stdio.h> #include <string.h> typedef struct dbl9 { double array[9]; } Dbl9; Dbl9 fun(double *in){ Dbl9 ret; memcpy(ret.array, in, sizeof(ret.array));//There can be no assurance that <in> the correct return ret; } int main(){ double array[9] = {1.0, 2.0, 3.0, 4.0, 5.0, 6.0, 7.0, 8.0, 9.0}; Dbl9 dbl9= fun(array); int i; for(i=0;i<9;++i){ printf(“%f\n”, dbl9.array[i]); } … Read more
[ad_1] Warning, long winded answer ahead. Edited to reference the C standard and to be clearer and more concise with respect to the question being asked. The correct answer for why you have 32 has been given a few times. Explaining the math using modular arithmetic is completely correct but might make it a little … Read more
[ad_1] &p gets the pointer to the integer p -> That is, the memory address in which p is stored. *p “dereferences” the pointer, i.e. looks at the object at the memory address provided by p and returns that object. Your code above is invalid C, as you cannot dereference an int: error: indirection requires … Read more
[ad_1] Well, this is a problem: fillwordnr(f,p[].ptrletter,p[].numbers,lines,nrofline,a,c,string[]); You have to specify which element of p you want to work with – p[0], p[1], p[i], etc. Assuming nrofline is a valid index for p, you would write fillwordnr( f, p[nrofline].ptrletter, p[nrofline].numbers, lines, nrofline, a, c, string ); Honestly, based on the code you’ve posted, it’s not … Read more