In your function int huffman(node_t *huff, int n) you try to realloc() the huff pointer but in C we pass variables by value so you only receive a copy of the pointer. This means caller retains the original pointer and…
Just create an object of emp1 inside your main, and give it a value like below and it should be ok emp1 emp; emp.number.number1=3; //printf then with emp.number.number1 😉 solved accessing values structure within structure? [closed]
this is really straightforward: typedef struct { int x; int y; } Point_t; Point_t f(int x, int y) { Point_t p = { x, y }; return p; } And (to beat possible comments upfront): no, this is not returning…
#include <stdio.h> #include <stdlib.h> int main() { struct hash { int pages; int price; }; struct hash *h[2]; h[0] = malloc(sizeof(struct hash)); h[0]->pages = 1; h[0]->price = 2; h[1] = malloc(sizeof(struct hash)); h[1]->pages = 3; h[1]->price = 4; printf(“value =…
Options() is your default constructor. Structs and classes are equivalent in the sense that they can have methods and constructors. What’s after : is the initialisation list for Options(). It tells you that in your default constructor for Options(): num_particles…
Starting at the left hand side: struct foo *ptr declares ptr to be of type struct foo *, that is a pointer to struct foo. The = initializes that ptr variable to whatever the right hand side evaluates as. And…
Well, this is a problem: fillwordnr(f,p[].ptrletter,p[].numbers,lines,nrofline,a,c,string[]); You have to specify which element of p you want to work with – p[0], p[1], p[i], etc. Assuming nrofline is a valid index for p, you would write fillwordnr( f, p[nrofline].ptrletter, p[nrofline].numbers, lines,…
You should debug your code by yourself. void stack::push(int *dat) { ch::LinkList* newNode = new ch::LinkList; newNode->initialize(dat,ptr); ptr->head = newNode; } void stack::ch::LinkList::initialize(int *dat, ch *nxt){ data = dat; if(nxt->head) next = nxt->head; else next = 0; } Note that:…
You can do it like that for (int i = 0; i < present.size(); ++i) cout << present[i]->id << ” “; or in C++11 for (auto p : present) cout << p->id << ” “; I hope it helps solved…
Now how can I sort the data by id With a sort. Since this smells like homework, you may or may not be allowed to use the venerable qsort function. (I don’t know how to get the number of elements…
p is a pointer to a structure – this means that p ‘holds’ the starting address for a structure in memory — Hence: p = d.elmts+i represents the starting address in memory, for the current structure (i represents the address…
The members of struct person are fixed in size, and are not allocated separately from the struct instance – short answer is that you cannot resize the arrays, nor can you deallocate their storage without deallocating the entire struct instance.…
Well the second one is nonsense in many way. You don’t want to do that. The second if used only – then think how would you pass it to the function. There are innumerous problem that you would face –…
Your code as written has several syntax errors, and also your comparison function doesn’t do quite what you want. Quoting from the manpage for qsort: The comparison function must return an integer less than, equal to, or greater than zero…