[ad_1] *a = *b; The above statement will simply do this: value(a) <– value(b) (i.e. pointer a will contain value ‘d’ ). printf(“%x\n”, a); This will print the pointer’s address(a) in hexadecimal. However, always use the “%p” format identifier to print the addresses. “%x” is used to print the values in hexadecimal format. printf(“%x\n”, *a); … Read more
[ad_1] You can predict your output by following each step manually. In your case, each func call would work like the following chart: func(5) + +–+ func(4) | + | +–+ func(3) | | + | | +–+ func(2) | | | + | | | +–+ func(1) = 3 | | | | | … Read more
[ad_1] Generally it’s an awful way to write code, and does not guarantee that it will be any faster. Things which are simple and fast in one language can be complex and slow in another. You’re better off either learning how to write fast Python code or learning C++ directly than fighting with a translator … Read more
[ad_1] It’s not clear exactly what you are trying to do here, except perhaps learning basic c++ constructs. Here is some code to get you going. #include <iostream> #include <string> #include <map> using namespace std; class TEST { public: //Constructor – sets member string to input TEST( string input ) : _name( input ) { … Read more
[ad_1] a is declared a an empty vector so you cannot access elements of a unless there are any elements in a. You want a.push_back(nums[i]); instead of a[k] = nums1[i]; //a is declared as empty vector so you have to push elements to it. OR you can do vector<int> a(num1.size()); instead of vector<int> a; [ad_2] … Read more
[ad_1] The code you provided does not work on any numbers. The only thing it does is construct some SQL query check its result During the SQL-query-construction, the code does not assume any “numbers” to be provided. It actually uses a variable called password_txt->Text, which suggests it’s some form of TextBox control. The code gets … Read more
[ad_1] new is for dynamic allocation (of an array on the heap in this case), and returns a pointer to the new array. [] in the declaration are for declaring it to be a stack array (and the brackets belong the right side of the variable name). So the two legal approaches your code is … Read more
[ad_1] The first class is static, which means: You can’t use it as a type argument You can’t use it as a variable type It will have no instance constructors (whereas your non-static class implicitly has a public parameterless constructor) It will be implicitly abstract and sealed (even though that combination can’t be static It … Read more
[ad_1] You are passing a pointer to a local variable. Once your function ends, this variable is gone. If this is C++ you should use the string class. If for whatever reason you don’t, at least be const correct: const char* Worker::getName() const { return name; } 1 [ad_2] solved cout corrupt char* [closed]
[ad_1] In all versions of C++, the second version (Foo::States::BAR) using scope syntax is the more conventional and will be less surprising for future maintainers of your code. Since the value is a constant, there is no need for an instance of the class, so this is similar to how static methods are most often … Read more
[ad_1] The assignment expression x = n evaluates to the value assigned to x. So a = 4 evaluates to 4, and b = 0 evaluates to 0. In C and C++, non-zero values are true, and zero values are false. 3 [ad_2] solved Why is a=4 evaluated as true but b=0 evaluated as false … Read more
[ad_1] you’re comparing string and char type replace where r1[4] == “I” / where r1[4] == “O” with where r1[4] == ‘I’ / where r1[4] == ‘O’ 3 [ad_2] solved LINQ Operator ‘==’ cannot be applied to operands of type ‘char’ and ‘string’
[ad_1] ex.message.Contains(“Cannot open server”) && ex.message.Contains(“requested by the login”) [ad_2] solved How can I check if a string contains two other strings [closed]
[ad_1] It is normal for the compiler to generate an application! What is surprising is the location for the executable, it should have been generated in the parent directory: C:\TDM-GCC-64\> gcc Chess/chess.c Chess/init.c -o chess The explanation is interesting: You are using the Windows operating system, where the filenames are case insensitive. You instructed gcc … Read more
[ad_1] XDocument xdoc = XDocument.Load(“file.xml”)); var elm = from element in xdoc.Descendants(“element”) select new { attribute = element.Attribute(“attribute”).Value, }; 2 [ad_2] solved How do I read the contents of an XML element using C#? [duplicate]