You can do this using groupBy and map functions of Laravel’s Collection: $collection = new \Illuminate\Support\Collection($array); $group = $collection->groupBy(‘product_id’); $resultArray = $group->map(function($item, $key) { return [ ‘total_size’ => $item->sum(‘comp_size’), ‘product_id’ => $key, ]; }); This will let you expand the code a bit easier in the future. 1 solved Sum array values of the same … Read more
The answer is “it depends”, or perhaps better put as “nobody knows”, as this type of question is always tightly coupled with compiler optimisations, processor architecture and many other factors. I would also like to point out that if you find one better on one system, it may not reflect that it’s better in a … Read more
Something like this might work for a start: <?php $Data = array ( array ( ‘country’ => array ( ‘code’ => ‘in’, ‘name’ => ‘India’ ), ‘language’ => array ( ‘code’ => ‘en’, ‘name’ => ‘English’ ) ), array ( ‘country’ => array ( ‘code’ => ‘in’, ‘name’ => ‘India’ ), ‘language’ => array ( … Read more
Some diversity of approaches (admittedly esoteric, but fun!): function firstAndLast(a, o){ return !(o = {}, o[a.shift()] = a.pop()) || o; } console.log(firstAndLast([1,2,3,4,5])); console.log(firstAndLast([‘a’,’to’,’z’])); https://jsfiddle.net/brtsbLp1/ And, of course: function firstAndLast(a, o){ return !(o = o || {}, o[a.shift()] = a.pop()) || o; } console.log(firstAndLast([‘a’,’to’,’z’])); console.log(firstAndLast([‘a’,’to’,’z’], {a:’nother’,obj:’ect’})); https://jsfiddle.net/brtsbLp1/1/ Another fun one: function firstAndLast(a){ return JSON.parse(‘{“‘+a.shift()+'”:”‘+a.pop()+'”}’); } https://jsfiddle.net/brtsbLp1/2/ … Read more
To access the array, you need to use array index. Instead of using @messages_test = options[‘Messages’][‘IBMessageID’].to_s you need to use, to access to first element the arrayoptions[‘Messages’] array, below code @messages_test = options[‘Messages’][0][‘IBMessageID’].to_s You can iterate the array, if you wish, by using options[‘Messages’] each do |item| puts item[“IBMessageID”] # for illustration end 1 solved … Read more
For those with a maths background it is a surprising feature that System.out.println(“=” + (-3 % 4)); for example, returns -3 instead of 1 (which would be in the range [0,3]); Edit: in other words, the error message error message: Exception in thread “main” java.lang.ArrayIndexOutOfBoundsException: -8 is ultimately caused by (n % m) can return … Read more
Well the loop seems to be this one (at the end of the code): for i,j in itertools.combinations([a,b,c],2): all_diffs=alldiffs(i,j) total=count_total(i,j) zero=count_zero(all_diffs) total=np.array(total) union=map(sub,total,zero) zero=np.array(zero).tolist() union=np.array(union).tolist() union=[list(x) for x in union] sim=[[float(aaa) / bbb for (aaa, bbb) in itertools.izip(aa, bb)] \ for (aa, bb) in itertools.izip(zero, union)] sim_comb=sum(sim,[]) sum_of_sim=sum(sim_comb) number_sum=len(sim_comb) ave=sum_of_sim/number_sum one_ave=1-ave print one_ave One possible … Read more
It’s quite simple: construct new array, taking one card from position 0, second from N/2, third from 1, fourth from N/2+1, etc. 2 solved C# Shuffle with Arrays
Since no return value is specified, it returns null. The return statement here is optional since it does not return any value and is located at the end of the function. You can use the return statement to jump out of the function explicitly without necessarily reaching the end of the function. See Returning values … Read more
Property observers observe and respond to changes in a property’s value. Property observers are called every time a property’s value is set, even if the new value is the same as the property’s current value. You have the option to define either or both of these observers on a property: willSet is called just before … Read more
As discussed in chat, here is a javascript example that builds what you asked for: var tabs = [{“uId”:”2″,”tabId”:1,”tabName”:”Main”,”points”:”10″,”active”:”true”},{“uId”:”3″,”tabId”:2,”tabName”:”Photography”,”points”:”20″,”active”:””}]; var tasks = [{“taskId”:3,”taskName”:”Sing Sing Gem”,”priorty”:3,”date”:”2014-04-25″,”done”:0,”tabId”:1,”uId”:”2″},{“taskId”:4,”taskName”:”Shooting”,”priorty”:4,”date”:”2014-04-25″,”done”:0,”tabId”:2,”uId”:”3″}]; var uidSet = {}; var UIDSortFunction = function(a,b){ uidSet[a.uId] = 1; uidSet[b.uId] = 1; return a.uId – b.uId; }; tabs.sort(UIDSortFunction); tasks.sort(UIDSortFunction); var endResult = []; var i, j, tabsLen = … Read more
You could push sliced parts to the result. let array = [1, 2, 2], objlist = [{ name: ‘dummy’ }, { name: ‘new’ }, { name: ‘news’ }, { name: ‘place’ }, { name: ‘place’ }], result = [], i = 0, j = 0; while (j < array.length) { result.push(objlist.slice(i, i += array[j++])); } … Read more
This is quite basic program called selection sort. The wiki article is: Selection sort. Basically in this program, i is first pointing to the first element in the array. Then, j points to the next element. If, the element j is smaller than element i, they get swapped. After swapping, the inner for loop still … Read more
You should not attempt to call constructors or destructors explicitly. Assign a new value to the object in the array, like you would with ints or anything else: st[i] = Student(Name_i, id_i); And remove st[i].~Student(); 0 solved How can we assign variable values to a overload constructor separately(not at Initialization) in Cpp?
This isn’t about programming, but math… Hope this helps: http://www.wikihow.com/Add-Large-Numbers (As a simple example, add 1 and 11. What is the result? 12 or 21?) solved Sum of long integer array in c++