UPDATED: Added eval. Hadn’t noticed that it was in a string. It seems to me that your biggest problem is that it is all wrapped in an array with a single element. You can do: var element = eval(jsonData)[0]; The eval is there to convert from string to a javascript object. Then, to access anything … Read more
As per my understanding, You have 3 checkbox and each contains the array as a value. Now, on checkbox selection you want to print the selected checkbox array. If Yes, you can try this : new Vue({ el: ‘#app’, data: { checkboxes: [], boundingBoxes: [ { name: “bounding box”, color: “red” }, { name: “bounding … Read more
I think you don’t realy get the way PHP is handling objects and arrays. As kingkero said, the proper way to access your buttons by “id” is $page[‘button’][‘Your id’] As so, you will have to change function that you use to create the actual button. You could create an object that is callable the way … Read more
this code may be solve your problems: $arr = array(“1” => “1”, “2” => “2”, “4” => “4”, “5” => “5”, “8” => “8”, “9” => “9”, “10” => “10”, “11” => “11”, “12” => “12”, “16” => “16”); $arr_result = array(); $arr_keys = array_keys($arr); $start = intval($arr_keys[0]); $end = intval($arr_keys[count($arr_keys)-1]); $group_idx = 0; $idx … Read more
Why do I have to skip the month of february in the for loop and use mes->fevereiro[j] instead of mes->meses[1][j]? [closed] solved Why do I have to skip the month of february in the for loop and use mes->fevereiro[j] instead of mes->meses[1][j]? [closed]
You can use the following recursive function to get the depth where the uuid value is found. This version returns value 0 if the uuid value is not found at all. function searchDepth($uid, $array, $depth = 0) { $depth++; foreach ($array as $element) { if (isset($element[‘uid’]) && $element[‘uid’] == $uid) { return $depth; } else … Read more
You had some error about your indentation and element word, it was element def copy_sort(array): copy=array[:] sorted_copy=[] while len(copy)>0: minimum=0 for element in range(0,len(copy)): if copy[element] < copy[minimum]: minimum=element print(‘\nRemoving value’,copy[minimum], ‘from’,copy) sorted_copy.append(copy.pop(minimum)) return sorted_copy array=[5,3,1,2,6,4] print(‘Copy sort…\nArray:’,array) print(‘copy :’, copy_sort(array)) print(‘array’,array)` 1 solved Python sorting algorithm [closed]
System.out.print(Arrays.deepToString());//neither of them seems to be working System.out.print([0].Stringform()); This is dead code. It does nothing. In the first line you are asking the class Arrays to do something?? I’m not sure what you want to do there. Also change the name of the Number() function it might have conflicts with Java. Also brackets and semicolons … Read more
With the little information you give us, I would say that you do not manage the incrementation of your variable i. const arrStr = [“hello”, “asdf”, “dfa”] arrStr[0].includes(“hel”) // -> true arrStr[1].includes(“hel”) // -> false arrStr[2].includes(“hel”) // -> false arrStr[3].includes(“hel”) // -> cannot read property ‘includes’ of undefined If you look at the DCR’s answers … Read more
Simply use str.split(‘,’) var str = “Volvo,Saab,Mercades,Audi”; var arr = str.split(‘,’); console.log(arr); 2 solved How do I change the array string into an array of objects in javascript?
Try this one it will work for you. $array= Array( 0 => ’05_00pm_07_00pm|15_04_2016′,1 => ’03_00pm_05_00pm|15_04_2016′,2 => ’07_00pm_09_00pm|15_04_2016′,3 => ’03_00pm_05_00pm|14_04_2016′, 4 => ’01_00pm_03_00pm|14_04_2016′,5 => ’01_00pm_03_00pm|15_04_2016′,6 => ’01_00pm_03_00pm|15_04_2016′,7 => ’01_00pm_03_00pm|15_04_2016′, 8 => ’01_00pm_03_00pm|15_04_2016′,9 => ’01_00pm_03_00pm|15_04_2016′,10 => ’01_00pm_03_00pm|15_04_2016′,11 => ’01_00pm_03_00pm|15_04_2016′, 12 => ’01_00pm_03_00pm|15_04_2016′,13 => ’07_00pm_09_00pm|14_04_2016′,14 => ’07_00pm_09_00pm|16_04_2016′,15 => ’01_00pm_03_00pm|14_04_2016′, 16 => ’07_00pm_09_00pm|13_04_2016′ ); foreach($array as $key=>$row) { $newArr[$key] … Read more
Perhaps the following will be helpful: use strict; use warnings; print “Interface Name,Vlan Id,IP Address\n”; while (<DATA>) { my $interface = /interfaces\s+(\S+)\s+/ ? $1 : q/”/; my $vlanID = /unit\s+(\S+)\s+/ ? $1 : q/”/; my $ip = /address\s+(\S+)\s+/ ? $1 : q/”/; print “$interface,$vlanID,$ip\n”; } __DATA__ set interfaces ge-1/0/0 unit 0 family inet address 10.100.200.1/24 … Read more
If you have F unique first names and L unique last names, then overall number of combinations is N = F * L So you can generate needed number of non-repeating random integer values in range 0..N-1 (for example, with Fisher-Yates sampling), sort them, and get corresponding name combinations: for i = 0..M-1 Generate K[i] … Read more
input = “””3 5 2 1 3 4 2 3 4 2 2 1 3 2 1 8 7″”” f = [int(i) for i in input.split()] A = tuple(f) The value of A is now: (3, 5, 2, 1, 3, 4, 2, 3, 4, 2, 2, 1, 3, 2, 1, 8, 7) Important note: This … Read more
May be this could help you out list=[] for i in range(0,N): name=raw_input(‘Enter Name:’) age=raw_input(‘Enter Age:’) list.append([name,int(age)]) solved How to input a list in list in Python? [closed]