My first thought is to do this with arrayfun using an anonymous function that adds each scalar element of a to the full array in b. Then since you get a cell array result you can expand that cell array into the array you are looking for: >> a=[1,2,3,4], b=[5,6,7] >> result = arrayfun(@(x) x+b, … Read more
Try this HashMap<String, String> param = new HashMap<String, String>(); param.put(“A”, “2”); param.put(“B”, “3”); param.put(“C”, “2”); String[] list = new String[7];// It is better to use List other than an array int i = 0; for (Map.Entry<String, String> entry : param.entrySet()) { int lim=Integer.parseInt(entry.getValue()); for(int j=0;j<lim;j++){ list[i]=entry.getKey()+” “+String.valueOf(j+1); i++; } } If you really want to … Read more
This can be done for instance with two imbricated .forEach(): var obj = { “name”: { 0: ‘name0’, 1: ‘name1’, 2: ‘name2’ }, “xcoord”: { 0: ‘xcoord0’, 1: ‘xcoord1’, 2: ‘xcoord2’ }, “ycoord”: { 0: ‘ycoord0’, 1: ‘ycoord1’, 2: ‘ycoord2’ } }; var res = []; Object.keys(obj).forEach(k => { Object.keys(obj[k]).forEach(v => { (res[v] = (res[v] … Read more
I don’t know exactly what data structure you get the wall in, but assuming it is: std::vector<std::vector<char>> wall; To be able to perform melting using std::sort, it is best to have columns in the outer vector and rows in the inner vectors. // melting bricks for (int col = 0; col < wall.size(); ++col) //column … Read more
You can use Array.reduce() to do it: Sort the array (safety) Iterate over the array with reduce to create an object containing the ranges and the start of the active range (rangeStart). On the first iteration, push the first element in the ranges and save this element as the rangeStart On the successive iterations, if … Read more
I’m taking a gamble by answering this.. but I’m assuming that you want to keep on adding two indexes within your array that are next to each other, to see if they’d equal any value in your second array? Also, I have no idea why you’re using a nested loop. You only need to traverse … Read more
max_input_vars integer How many input variables may be accepted (limit is applied to $_GET, $_POST and $_COOKIE superglobal separately). Use of this directive mitigates the possibility of denial of service attacks which use hash collisions. If there are more input variables than specified by this directive, an E_WARNING is issued, and further input variables are … Read more
I think you’re looking to iterate over the byte array and find the absolute value of each element. Math.abs() should work for that. https://www.geeksforgeeks.org/java-math-abs-method-examples/ solved Setting all values in a byte array positiv [closed]
First of all, you need to provide a minimal reproducible example of your code. You can check here: https://stackoverflow.com/help/minimal-reproducible-example In regards to your question, using three loops can be a solution: import java.util.ArrayList; public class Main { public static void main(String[] args) { var combinations = new ArrayList<int[]>(); for (int i = 0; i < … Read more
([60, 21, -18, -57, -95, -67, -29, 8, 45, 82] as [Double]) .consecutivePairs .filter { $0.sign != $1.sign } public extension Sequence { /// Each element of the sequence, paired with the element after. var consecutivePairs: Zip2Sequence<Self, DropFirstSequence<Self>> { zip(self, dropFirst()) } } solved Retrieve numbers before/after sign change in [Double]
Yes and no. Yes, because it is the way you should return it. No, because you should (and have to) use new[] operator (or malloc function). So basically you should write: int* function(int n){ int i = 0; int *array = new int[n]; // or c-style malloc(n*sizeof(int)) for(i = 0; i<=n ; i++){ array[i] = … Read more
You can build a backtracking based solution to formulate all the possible sub-sequence for the given array. Sharing an ideone link for the same: https://ideone.com/V0gCDX all = [] def gen(A, idx = 0, cur = []): if idx >= len(A): if len(cur): all.append(cur) return gen(A, idx + 1, list(cur)) incl = list(cur) incl.append(A[idx]) gen(A, idx … Read more
memset(&host, 0, sizeof(host)); will fill it with zeroes. 0 solved How to use default values in a char array?
One actually does never want to mix computation logic with whatever kind of output code. In addition one could make use of Array.prototype.filter and a precise filter condition which does target odd and/or even number values … something similar to the next provided example code … function getEvenCount(list) { return list.filter(item => (typeof item === … Read more
You can do this by encoding the array in JSON format. Here’s the sample code for your better understanding: <?php $names = array( array( “foo”=> “bar”, ), array( “foo”=> “bar”, ), array( “foo”=> “bar”, ), ); $namesJSON = json_encode($names); echo “<pre>”; echo $namesJSON; echo “</pre>”; ?> This will output the JSON array which is required. … Read more