Your question is completely unclear but assuming your situation, you might be wanting something similar to this. You said they are already showing up in your page and you want them to appear as links var users = [ ‘<a href=”#2016″>2016</a>’, ‘<a href=”#2015″>2015</a>’, ‘<a href=”#2014″>2014</a>’, ‘<a href=”#”>#</a>’, ‘#’, ‘#’, ‘#’, ‘#’ ]; 1 solved Need … Read more
There are many ways to iterate/loop through an array. One common way it using a for loop. There can be many variations of a for loop: standard for loop (loops through numbers where i is each number): for(let i = 0; i < dangle.length; i++) { // loop through the dangle array let arr = … Read more
An array is a series of values with no defining keys: [‘one’, ‘two’, ‘three’] An object uses keys which have values which can be anything within the scope of the language. eg: boolean, integer, string, object, array or event functions: { one: { two: ‘three’ }, four: [‘five’, ‘six’], seven: ‘eight’, nine: 10, eleven: function … Read more
I’m not sure what the second check is supposed to be (the modulus of something has to be 1). If that is supposed to be that the modulus of all digits of the number has to be 1, here is how you could do it: var results = []; for (let i = 1; i … Read more
Have a look at the JS Array Methods, specifically array.filter. This code should do what you need: var playersWhoDebutedIn2003 = players.filter(player => { return player.debut === 2003;}); solved how to return array of objects in javascript? [closed]
This seems to work: const str=”XII-14″; const next = 123; const text1 = ‘00000000001’ + next; const len = 6; console.log(str + text1.substr(-len)); It returns: XII-14001123 solved how to convert this code substr in php to javascript
JSFIDDLE DEMO code: var json = { “test”: [ { “a”: “val_a1”, “b”: “val_b1”, “c”: “val_c1”, “d”: “val_d1” }, { “a”: “val_a2”, “b”: “val_b2”, “c”: “val_c2”, “d”: “val_d2” }, { “a”: “val_a3”, “b”: “val_b3”, “c”: “val_c3”, “d”: “val_d3” } ] }; var new_json = {test:{}}; $(document).ready(function(){ $.each(json.test, function(key, value){ //console.log(“key = “+key); //console.log(“value = “); … Read more
this should work: const all = [ { “a”: “Content A”, “b”: { “1”: “Content 1”, “2”: “Content 2” } }, { “y”: “Content Y”, “x”: { “3”: “Content 3”, “4”: “Content 4” } }, ]; console.log(all.reduce((prev, el) =>{ let curr = Object.entries(el); let k1 = curr[0][0]; let k2 = curr[1][0]; Object.entries(curr[1][1]).forEach((o => { let … Read more
var sales = [ { order_id: 138, price: 25, }, { order_id: 138, price: 30, }, { order_id: 139, price: 15, }, { order_id: 131, price: 25, }, ]; var buf = {} sales.map(obj => { if(buf[obj.order_id]) { buf[obj.order_id].price += obj.price } else { buf[obj.order_id] = obj } }) var result = Object.values(buf) console.log(result) 1 … Read more
It looks like you’ve overcomplicated the problem. It can be as simple as function updateObj(obj,keyName,val) { obj[keyName] = val; return obj; } const bag = { color: ‘yellow’, hasMoney: false } console.log(updateObj(bag, ‘color’, ‘Blue’)); // => { color: ‘Blue’, hasMoney: false } const house = { sqFt: 1500, isOccupied: true } console.log(updateObj(house, ‘sqFt’, 2000)); // … Read more
You can simply get the data by key: data.performance.fundBtcArr ,data.performance.fundUsdArr,data.performance.btcUsdArr var data={“performance”: {“datesArr”: [“2018-04-30”, “2018-05-07”, “2018-05-14”, “2018-05-21”, “2018-05-28”, “2018-06-04”, “2018-06-11”, “2018-06-18”, “2018-06-25”, “2018-07-02”, “2018-07-09”], “fundBtcArr”: [1, 0.956157566, 0.988963214, 0.992333066, 1.118842298, 1.064376568, 1.109733638, 1.082080679, 1.142624866, 1.1107828743809005, 1.0626307952408292], “fundUsdArr”: [1, 0.974710531, 0.944055086, 0.903073518, 0.869041365, 0.870284702, 0.815468401, 0.789070479, 0.777083258, 0.8027552300742684, 0.7766297878480255], “btcUsdArr”: [1, 1.019403669, 0.954590699, 0.910050818, 0.77673267, 0.81764737, … Read more
This can be done for instance with two imbricated .forEach(): var obj = { “name”: { 0: ‘name0’, 1: ‘name1’, 2: ‘name2’ }, “xcoord”: { 0: ‘xcoord0’, 1: ‘xcoord1’, 2: ‘xcoord2’ }, “ycoord”: { 0: ‘ycoord0’, 1: ‘ycoord1’, 2: ‘ycoord2’ } }; var res = []; Object.keys(obj).forEach(k => { Object.keys(obj[k]).forEach(v => { (res[v] = (res[v] … Read more
You could use this recursive, pure JavaScript function: The snippet below applies this function to the example data you provided and returns the required result: function extract(data, select, curpath) { var result = {}; // Part of the path that has been traversed to get to data: curpath = curpath || ”; if (typeof data … Read more
Hello you have to sort your object. Just use .sort of the array for that. Here is a sample: var obj = { “foo”: “bar”, “baz”: [ { “order”: 2, “fruit”: “banana” }, { “order”: 1, “fruit”: “apple” }, { “order”: 3, “fruit”: “peach” }, ] } // get property var arr = obj[“baz”]; // … Read more
The line el.setAttribute(key, [key]); tries to set the attribute to an array containing the key as its only entry (and thus will set href to “href” since the array will get coerced to string). You probably meant el.setAttribute(key, obj.att[key]); // ——————^^^^^^^ Live Example: function hoistNav() { const nav = []; nav[0] = {text: ‘HOME’, att: … Read more