You need a method to add void add(int a[][maxCols], int b[][maxCols], int res[][maxCols]) { int row, col; for (row = 0; row < maxRows; row++) { for (col = 0; col < maxCols; col++) { res[row][col] = a[row][col] + b[row][col]; } } } and create 2 matrix in main, add them and show the result: … Read more
First of all, your ternary operator seems to be quite repetetive. There is a way to make it shorter: totalPrice = salesPrice + ( salesPrice <= 25 ? minShipping : maxShipping ); Then, it is a good habit to declare your variables before you use them using var keyword. In this particular case the advice … Read more
What happens here? You originally call the function with k = 7. The function sees that the given value k = 7 is > 0 and thus calculates 7 + the result of the function if called with 6. In order to determine the latter, it calls itself with k = 6. The function sees … Read more
NSArray *firstArray=[NSArray arrayWithObjects:@”1″,@”2″,@”3″, nil]; NSArray *secondArray=[NSArray arrayWithObjects:@”10″,@”20″,@”30″, nil]; NSMutableArray *sumArray=[NSMutableArray new]; for (NSInteger i=0; i<[firstArray count]; i++) { NSString *newValue=[NSString stringWithFormat:@”%ld”,([[firstArray objectAtIndex:i]integerValue] + [[secondArray objectAtIndex:i]integerValue])]; [sumArray addObject:newValue]; } NSLog(@”sum=%@”,sumArray); Output is : sum=( 11, 22, 33 ) NOTE: both firstArray & secondArray must be of same size, and contain integers as string. Otherwise you need … Read more
Here is a simple calculator example to help get you started. while True: num1 = input(‘First Number: ‘) num2 = input(‘Second Number: ‘) op = input(‘Operator: ‘) try: num1 = int(num1) num2 = int(num2) except: print(‘Input a valid number!’) continue if op not in [‘+’, ‘-‘, ‘*’]: print(‘Invalid operator!’) continue if op == ‘+’: print(str(num1 … Read more
My first thought is to do this with arrayfun using an anonymous function that adds each scalar element of a to the full array in b. Then since you get a cell array result you can expand that cell array into the array you are looking for: >> a=[1,2,3,4], b=[5,6,7] >> result = arrayfun(@(x) x+b, … Read more
When each() method is called, it iterates over the DOM elements that are part of the object (JQuery). this keyword refers to the current element. Where text function can be used to retrieve the text of that element, so simply having a inner callback function to return the update text (increment by 1) would update … Read more
import java.util.Scanner; public class Demo { public static void main(String[] args) { Scanner x=new Scanner(System.in); int n=0;int g=0; int term=0;int temp=0; int sum=0; int factor=1; System.out.print(“Input N:”); n=x.nextInt(); g=n; int number = 0; if (n<=0) { System.out.println(“Please enter a positive integer”); System.exit(0); } if (n>0) { System.out.print(“The factors are:”); while (factor<n) { if (n%factor==0) { … Read more
Java strings are immutable. Every time you do: s+=c; You’re really saying: s = new String(s + c); new String(s + c) must allocate a string of length s + 1, or: 1 2 3 4 5 6 7 8 9 … etc. Since Sum(1..N) == (n + 1) (n / 2), this is O(n^2). … Read more
Call stron the number and str.join the result of that: i = 4316 print(“+”.join(str(i))) 4+3+1+6 solved Python – How to show addition of integers digits
Try using setOnClickListener to listen to click events import android.support.v7.app.AppCompatActivity; import android.os.Bundle; import android.view.View; import android.widget.ArrayAdapter; import android.widget.Button; import android.widget.EditText; import android.widget.Spinner; import android.widget.TextView; public class MainActivity extends AppCompatActivity { EditText abasic, ahra, aca, lopfd, lophd, la; TextView ebasic, ehra, eca, agross, egross, loprs, hdrs, lars, td, spd, eepf, erpf, tpf, eeesi, eresi, tesi, pfesi; … Read more