So you want to generate all permutations from size = 1 to size = N? Stack Overflow user Andy Carson has created a JavaScript library with a permutation generator function that lets you specify size. See: GitHub / acarl005 / Generatorics // Adapted from: https://stackoverflow.com/a/41232141/1762224 // Uses: https://github.com/acarl005/generatorics const allPermutations = (arr) => Array.from({ length: … Read more
Your issues lies in your formatting and confusion between the use of the echo command and non PHP wrapped HTML. Code should read as follows when properly formatted. <?php $db_host = “localhost”; $db_username = “vistor”; $db_pass = “visitor”; $db_name = “test”; $db = new PDO(‘mysql:host=”.$db_host.”;dbname=”.$db_name,$db_username,$db_pass); $db->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_WARNING); $query = $db->query(“SELECT * FROM pet’); ?> <html> … Read more
Use it like this – String [] myArray = myList.toArray(new String[myList.size()]); solved JAVA casting list of strings to string array [duplicate]
Use this String[] params = data.split(” “); String firstString = params[0]; split() function will split your whole string using space as delimiter, resulting in array of strings. First element of the array is the string you are looking for. 2 solved Extract specific string from String [closed]
If it is WindowsForms that you are using, you can use the PictureBox control. 2 solved How do I put an image in VisualStudio with C#? [closed]
my_list = [1, 2, 5, 8, 15, 25] deleted_elements = [] deleted_elements.append(my_list.pop()) deleted_elements.append(my_list.pop()) deleted_elements.append(my_list.pop()) print(my_list) print(deleted_elements) print(“Last deteleted: ” + str(deleted_elements[-1])) solved How to print last deleted element from the list? [closed]
Just when I was about to go crazy, I found a way to do it. Its brute force at the least The extended solution is here : https://codesandbox.io/s/dynamic-table-jc3qf3?file=/src/index.js solved Merge Table rows with same values using Vanilla JavaScript
Use goto: This will only exit the while loop. while (true) { … if (some condition) { goto CLEANUP; } … } CLEANUP: … exit() the program: while (true) { … if (some condition) { exit (EXIT_FAILURE); /* OR, if in the `main()` function: */ return EXIT_FAILURE; } …. } abort() the program: while (true) … Read more
Verify that you have the latest version of Node.js installed (or, at least 13.2.0+). Then do one of the following, as described in the documentation: Option 1 In the nearest parent package.json file, add the top-level “type” field with a value of “module”. This will ensure that all .js and .mjs files are interpreted as … Read more
The correct way to avoid SQL injection attacks, no matter which database you use, is to separate the data from SQL, so that data stays data and will never be interpreted as commands by the SQL parser. It is possible to create an SQL statement with correctly formatted data parts, but if you don’t fully … Read more
This problem is indeed not vba specific. For each box, add a label when it was added to the storage. You may take the point in time as a timestamp, iteration number or whatever unit suits you. Then you can now evaluate the time the box spent in storage by calculating now-time_when_box_was_added, for every single … Read more
I’ll do my best to explain it here on simple terms, but be warned that this topic takes my students a couple of months to finally grasp. You can find more information on the Chapter 2 of the Data Structures and Algorithms in Java book. There is no mechanical procedure that can be used to … Read more
Assuming you need to create object at compile time depending on a variable, you can try something like following class class1{}; class class2{}; int main( int argc, char *argv[] ) { constexpr bool variable =true; /* x is object of type class1 or class2 depending on compile time constant ‘variable’ */ typedef std::conditional<variable, class1, class2>::type … Read more
for (int i = 0; i < userInput; i++) { System.out.print(” ” +(i%7)+1); } Assuming it is java code that you are talking about. 2 solved using for loop in repeating number of day [closed]
Try this var noArray = [2,3,5,7,9,11,13,15,17,19]; function BiggerOf(arrayVal, val){ for (i = 0; i < arrayVal.length; i++) { if(arrayVal[i] > val ){ alert(arrayVal[i]); } } } BiggerOf(noArray, 8); solved javascript function BiggerOf(array,value) [closed]