Kirat I guess, you want to store first list items as keys and second list items as values in a HashMap. For that, you need to create a hashmap of string, string type as given below and store all its value there. HashMap<String, String> hmap = new HashMap<String, String>(); for(int i=0;i<a1.size();i++){ hmap.put(a1.get(i),a11.get(i)); } for(Map.Entry m:hmap.entrySet()) { … Read more
You need to use if ( (RanNum == 1) || (RanNum == 2) || (RanNum == 3) || (RanNum == 4) || (RanNum == 5) ) instead of if (RanNum = 1||2||3||4||5) Similarly for the other if statement. That’s one problem. The other problem is that you have the line: int RanNum; in main but … Read more
algorithm for finding the number of 1s in a matrix (only vertical 1s). The image is self explanatory that what i exactly want solved algorithm for finding the number of 1s in a matrix (only vertical 1s). The image is self explanatory that what i exactly want
You can solve this problem using a regular expression and NSRegularExpression. Construct a pattern which matches the text between brackets. For example the pattern @”\\[([^]]*)]” matches an opening bracket \\[ – the backslash is required to treat the bracket as a literal character, zero or more characters except a closing bracket [^]]*, groups that text … Read more
your question itself has the answer… you say … “Im thinking to keep an anti lost app in system partition….” and also know that.. ….”and it’s can only be done with root access..” read these do sentences again… you will get your answer… also read this article to get a rough idea of what its … Read more
That depends of the definition of your structs. if you want only the array of items, you should unmarshal the main structure and then get the items array. something like this package main import ( “encoding/json” “fmt” “io/ioutil” “os” ) type Structure struct { Items []Item `json:”items”` } type Item struct { ID int `json:”id”` … Read more
Here is the sample code int main(void) { int x = 0x1234abcd; int y = 0x5678cdef; long long z = ((long long)x<<32) | y;/* x needs to be type casted as long long */ printf(“%llx\n”,z); return 0; } Also take consideration of x or y being negative number i.e if sign bit is set(1). It’s … Read more
I assume that your expected output is bye see you.If I understood correctly then following methods can be used to get the desired output: In this string splits into an array(splits()) with delimiter ” ” and find index of bye (j)and you(k) in the array then using a for loop to get strings in the … Read more
You want to overload << operator. For instance: ostream& operator<<(ostream& os, const Date& dt) { os << dt.mo << “https://stackoverflow.com/” << dt.da << “https://stackoverflow.com/” << dt.yr; return os; } If a() isn’t constructor, but only a () operator overloaded which I assumed changes the a field of the class A to the parameter provided inside … Read more
You should use Qt signaling mechanism. class QWindow : QMainWindow { //this macro is important for QMake to let the meta programming mechanism know //this class uses Qt signalling Q_OBJECT slots: void updateLabel(QString withWhat) … }; And now You just need to connect this slot to some signal class SomeThreadClass : QObject { Q_OBJECT … … Read more
You could create a list with the years and iterate over it: years = [‘1990’, ‘1995’, ‘2000’, ‘2005’, ‘2010’, ‘2015’] plot_i = 1 for y in years: data = mmr[mmr[‘Year’]==y] ax = fig.add_subplot(2,3,plot_i) ax.hist(data[‘MMR’], color=”darkred”, edgecolor=”white”) ax.set_title(y + ‘ MMR Distribution’, fontweight=”bold”, loc=”left”) ax.spines[‘left’].set_visible(False) ax.spines[‘top’].set_visible(False) ax.spines[‘right’].set_visible(False) ax.spines[‘bottom’].set_visible(False) ax.tick_params(length=0) ax.set_xlim(0,3000,500) plot_i = plot_i + 1 1 … Read more
There are a lot of specifications missing for the question, but the basic concept might be the following: Listen the events for the container resizing with a ComponentListener In the Event listener make the resize logic, for example by increasing the font size until the text does not fit in the container. See this example. … Read more
You have incorrect syntxis What do you whant to do with ? jQuery(function() { jQuery.each(jQuery(‘h1’).add(‘h2’).add(‘h3’).add(‘h4’).add(‘h5’).add(‘h6’).add(‘ul#navigation’)).function(index, element) { var bounds = jQuery(element).offset(); var image_left = bounds.left; var image_top = bounds.top + bounds.height; var image = jQuery(‘<img src=”https://stackoverflow.com/media/images/foldback.png”>’); image.style.position = ‘absolute’; image.style.top = image_top + ‘px’; image.style.left = image_left + ‘px’; } function set_search_width() { var offset … Read more
If the syntax is wrong the compiler will produce an error, so that way you will know anyway. If it is compiling but not working as you expect then it’s going to be a logic error, in which case you can use a debugger to work out why. It doesn’t seem to be a syntax … Read more
A typical linked list structure is made of three parts The Data class Bunny { string name; // don’t use pointers unless you really, really need them int age; bool gender; string color; bool radioactive_bunny; public: string getGender(); // don’t need to know which Bunny anymore because // these functions are bound to a particular … Read more