Introduction A prime number is a natural number greater than 1 that has no positive divisors other than 1 and itself. Determining if a number is prime is an important problem in mathematics, and there are several methods for solving it. In this article, we will discuss some of the most common methods for determining … Read more
Introduction Compile errors can be a source of frustration for many developers. In this article, we will discuss a particular compile error: “Only assignment, call, increment, decrement, and new object expressions can be used as a statement”. We will explain what this error means and how to fix it. We will also provide some tips … Read more
You have to write if($_POST[‘postnummer’] == “7900” || $_POST[‘postnummer’] == “7950” || $_POST[‘postnummer’] == “7960”) { $region = “Nordjylland”; } elseif ($_POST[‘postnummer’] == “8654” || $_POST[‘postnummer’] == “8660” || $_POST[‘postnummer’] == “8680” || $_POST[‘postnummer’] == “8700”) { $region = “Midtjylland”; } solved php if elseif statement select wrong variable every time [closed]
You can iterate the digits by using the modulo (%) and division (/) operators: public static int countCommonDigits(int a, int b) { int count = 0; while (a > 0 && b >0) { // Get the right most digits of each number int digitA = a % 10; int digitB = b % 10; … Read more
You can’t access $dine in your second function because it’s nowhere defined. The $dine from your first function is only a local variable. I would suggest this solution which uses the fact that calculate_dinein_price() also returns the value of $dine: public function calculate_dinein_total(){ $total_dine = 0.00; $total_dine = $total_dine + $this->calculate_dinein_price(); return $total_dine; } 8 … Read more
Just index the list/string. It’s the same kind of syntax for both lists and strings. >>> s=”abcdefg” >>> s[0] + s[1] # This does the operation ‘a’ + ‘b’ ‘ab’ Lists and strings are both sequence types in Python and sequences in Python are 0-indexed. This means the first item is at index 0, the … Read more
To do a join and get half a result even if the other record does not exist, use an outer join. To chose the first non-NULL value of a list, use COALESCE: SELECT IDowner as IDoutput, COALESCE(FirstName || ‘ ‘ || LastName, CompanyName) AS Name FROM Owner LEFT JOIN Contacts ON Owner.IDcontacts = Contacts.IDcontacts LEFT … Read more
It looks like you are actually looking for descending order. Anyways, here is a solution from one list to another: Dim myList As List(Of String) = {“test|10”, “name|44”, “blabla|16”}.ToList Dim orderedList As List(Of String) = (From item In myList Order By item.Substring(item.IndexOf(“|”) + 1) Descending Select item).ToList EDIT: This will sort the items as strings, … Read more
Add this rule to your CSS: .page-header-image.grid-parent { text-align: center; } This element contains the image and has full width: Since the image is an inline element, text-align: center; will center it inside its container. 2 solved Centering featured image in WordPress [closed]
Assuming that $arr is the lines of the file… $emptyLinesSkipped = 0; foreach ($arr as $value) { if (” === trim($value)) { if ($emptyLinesSkipped < 2) { $emptyLinesSkipped = $emptyLinesSkipped + 1; continue; } $item3 = $value; // and so on… } } solved How to detect second occurrence of an empty line in a … Read more
it should be the following for it to work correctly: var = “1” if var == “1”: print(“DL”) else: print(“DSU”) As said in the comments, print() is a function so to check if the “1” matches the condition, put it in a variable. 0 solved Python – If Statment Not Working Properly [closed]
You’re not using “CSS3”. You’re using a combination of invalid CSS (there is no plan for a display: box in CSS), an early WebKit draft implementation of CSS3 Flexbox, and XUL boxes (which are completely unrelated to CSS3 Flexbox and to what WebKit implements). XUL boxes are not allowed to be floated; when you float … Read more
I’m assuming your datetime variable is a VARCHAR – this can be directly cast via CONVERT: Declare @YourVariable Varchar (15) = ‘JAN 01 1996’ Select Convert(Date, @YourVariable) 1996-01-01 2 solved Converting datetime variable format
Something like this… List<String> result = Stream.of(“A”, “A”, “BB”, “C”, “BB”, “D”) .collect(Collectors.groupingBy( Function.identity(), Collectors.counting())) .entrySet() .stream() .filter(x -> x.getValue() == 1L) .map(Entry::getKey).collect(Collectors.toList()); System.out.println(result); // [C, D] 2 solved return the list with strings with single occurrence [closed]
Exception line (java.lang.ArrayIndexOutOfBoundsException: length=5; index=5) clearly mentions that you are Trying to get index=5but the length of the dato is 5(length=5). So, use only proper index i.e. index 0 to 4. OR Make sure that enough indexes exists to access. Note: You have used dato.split(“, “);. Try with dato.split(“,”);. May be the problem is with … Read more