[Solved] How to dynamically allocate memory in 2D array and store values? [closed]

As i said problem is in scanning N and M variables. Change scanf(“%d %d”,&N,&N); to scanf(“%d”,&N); scanf(“%d”,&M); and you are fine. Problem was you were reading N twice while didnt read an M which was used uninitialized. Non-static variables (local variables) are indeterminate. Reading them prior to assigning a value results in undefined behavior. You … Read more

[Solved] Break out of Python for loop

You could just iterate until 5 instead of 6 and print your message out of the loop: for counter in range(5): # Remove the if statement: # if counter == 5: # print(“”) # break myCar.accelerate() time.sleep(1) print(“Maximum speed reached!”) 1 solved Break out of Python for loop

[Solved] How to create reusable UI control using JavaScript [closed]

Look into javascript templating. See mustache.js for one example. e.g. <script type=”text/template” id=”template”> {{#elements}} <div id=”{{id}}”> {{content}} </div> {{/elements}} </script> And your JavaScript: var view = { “elements”: [ { id: “one”, content: “Lorem ipsum dolor” }, { id: “two”, content: “Sit amet consectetur” } ] } var template = document.getElementById(“template”).innerHTML; var output = Mustache.render(template, … Read more

[Solved] printf() function in C

Read the printf spec: First format string, then parameters. #include <stdio.h> int main(){ long mn = 166662; printf(“Howdy, I am %ld i hope that you had a better better day than I am having.\n”, mn ); return 0; } 2 solved printf() function in C

[Solved] SQL, SUM + CASE [closed]

Never use commas in the FROM clause. Always use proper, explicit JOIN syntax. Then, you cannot nest aggregation functions, so this should be sufficient: SELECT o.ID_DOSSIER, SUM(CASE WHEN ID_TYPE IN (‘0’, ‘1’) THEN TTL * -1 WHEN ID_TYPE IN (‘2’, ‘3’) THEN TTL END) FROM ope o JOIN actor a ON o.ID_ACTION = a.ID_ACTION GROUP … Read more

[Solved] Sort a class array by a string attribute in Java

For Java 8 use a lambda expression and the Arrays sort function: Users[] someUsers = {user1, user2, user3}; Arrays.sort(someUsers, (a,b) -> a.firstName.compareTo(b.firstName)); For previous versions use a Collection Comparator: Users[] someUsers = {user1, user2, user3}; List<Users> userList = new ArrayList<Users>(Arrays.asList(someUsers)); Comparator<Users> comparator = new Comparator<Users>() { @Override public int compare(Users left, Users right) { return … Read more

[Solved] Cummulative SUM based on columns

No need to make thinks more complicated than they need to be… IF OBJECT_ID(‘tempdb..#TestData’, ‘U’) IS NOT NULL DROP TABLE #TestData; CREATE TABLE #TestData ( ID INT NOT NULL, [Year] INT NOT NULL ); INSERT #TestData (ID, Year) VALUES (1, 2010), (1, 2010), (2, 2010), (2, 2011), (3, 2012), (4, 2013), (5, 2014), (5, 2014), … Read more

[Solved] Adding attributes with jquery

There are a few issues on your snippet. You are not loading jQuery library so you cannot select a DOM element(such as p.slider-price) like $(“p.slider-price”). To fix that, you should load the jQuery library (in fiddle you do that by choosing it from the frameworks & extensions menu). Than, using jQuery you will be able … Read more

[Solved] In JavaScript, what is the simplest way to insert text into a string?

Use: var queryStringParts = queryString.split(‘&’); var pairs = queryStringParts.map(function(str) { return str.split(‘=’) }) var rewrittenParts = pairs.map(function(pair){ return ‘slides[0].’ + pair[0] + ‘=’ + pair[1] }); var newQuerystring = rewrittenParts.join(‘&’); As was pointed out in the comments, in this specific case we could skip the split into pairs step and just do var queryStringParts = … Read more

[Solved] Why won’t my python program work?

raw_input returns a string … you cannot square a string (or raise it to any power for that matter) try def square(n): n = int(n) #this will try to force it to be an integer instead of a string … print square(n) beware if a user types “hello” or something though .. as it cannot … Read more