is what you are expecting is to convert vb to c#? void Main() { string s =”xhhxzx”; int i5 = 3; string res = e(s, i5); Console.WriteLine(res); } public static String e(String str, int i5) { return (str.Length / i5).ToString(); } you can do in one line public static String e(String str, int i5) => … Read more
Based on your comments & question for migration this is what I am suggesting: Map<LinkRelation, Optional<Link>> links = new HashMap<LinkRelation, Optional<Link>>(); links.put(IanaLinkRelations.SELF, Optional.of(response.getLink(IanaLinkRelations.SELF))); links.put(IanaLinkRelations.NEXT, Optional.of(response.getLink(IanaLinkRelations.NEXT))); links.put(IanaLinkRelations.PREVIOUS, Optional.of(response.getLink(IanaLinkRelations.PREVIOUS))); …. //calling addLinlk addLink(apmCoreBaseUrl, response, links, IanaLinkRelations.SELF); addLink(apmCoreBaseUrl, response, links, IanaLinkRelations.NEXT); addLink(apmCoreBaseUrl, response, links, IanaLinkRelations.PREVIOUS); And inside addLink: private void addLink(String baseUrl, RegistrationsResource response, Map<LinkRelation, Optional> links, LinkRelation … Read more
s = “Stackoverflow is a platform” L = s.split(‘ ‘) K = [‘ ‘.join(L[0:i]) for i in range(1,len(L)+1)] print(K) solved save all word permutations that are in a sentence in to a list [closed]
There are many options how you can delete an element from the array. Look at the snippet below, there you can find examples with filter, slice and splice array methods for removing items. class TimeFilter { onHourChange(hours) { const noZeroMinutes = item => !(hours === 0 && item.value === 0); this.minuteOptions = [ { value: … Read more
Class in another class, the error as TypeError: Student.__init__() missing 1 required positional argument: ‘lap’ in line 21. s1=Student(‘raj’,2) [closed] solved Class in another class, the error as TypeError: Student.__init__() missing 1 required positional argument: ‘lap’ in line 21. s1=Student(‘raj’,2) [closed]
N is uninitialised meaning N could have any integer value. That unknown value is copied to M, and then scanf() called to assign a value to N. The program needs to verify that system calls (like scanf()) has done what was expected with user input. Below is a “better” version that tries to protect itself … Read more
QueryReadOnlyListAsync calls the Dapper extension method QueryAsync, which returns a Task<IEnumerable<T>>. IEnumerable doesn’t implement IReadOnlyList. You can’t return Task<IEnumerable> if the method’s return type is Task<IReadOnlyList>. You need to convert the IEnumerable into a collection that implements IReadOnlyList, such as a regular List: //Make method async so you can await the Task returned by ExecuteWithResiliency … Read more
You can sequentially loop through the string and append the inverted character to another string. You can check whether the character is lowercase or not by converting it to lowercase (with String.toLowerCase) and checking whether the result is equal to the original. let swappedName = “elZerO”; let res = “”; for (let i = 0; … Read more
This is a popular question for people who learn python. The answer is that python has no pointer but using id(). And id() return C language memory address in CPython interpreter. Everything in python is a python object and id() is the identity of the python object. When you write python code you need to … Read more
I found a solution that works, after trying alot of different things (\bquick brown\b).*(\bover the\b) It has a match on “The quick brown fox jumps over the lazy dog, bla bla, something something” But not “The quick brown fox jumps over something the lazy dog, bla bla, something something” And not “The quick brownest fox … Read more
After 4 days of trying I found the answer myself. Thanks for the great help guys… import numpy DARK = [] a = [] stack = [] for i in range(0,3): # create 3d numpy array d = numpy.array([[1, 2], [3, 4]]) a.append(d) stack.append(numpy.array(a)) # write it into the actual variable DARK.append(numpy.array(numpy.median(stack[i], 0))) solved python2.7 … Read more
import re rx = [‘abc’, ‘de fg’, ‘hg i’] def string_m(a=rx): new = [] for i in a: l = re.sub(” “,”https://stackoverflow.com/”,i) r = l.split(“https://stackoverflow.com/”) #r.reverse() rx = ” “.join(r) new.append(rx) new.reverse() return new a=string_m(rx) print(a) Your biggest problem is that you return the result of the first iteration of your for loop instead of … Read more
If you want to print hyphens instead of zeroes, then simply print hyphens instead of zeroes. So instead of this: System.out.print(scoreArray[x][y]); you might write this: if(scoreArray[x][y] == 0) System.out.print(“-“); else System.out.print(scoreArray[x][y]); Your question doesn’t include the code that prints the array so I can’t be more specific to your code. 1 solved Display char instead … Read more
You need to use reflection. Here’s a sample: static void Main(string[] args) { string obj1 = “a string”; int obj2 = 12; DateTime obj3 = DateTime.Today; object[] obj_array = { obj1, obj2, obj3 }; foreach (object obj in obj_array) { //Print value Console.WriteLine(“Value: ” + obj.ToString()); //Print property names Console.WriteLine(“Property Names:”); foreach (PropertyInfo prop in … Read more
Yes, it is doable (with some restrictions). #include <stdio.h> #include <stdlib.h> #include <limits.h> // Assuming 2s-complement numbers // and an understanding compiler // Some checks omitted! int main(int argc, char **argv) { int input; unsigned int itmp; int size; int sign, sin, sout; char out[3] = { ‘0’, ‘+’, ‘-‘ }; if (argc != 2) … Read more