Where is the value stored? That depends on the PHP configuration. By default, session variables are serialized and written into a file on the server’s file system. On each page view that starts the session, they are unserialized and accessible from the $_SESSION array. It’s possible to override the default session handler so that you … Read more
Instead of echo, try this: printf(‘%+d’, $gd); Reference: printf() string formatting 2 solved How to show plus and minus sign when subtracting two variables: [closed]
As the comments have suggested you need to change the return type of the function to return int and you need to return your damageDelt variable. One way to do this is declare it outside of your if statements and then return it at the end of the function. If you didn’t want to do … Read more
The problem you’re experiencing is due to a misunderstanding of lists, list-references, and possibly the concept of mutability. In your case, you are binding the name user_data to a list object. In other words, user_data acts as a list-reference to the actual list object in memory. When you say user_list.append(user_data), all you’re doing is appending … Read more
One way to do this is creating a new Swift Files, and make a struct with static variables like this: struct CommonValues { static var UserNum: Int = 0 } And then, you modify it in any view controller if you need it. You maybe should save it and load it as well, I recommend … Read more
You have to understand that in computing, when ever something is destroyed, it is not set to 0 or some magic value. It is simply set to be overwritten when the next process comes. In your loop, you didn’t initialize SampleVariable and it just took what ever value was there before. In the first iteration … Read more
Your hasAnimals method needs to return a boolean value i.e. true or false based on the value of the type variable. You’re .. kind of on the right track, but you’re not honoring the requirements of the method. It shouldn’t print anything, and it shouldn’t return type because type is an int and not the … Read more
May be this function can help: def checkChange(FileName, oldContent): fSrc = open(FileName, ‘r’) actualContent = fSrc.read() fSrc.close() if actualContent != oldContent: print(1) return actualContent solved Python Check txt variable loop [closed]
You can make the scopes non-overlapping using braces: switch (something) { case 1: { int Number; } break; case 2: { float Number; } break; } Going out of scope is the only way a variable name is “deleted” in the sense you are talking about. Notably and unlike some other languages, C# doesn’t allow … Read more
No, you can’t, and it makes no sense honestly to have a feature like that. If you want , you can use a dictionary, where you can have the key be a string: Dictionary<string, RectangleShape> shapes = new Dictionary<string, RectangleShape>(); shapes.Add(“nameTheKey”, new RectangleShape( … )); Then you can simply read the “variable” like shapes[“nameTheKey”] solved … Read more
You seem to have misunderstood how variable scopes work. The x in Assign is not the same as x in Main. This is because in C#, int is passed by value (this is the same as C++, BTW). You probably meant to mark the variables in Assign as ref: class Program { static void Assign(ref … Read more
Working example with global variable and two windows. It uses only one mainloop() and Toplevel() to create second window. import tkinter as tk # — functions — def main(): #inform function to use external/global variable global int_var # only if you will use `=` to change value root = tk.Tk() root.title(“Root”) # change global variable … Read more
Where is my mistake? There are possibly three mistakes. The first is that ‘variable_’ + ‘a’ obviously isn’t equal to ‘variable_1′. The second is the quoting in the argument to exec. Do for x in list: exec(“variable_%s=””” % x) to get variable_a etc. The third mistake is that you’re not using a list or dict … Read more
name, in your case, is the actual name of the variable. It is an array of char pointers. The first element of the array points to a string “blah and blah”. solved In the C language how do you use make multiple strings in separate variables
Instead of writing the following which id not valid Java, Paraula tipo1; tipo1 = { Paraula.lletres[0] = ‘t’; Paraula.lletres[1]=’1′; Paraula.llargaria = 2; perhaps you intended to write Paraula tipo1 = new Paraula(); tipo1.lletres[0] = ‘t’; tipo1.lletres[1]=’1′; tipo1.llargaria = 2; However a much cleaner way to do this is to pass a String to the constructor … Read more