a==14 is not a statement, it’s an expression. It produces a boolean result, that is discarded as soon as it is produced. It is a line that has absolutely no effect on the program. On the other hand, there is no === operator in python, that’s why your program fails in that case. Contrary to … Read more
First one is three-element tuple. Second one is some string. Third one is same three-element tuple, since in this context parentheses are redundant. Small code snippet will be enough to prove it: g1 = (3, 4, 5) g2 = “(3, 4, 5)” g3 = 3, 4, 5 type(g1) # <type ‘tuple’> type(g2) # <type ‘str’> … Read more
Can you do in C++ something like this: Yes. struct Lecture { }; struct Carriage { Carriage(const Lecture&) { } void runIt() { } }; int main() { Lecture le; Carriage ca = le; ca.runIt(); } The problem is, when I am trying to invoke a method which belongs to Lecture class the methods is … Read more
The problem is with the pointer assignments as you build the slice you are trying to reference. The addresses keep changing. func main(){ var lump []int // A loop to build a slice of `int`’s from 0 size to 8 size // and print each index address for i:= 0; i < 8; i++{ lump … Read more
Instead of writing the following which id not valid Java, Paraula tipo1; tipo1 = { Paraula.lletres[0] = ‘t’; Paraula.lletres[1]=’1′; Paraula.llargaria = 2; perhaps you intended to write Paraula tipo1 = new Paraula(); tipo1.lletres[0] = ‘t’; tipo1.lletres[1]=’1′; tipo1.llargaria = 2; However a much cleaner way to do this is to pass a String to the constructor … Read more
Consider using get() to obtain environment variables from string values. Additionally, consider the nested lapply() between dataframe and model lists for more organized returned object. Nested for loops would require appending each iteration into growing list unless you just need to output. Below examples use linear models, lm(): model1 <- y ~ x1 model2 <- … Read more