[ad_1] You can parse your String as DateTime like var text = “24/02/2017 13:57:53”; var dateTime = DateTime.Parse(text); And then you can access the time like var time = dateTime.TimeOfDay; 0 [ad_2] solved How to get time only with date and time in C# [closed]
[ad_1] Copied from AWS user guide: Amazon Linux instances are set to the UTC (Coordinated Universal Time) time zone by default Furthermore: Network Time Protocol (NTP) is configured by default on Amazon Linux instances; however, an instance needs access to the Internet for the standard NTP configuration to work. In addition, your instance’s security group … Read more
[ad_1] The line: $this->display = ” $this->n”.”$this->suf”.” $this->name”; is the first line of the class’ constructor. It stores in the $display property of the object a string that contains only spaces because the values it contains are not set yet. Read about double-quotes strings and variables parsing inside double-quotes strings. In order to work, the … Read more
[ad_1] Try this code, final Handler h = new Handler(); h.post(new Runnable() { @Override public void run() { long millis = (long) currentTime(); dateAndTime.setText(getDate(millis, “dd/MM/yyyy hh:mm:ss.SSS”)); h.postDelayed(this, 1000); } }); 4 [ad_2] solved android update textview for every 30 seconds [duplicate]
[ad_1] Simply by using string date = DateTime.Now.ToString(“yyyy.MM.dd”); See this documentation for more info on custom date and time formats. 0 [ad_2] solved How can we obtain date time format in yyyy.MM.dd [duplicate]
[ad_1] Try this method: public static long getDateDiff(long timeUpdate, long timeNow, TimeUnit timeUnit) { long diffInMillies = Math.abs(timeNow – timeUpdate); return timeUnit.convert(diffInMillies, TimeUnit.MILLISECONDS); } It gives you the difference of whatever unit (days, years, …). long timestamp1 = 1500462813000; long timestamp2 = System.currentTimeMillis(); long diffInDays = getDateDiff(timestamp1, timestamp2, TimeUnit.DAYS); 2 [ad_2] solved Find difference between … Read more
[ad_1] Now I found the fastest solution is assembly. Just like this: __asm__ volatile( “0: \n” “# load 3 64-bit regs with interleave: \n” “vld3.8 {d0,d1,d2}, [%0]! \n” “# swap d0 and d2 – R and B\n” “vswp d0, d2 \n” “# store 4 64-bit regs: \n” “vst4.8 {d0,d1,d2,d3}, [%2]! \n” “subs %1, %1, #1 … Read more
[ad_1] This should do what you need: if (($time1-$time2) == 86400) { // Exactly 24 hours have passed. } 3 [ad_2] solved Comparing timestamps in PHP
[ad_1] It may be a problem with scope (what’s declared inside the brackets may not be available after the brackets close). Not sure what Java is doing. if (totalSeconds >= 60) { int intMinutesFromSeconds = (int) minutesFromSeconds; } int totalMinutes = intMinutesFromSeconds + … You can fix it with something like: int intMinutesFromSeconds = 0; … Read more
[ad_1] You will need a helper column with this formula: =24*(SUMPRODUCT((TEXT(ROW(INDEX(AAA:AAA,$F$1):INDEX(AAA:AAA,$F$2)),”dddd”)=A1)*(C1-B1))-IF(TEXT($F$1,”dddd”)=A1,MOD($F$1,1)-B1,0)-IF(TEXT($F$2,”dddd”)=A1,C1-MOD($F$2,1),0)) Then sum that column. Here it is in one formula using NETWORKDAYS.INTL =IF(DATEDIF(F1,F2,”d”)>1,NETWORKDAYS.INTL(F1+1,F2-1,”0000011″)*12+NETWORKDAYS.INTL(F1+1,F2-1,”1111101″)*4,0)+IF(DATEDIF(F1,F2,”d”)>0,(MOD(F2,1)-IF(WEEKDAY(F2,2)<6,TIME(7,0,0),TIME(9,0,0)))*24+(IF(WEEKDAY(F1,2)<6,TIME(19,0,0),TIME(13,0,0))-MOD(F1,1))*24,(F2-F1)*24) 4 [ad_2] solved how to calculate time difference in excel working hours only
[ad_1] strtotime can parse a “period” format like that natively, the only key point is to also pass in 0 as the second parameter so that the result is relative to the unix epoch rather than the current time: $seconds = strtotime(‘7 days 18:50:19’, 0); echo $seconds; 672619 0 [ad_2] solved PHP time period “7 … Read more
[ad_1] may this will help you…. #include<iostream> using namespace std; int main() { system(“TITLE how old are you?”); system(“color f3”); int yearnow,yearthen,monthnow,monththen,age1,age2; cout<<“\t\t\tEnter the current year and month \n\t\t\t(eg. 1997, enter, 7, enter):\n “; cin>>yearnow; cin>>monthnow; cout<<“Enter your birthyear and month: \n”; cin>>yearthen; cin>>monththen; if(monththen >12 || monththen<1) return 1; if(monththen > monthnow){ age1=yearnow-yearthen-1; age2=(12-monththen) … Read more
[ad_1] You have cout << “Your elapsed time is ” << elapsedtime <<endl; Did you mean cout << “Your elapsed time is ” << elapsedtime(time1, time2) <<endl; Update For some reason, cout << “Your elapsed time is ” << elapsedtime <<endl; does not produce a compiler error under g++ 4.7.3 even though the intent is … Read more
[ad_1] Use explode() to separate the hour / minute pieces, then do the math yourself: list( $hour, $min) = explode( ‘:’, “192:40”); list( $hour_sub, $min_sub) = explode( ‘:’, “02:30”); $result = ($hour – $hour_sub) . ‘:’ . ($min – $min_sub); echo $result; This will print: 190:10 If the time were to wrap around, ($min – … Read more
[ad_1] Something like this DateFormat sdf = new SimpleDateFormat(“hh:mm”); Date date = sdf.parse(time); 2 [ad_2] solved Convert only time part in android from string to time