[ad_1] There are many prblems in your code. To name a few: scanf(“%c”,&choice1); will consider the enter key press. case 5 float price(); –> not correct. if(decision1 == ‘y’){ main(); }–> use a flag and do..while() etc. etc. Also, it is not a very good practive to put everything inside main. To clean up the … Read more
[ad_1] Of course you can. “Hex Values” is merely a notation for an integral type, which is a valid case label in a C# switch block. Excepting the follow-through nature of a switch block – which you are obviating with break statements – the order of the case labels does not matter. [ad_2] solved switch … Read more
[ad_1] The switch statement jumps to the case that matches, and continues processing from there until it sees a break. Since there are no breaks in that code, it starts at case 1, outputs 1, and then continues with case 2 and outputs 2. Although it’s rare, sometimes this “fall through to the next case” … Read more
[ad_1] You switch it (see what I did there?) by writing something like this: switch(room.toUpperCase()) { case “P”: //do stuff for P break; case “S”: //do stuff for S break; ….. default: //do what’s in your “else” block break; } The switch statement decides which item to look at, then each case is for each … Read more
[ad_1] Try out this : package com.sujit; import java.util.Scanner; public class UserInput { public static void main(String[] args) { Scanner input = new Scanner(System.in); boolean flag = true; do { System.out.println(“Enter 1st number”); int num1 = input.nextInt(); System.out.println(“Enter 2nd number”); int num2 = input.nextInt(); System.out.println(“select one operator :\n 1)+\n2)-\n3)*\n4)/\n5)Exit(Enter E)\n”); System.out.println(“Enter your choice :”); char … Read more
[ad_1] Just replace your object with an enum, that’s what they’re for: export enum APP_STATUS { CONFIRMED, INCONSISTENCIES, SUCCESS, ERROR, LOADING, OK, } export interface Inconsistency {}; export interface InconsistenciesLoading { type: APP_STATUS.LOADING; } export interface InconsistenciesError { type: APP_STATUS.ERROR; } export interface InconsistenciesSuccess { type: APP_STATUS.SUCCESS; } export interface InconsistenciesData { type: APP_STATUS.INCONSISTENCIES; data: … Read more
[ad_1] Edit: Okay! A switch! Let’s do it! var count = 0; for(var i = number.length; i–;){ switch(true){ case typeof number[i] == ‘number’: count++; } } alert(count); 8 [ad_2] solved Using a Javascript switch statement, how can I count the number of elements (numbers only) in an array? [closed]
[ad_1] You cannot compare strings using = (or even by ==, for that matter) operator. You need to use strcmp() for that. In your code, inside mobileno() function, if( s=”katrina” ) is essentially trying to assign the base address of the string literal “katrina” to s. It is nowhere near a comparison. That said, Never … Read more
[ad_1] Your question is probably a duplicate of something else, but the reason is that case statement within a Java switch by default will flow onto the next case statement unless a break be explicitly mentioned. To better understand why the case statements behave this way, an example would make this clear. Let’s say that … Read more
[ad_1] A switch statement is meant to be used in place of if else statements For example int a =4; if(a == 1) doSomething(); else if(a == 2) doSomethingElse(); else if(a == 3) BLAH(); else CaseUnaccountedFor(); Is equivalent to int a =4; switch(a) { case 1: doSomething(); break; case 2: doSomethingElse(); break; case 3: BLAH(); … Read more
[ad_1] Yes the dictionary will be re-created if you leave and then re-enter that scope, for example def switch(a): responses = {1: ‘a’, 2: ‘b’, 3: ‘c’} print(id(responses)) return responses[a] Notice that the id of responses keeps changing which illustrates that a new object has been created each time >>> switch(1) 56143240 ‘a’ >>> switch(2) … Read more
[ad_1] The reason you are getting the error is that some execution paths in your code do not set a value to hours. It is difficult to see this problem because you are mixing input validation with result calculation logic. You could just initialize hours to 0, but I suspect that your program still won’t … Read more
[ad_1] int operation(int op, int n1, int n2) { switch( op ) { case 1: return subtraction(n1, n2); case 2: return multiplication(n1, n2); default: // default case, when the op value is neither 1 or 2 cout << “Error! << endl; return 0; } } @Edit: Added default case as suggested below. Also, I think … Read more
[ad_1] I found the answer to my question. Field field = this.getClass().getDeclaredField(nameOfField); return (Double) field.get(this); [ad_2] solved Is there a shorter way to write this code, without repeating three times switch?
[ad_1] In C++ this code is ill-formed because you cannot jump into the scope of a variable. In C the code is undefined behaviour: int i; inside the switch block exists, however by jumping to case 1: you bypassed the part where the value 2 would have been assigned to i. So in fact you … Read more