You’re missing crucial break statements in your switch, e.g. switch(rank) { case 14: { if(suite == ‘H’) printf(“Your card is the Ace of Hearts!”); else if(suite == ‘C’) printf(“Your card is the Ace of Clubs!”); else if(suite == ‘D’) printf(“Your card is the Ace of Diamonds!”); else printf(“Your card is the Ace of Spades!”); } … Read more
condition should be incrementing by 10: for (int x = 10; x <= 20; x=x+10) solved Unexpected behavior of a switch statement in a for loop [closed]
I am not sure that I get it correctly, but you may try Random rnd = new Random(); int caseSwitch = rnd.Next(1, 13); 2 solved C# Switch Randomized [closed]
No, you cannot. Functions cannot be generally declared inside another function. You can only define them. The language was designed like that. Also see these: Function Declaration and Function Prototypes C – Functions Declaring a function – function prototypes I think you need a good C book or tutorial. You can choose a good book … Read more
The are two errors (compile time errors, at least). First of all, cin, cout and endl are not known, you have to write them as std::cin, std::cout and std::endl. The second problem is here: switch (choice); Remove that semicolon and it’s fine. The reson why it’s not working with the semicolon is because then switch … Read more
If you have switch cases that are the same, you can combine them by omitting the return and break lines of the earlier cases. In the following, 3, 4, 5 and 6 all take the return value of case 7 (true): switch($role) { case 3: case 4: case 5: case 6: case 7: return true; … Read more