Keep track of the number of bytes you’re writing, and when it reaches a specified point, close the existing file and continue in a new one. There’s no need to analyze the size of the file, since you know exactly what’s going into it. Something like this: long fileSizeByteLimit = 5000000; long bytesOutput = 0; … Read more
When you do cin >> divers; the end-of-line character is not removed from the input, just the number leading up to it. Then, the next time you ask for a line with std::getline() it returns just the end-of-line character that is already there and does not wait for your new input. So when you do … Read more
A first step will be to convert the time in HH:MM:SS format (which is how your string is formatted) to that of seconds as per the following: String timerStop1 = String.format(“%02d”, hours) + “:” + String.format(“%02d”, minutes) + “:” + String.format(“%02d”, seconds); String[] timef=timerStop1.split(“:”); int hour=Integer.parseInt(timef[0]); int minute=Integer.parseInt(timef[1]); int second=Integer.parseInt(timef[2]); int temp; temp = second … Read more
it may not be possible by str_split as ‘again’ has 5 characters. you can get ‘from’, ‘here’ by following code. $txt = “lookSTARTfromhereSTARTagainhere”; $txt = str_replace(‘look’,”,$txt); $txt = str_replace(‘START’,”,$txt); $disp = str_split($txt, 4); for ($b = 0; $b<3; $b++) { echo “$disp[$b]”; } solved How do i start text str_split after some characters
Parenthesis in regular expressions are used to indicate groups. If you want to match them literally, you must ‘escape’ them: import re found = re.findall(r’\(.*?\)’, text) print(found) Outputs: [‘(not all)’, ‘(They will cry “heresy” and other accusations of “perverting” the doctrines of the Bible, while they themselves believe in a myriad of interpretations, as found … Read more
You can use strconv from the strconv package package main import ( “fmt” “strconv” ) func main() { a := 4 b := 3 c := “1” fmt.Println(c + strconv.Itoa(a) + strconv.Itoa(b)) } Or you can use Sprintf from the fmt package: package main import ( “fmt” ) func main() { a := 4 b … Read more
I suggest you use explicit formats in your case, you can do that by using ParseExact to get the DateTime object and then providing the desired format to the ToString overload: string date = “15/01/2017”; DateTime date1 = DateTime.ParseExact(date, “dd/MM/yyyy”, CultureInfo.CurrentCulture); btnBack.Text = date1.ToString(“MM-dd-yyyy”); solved How to convert dd/MM/yyyy string to MM-dd-YYYY DateTime int C#
The following list comprehension using itertools.groupby and str.join will work: from itertools import groupby s = “aaaabbcccdd” [”.join(g) for _, g in groupby(s)] # [“aaaa”, “bb”, “ccc”, “dd”] 1 solved How to split string into substrings of identical letters?
The displayInOrder() function is expecting a pointer to an the whole array. Instead, you passed a pointer to cities[5]. This has two problems: It’s a pointer to a specific element, not the whole array. The last element of the array is cities[4], so you’re accessing outside the array bounds. You should call the function this … Read more
This should help: var myRegex = new Regex(@”((\d){3}-1234567)|((\d){3}\-(\d){3}\-4567)|((\d){3}1234567)”); string newStringWithoutPhoneNumbers = myRegex.Replace(“oldStringWithPhoneNumbers”, string.Empty); 1 solved C# Remove Phone Number from String? [closed]
You can just use s2.Substring(7); And it will take a substring starting from 7 index including 7th char. Retrieves a substring from this instance. The substring starts at a specified character position and continues to the end of the string. https://msdn.microsoft.com/en-us/library/hxthx5h6(v=vs.110).aspx 1 solved Get from 8th string character to last string character
I believe I have found a solution. Not sure if it is the best way, but I am using regex to extract what need string pattern = @”[0-9][0-9 /.,]+[a-zA-Z ]+”; string input = line; var result = new List<string>(); foreach (Match m in Regex.Matches(input, pattern)) result.Add(m.Value.Trim()); return result; This piece of code returns what I … Read more
The std::setw() I/O manipulator is the direct equivalent of printf()‘s minimum width for strings, and the std::left and std::right I/O manipulators are the direct equivalent for justification within the output width. But there is no direct equivilent of printf()‘s precision (max length) for strings, you have to truncate the string data manually. Try this: #include … Read more
How many objects are created ? // “xyz” is interned , JVM will create this object and keep it in String pool String x = “xyz”; // a new String object is created here , x still refers to “xyz” x.toUpperCase(); // since char literal `Y` is not present in String referenced by x , … Read more
What about to split the string and strip words punctuation, without forget the case? w in [ws.strip(‘,.?!’) for ws in p.split()] Maybe that way: def wordSearch(word, phrase): punctuation = ‘,.?!’ return word in [words.strip(punctuation) for words in phrase.split()] # Attention about punctuation (here ,.?!) and about split characters (here default space) Sample: >>> print(wordSearch(‘Sea’.lower(), ‘Do … Read more