DD is wrong. D is day of year. Sixth day of year is January 6. You should use dd. Docs: SimpleDateFormat 1 solved Why is SimpleDateFormat parsing Date with wrong Month and Day? [duplicate]
Try transaction[‘amount’] For example a = {“amount”=>”-50.01″, “currency”=>”CAD”} Then a[‘amount’] returns ‘-50.01’ 2 solved Negative string value in hash ruby [closed]
Unless your data size is small (< a few MB), you probably want something like Apache Lucene, which can be used to index and search large document sets, and can do fuzzy searches using Levenshtein distance and other algorithms for similarity matches. solved Is there a library in Java for SQL like string searches? [closed]
I don’t understand your problem: def get_dangerous_query(): # do some database access # For a demo, just return what we know the table contains return “SELECT * FROM TABLE WHERE COL1 = ‘%s’ and COL2 = ‘%s'” qry = get_dangerous_query() % (var1, var2) “”” vs ” only has an effect on string literals. Quotes are … Read more
String date = “13-08-2016”; String[] values = date.split(“-“); int day = Integer.parseInt(values[0]); int month = Integer.parseInt(values[1]); int year = Integer.parseInt(values[2]); You can use String.split(String regex) method to parse the date to array of String then convert each value to int. JavaDoc: public String[] split(String regex) Splits this string around matches of the given regular expression. … Read more
Tom, The problem is that one string is longer than the other one. import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner sc = new Scanner(System.in); String elso = sc.nextLine(); String masodik = sc.nextLine(); String longestString = elso; String shortestString = masodik; if (shortestString.length() > longestString.length()){ shortestString = elso; longestString = … Read more
I make a snippet for you, so you can start from here $str=”December 2012 Name: Jack Brown”; $ptr = “/^(?P<month>:Jan(?:uary)?|Feb(?:ruary)?|Dec(?:ember)?) (?P<year>:19[7-9]\d|2\d{3}) (Name:(?P<name>(.*)))/”; preg_match($ptr, $str, $data); echo ‘For ‘.trim($data[‘name’]).’ – ‘.$data[‘month’].’ ‘.$data[‘year’]; the result will be ‘For Jack Brown – December 2012’ this is a array Array ( [0] => December 2012 Name: Jack Brown [month] … Read more
You can try something with 2^N (N can takes as length ). Then convert 0-2^N to binary and use proper binary formating. The you can have what you looking for. First step- get 2^N double twosPow = Math.pow(2, occurrence); Now iterate from 0 up to twosPow. and convert number to binary Second step- how to … Read more
You can use the below regex to achieve your requirement: [ ](?=[^\)]*?(?:\(|$)) Explanation of the above regex: [ ] – Represents a space character. (?=[^\)]*?(?:\(|$)) – Represents a positive look-ahead asserting everything inside of (). (?:) – Represents a non-capturing group. | – Represents alternation. $ – Represents the end of the test String. You … Read more
I gave a unsatisfying answer, thanks to @OlegEstekhin for pointing that out. As noone else answered yet, and a solution is not a two-liner, here it goes. Make a wrapping InputStream that throws away escape sequences. I have used a PushbackInputStream, where a partial sequence skipped, may still be pushed back for reading first. Here … Read more
To extract characters from a string and to store them into a Character Array Simple Method (Using string indexing): #include<iostream> using namespace std; // Using the namespace std to use string. int main(int argc, char** argv) { string input; cout << “Enter a string: “; cin>>input; // To read the input from the user. int … Read more
I shouldn’t, but check this out: Matcher m = Pattern.compile(test.replace(“{“, “\\{(“).replace(“}”, “)\\}”)).matcher(test); m.find(); for (int i = 1; i <= m.groupCount(); i++) { System.out.println(m.group(i)); } Ideone Demo 1 solved Reading data within parenthesis
Lexing is not specific to C (in the sense that you’ll use similar techniques in other programming languages). You could do that with hand-written code (using finite automaton coding techniques). You could use a lexer generator like flex. You might even use regexprs, e.g. regex.h functions on POSIX systems. Parsing is also a well known … Read more
Array of char data type is called Sting. You can take a string’s input using scanf() and gets(). But if you use scanf(), the string will be input by pressing Space-bar or Enter. But if you use gets(), input will be given only by pressing the Enter key. Example 1: char s[100]; scanf(“%s”, s); Example … Read more
Alamofire.request works asynchronously. A function / method which includes an asynchronous call can never have a return value. You need a callback for example func getUsuarios(completion : ([String]) -> Void) { var usuariosDataBase = [String]() Alamofire.request(.GET, url) .responseJSON { response in print(response) do { let json = try NSJSONSerialization.JSONObjectWithData(response.data!, options: .AllowFragments) if let blogs = … Read more