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[Solved] User input integer list [duplicate]

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Your best way of doing this, is probably going to be a list comprehension. user_input = raw_input(“Please enter five numbers separated by a single space only: “) input_numbers = [int(i) for i in user_input.split(‘ ‘) if i.isdigit()] This will split the user’s input at the spaces, and create an integer list. 1 solved User input … Read more

[Solved] How to replace a substring with ( from a string

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This regex String a = “Want to Start (A) Programming and (B) Designing”; String b = a.replaceAll(“\\(“, “\n\\(“); System.out.println(b); results in Want to Start (A) Programming and (B) Designing Just escape the brackets with \\ and you’re fine. Edit: more specific, like mentioned below a.replaceAll(“(\\([AB]\\))”, “\n$1”); to match only (A) and (B) or a.replaceAll(“(\\(\\w\\))”, “\n$1”); … Read more

[Solved] How to read a string from user with spaces

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Just use this. BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); String line; while((line = br.readLine())!=null){ // you can stop taking input when input line is empty if(line.isEmpty()){ break; } System.out.println(line); // printing the input line } br.close(); See live demo 4 solved How to read a string from user with spaces

[Solved] Looping a string split from an array [closed]

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Change your code to this: String[][] content_split = new String[string_array.length][]; // create 2d array for (int i=0; i<string_array.length; i++){ content_split[i] = string_array[i].split(” : “); // store into array and split by different criteria } Which leaves you with a 2D array of your split content. solved Looping a string split from an array [closed]

[Solved] How to convert String into String Array in Java? [duplicate]

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Split on “,”. String st = “Tokyo, New York, Amsterdam” String[] arr = st.split(“,”); If st has ‘{‘ and ‘}’. You might want to do something along the lines of… st = st.replace(“{“,””).replace(“}”,””); to get rid of the ‘{‘ and ‘}’. 1 solved How to convert String into String Array in Java? [duplicate]

[Solved] Extract numbers, letters, or punctuation from left side of string column in Python

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Use Series.str.extract with DataFrame.pop for extract column: pat = r'([\x00-\x7F]+)([\u4e00-\u9fff]+.*$)’ df[[‘office_name’,’company_info’]] = df.pop(‘company_info’).str.extract(pat) print (df) id office_name company_info 0 1 05B01 北京企商联登记注册代理事务所(通合伙) 1 2 Unit-D 608 华夏启商(北京企业管理有限公司) 2 3 1004-1005 北京中睿智诚商业管理有限公司 3 4 17/F(1706) 北京美泰德商务咨询有限公司 4 5 A2006~A2007 北京新曙光会计服务有限公司 5 6 2906-10 中国建筑与室内设计师网 11 solved Extract numbers, letters, or punctuation from left side of string … Read more

[Solved] How to save ” in a string in C++?

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You will need to escape the quotation mark you require in the string; std::string str(“Q850?51’18.23\””); // ^ escape the quote here The cppreference site has a list of these escape sequences. Alternatively you are use a raw string literal; std::string str = R”(Q850?51’18.23″)”; The second part of the problem is dependent on the format and … Read more

[Solved] Java else if with strings not working – Scanner(System.in); [duplicate]

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What you are missing is not checking the input value. First check the input value…: System.out.println(input); …and see if the value is ok. Then you can say if your “if-else” component is working or not. Also delete the gap @ input.equals (“Hola”). it must be input.equals(“Hola”) Addition: You cannot use == operator for Strings in … Read more

[Solved] Finding and counting the frequency of known pairs of words in multiple files [closed]

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When using combinations() you are getting all pairs, even the non-adjacent ones. You can create a function that will return the adjacent pairs. I’ve tried the following code and it worked, maybe it can give you some insight: import os import re from collections import Counter def pairs(text): ans = re.findall(r'[A-Za-z]+’, text) return (tuple(ans[i:i+2]) for … Read more