ruby

[Solved] How do I fix Rails RuntimeError Current ExectJ doesn’t support ES5?

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The main problem was in your Gemfile here gem ‘therubyracer’, platforms: :ruby gem ‘mini_racer’, platforms: :ruby You had two racer type gems, you only need one. You should just use gem ‘mini_racer’ and get rid of therubyracer. Do that and run bundle install. You will also need to clean up merge conflict stuff left in … Read more

[Solved] Global variables, member variables and instance variables in Python [closed]

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You have asked a lot of questions under one! I will try to answer each of those 🙂 Variables – global vs local global variables are those ones whose scope is global, i.e. available in entire program. local variables by contrast are those ones which resides in one particular scope, a function, inside a loop, … Read more

[Solved] Sort (hex) colors by Hue [closed]

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In this updated example also we don’t care about hash, we’ll just deal with an arrays of hex colors: require ‘paint’ #intantiate web_colors from gist and shuffle them eval(`curl https://gist.githubusercontent.com/lacostenycoder/394341d3c63589a050d72b8d9ae529aa/raw/4a11cd6ca81e07a643e5f3481e38494ff3c9b973/web_colors_shuffle.rb`) def hex_to_rgb(hex) h = hex.gsub(“#”,””) /(?<r>..)(?<g>..)(?<b>..)/ =~ h [r,g,b].map {|cs| cs.to_i(16)} end def rgb_to_hsl(r,g,b, by_hue=false) # normalize r, g and b r /= 255.0 g … Read more

[Solved] How does the === work in ruby? [duplicate]

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Because String === ‘a’ is the same as String.===(‘a’), which calls Class#===, inherited from Module#=== to test whether the parameter inherits from the receiver module; and ‘a’ === String is the same as ‘a’.===(String), which calls String#===, inherited from Object#=== to test whether the parameter is equal to the receiver object. In other words, === … Read more

[Solved] Calling #[] on a ruby method [closed]

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If I understand the question, you want a method that takes any number of arguments, and returns an object that will create a range of numbers when the [] method is used. This method takes any number of arguments (using the * splat operator), and then returns a proc, which [] can be used on. … Read more

[Solved] Format a string containing Phone numbers

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This will take care of 0‘s in between the phone numbers phone=”08763843478,+918763843478,08763843478,+918763843478,+918763840008″ phone.split(‘,’).map{|num| num.gsub(/^\+91|^0/, ”)}.join(‘,’) #=> “8763843478,8763843478,8763843478,8763843478,8763840008” 0 solved Format a string containing Phone numbers

[Solved] a href not working with a bare web page

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Apparently the answer was here: How to setup URLs for static site with Ruby Rack on Heroku Individual pages were being routed to “https://stackoverflow.com/” all the time. Needed to modify “config.ru” to get routing to work properly. Next step is to look into “sinatra”. solved a href not working with a bare web page

[Solved] How to get value from another ruby script

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If all files are written in Ruby, you can probably require your test case from your test suite (or vice versa) and call the appropriate methods. However, let’s assume that your test cases are arbitrary executables: In my test case script, I have a value which is set true/false (pass/fail) as per the test result. … Read more

[Solved] Javascript can implement OOP but Ruby can’t implement functional programming? [closed]

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Ruby does have first class functions. What makes you think it doesn’t? From wikipedia: A language that has first-class functions is one where: The language supports constructing new functions during the execution of a program, storing them in data structures, passing them as arguments to other functions, and returning them as the values of other … Read more

[Solved] Splitting array and get desired elements [closed]

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This should also works… array=[“1″,”2″,”3,a”,”4,b”] for i in 0..array.length()-1 if array[i].include?(“,”) ab=array[i].split(“,”) array[i]=ab[0] end end print array #[“1″,”2″,”3″,”4”] 1 solved Splitting array and get desired elements [closed]

[Solved] Sorting program in ruby [closed]

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if unsorted[0] <<== unsorted[1] then numsmall = unsorted[a] ^ (eval):51: syntax error, unexpected kTHEN, expecting kEND That little ^ points to first problem here. <<== is not a legal operator in ruby, hence the syntax error. Perhaps you mean “less than or equal to” which is <=? if unsorted[a] <= unsorted[b] Also, indentation will help … Read more