Use String.split: String[] kvPairs = “key1=value1;key2=value2;key3=value3”.split(“;”); This will give you an array kvPairs that contains these elements: key1=value1 key2=value2 key3=value3 Iterate over these and split them, too: for(String kvPair: kvPairs) { String[] kv = kvPair.split(“=”); String key = kv[0]; String value = kv[1]; // Now do with key whatever you want with key and value… … Read more
Use this regex it will work var regex = /^\d{5}\.\d{2}$/; var num = ‘23445.09’; console.log(regex.test(num)); // True var num2 = ‘12345.6’ console.log(regex.test(num)); // False Demo : https://jsbin.com/wasefa/edit?html,js,console,output 5 solved Javascript Regex for decimal [duplicate]
The regular expression that will match one or more numerals in succession is: \d+ You could apply it this way: Regex.Matches(myString, @”\d+”) Which will return a collection of MatchCollection object. This will contain the matched values. You could use it like so: var matches = Regex.Matches(myString, @”\d+”); if (matches.Count == 0) return null; var nums … Read more
The “basic” regex matching just the year field is \d{4} but it is not enough. We must prohibit that before the year occurs: 3 letters (month) and a space, then 2 digits (day) and a space. This can be achieved with negative lookbehind: (?<!\w{3} \d{2} ) But note that: after the day field there can … Read more
PHP validating and filtering a list of international numbers so im left only with valid cellphone numbers from that country [closed] solved PHP validating and filtering a list of international numbers so im left only with valid cellphone numbers from that country [closed]
You could try the below pattern to match XXXX.XXXX.XXXX, \b[a-z0-9]{4}(?:\.[a-z0-9]{4}){2}\b I assumed that the Hardware address must contains lowercase letters and numbers. 0 solved Regex pattern for parsing this test file?
Something like this (assuming your data is named df) # get the column names that follow this pattern cols = grepl(“[0-9]+_parameter”, names(df)) # see if any of those columns have a 97 any(df[cols] == 97) A base R way to filter for rows that have a 97 in any of those columns is this: df[rowSums(df[cols] … Read more
If I get your question right you want the pattern only on lines which have RED. If that’s the case then you can use the below (L\d+).* RED Demo 1 solved Extract value from string with regex [closed]
The regular expression [abc]? matches zero or one character that can be either a, b, or c. Thus it does not match abc. Positive matches would be the empty string, a, b, or c. On the other hand [abc]+ matches one or more characters that can be either a, b, or c. Therefore, it can … Read more
For this you don’t even need regex. Just split the String and call the right indices: String latLongString = “Tracking info Latitude: 3.9574667 Longitude: 7.44882167″; //yours obviously won’t be hardcoded String[] split = latLongString.split(” “); String lat = split[3]; String lon = split[5]; solved Extracting two numbers from a string using java
You can use this: ([^\/]+)(?=”$) It will match anything after the last slash up to a quotation mark at the end of the line “$ (without including it in the match). Demo: https://regex101.com/r/mY9nI1/1 4 solved Regex match between two characters
“(\-)(.*)” is the pattern, which will give you 2 matches if the string contains them. solved Regular Expression to match first character and after a character [closed]
This is one way to do it: import re x = “‘(‘2275.1’, ‘1950.4’)'” y = re.findall(r’\d+\.\d’, x) for i in y: print i Output: 2275.1 1950.4 solved Removing parentheses and comma
Have a look on the option “-o” (–only-matching) of grep command. By default grep keep lines that match the given pattern. With the option ‘-o’, grep will keep only the part of the line that match your url pattern 0 solved How to create list of jpg urls from file?
Give this a shot: (\b999\d), Your matches will be saved to the capture group. If you only want 999x, and not 999xx, this is going to work because of the , at the end. Test it out here -> https://regex101.com/r/yU2oN0/2 solved What would be the regular expression to match the specific pattern string. i.e : … Read more